EduFarming
Your list · 0हिं

Type at least two letters. Press Esc to close.

↑↓ navigate↵ openTAB cycle filter

Conditional Probability & Bayes' Theorem · Question 114 of 125

Question 114

HardOriginal question

Machines A, B and C make 50%, 30% and 20% of a factory's bolts, and 1%, 2% and 3% of their bolts are faulty. A bolt picked at random is faulty. What is the probability that machine C made it?

Options for question 114

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. P(C∣F)=0.2×0.030.017=0.0060.017P(C \mid F) = \frac{0.2 \times 0.03}{0.017} = \frac{0.006}{0.017}.

  2. =617= \frac{6}{17}.

Worth noting

15\frac{1}{5} is C's share of all bolts; among faulty bolts its share is larger, as its fault rate is highest.

Concept
Bayes' theorem
Typical time
120 s
Your time
—
The rule this testsBayes' theorem
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.