Three cards are drawn one after the other, without replacement, from a well-shuffled pack of 52. What is the probability that the three cards are of three different suits?

Explanation

1. 01

   The first card can be any card; the second must avoid its suit, $\frac{39}{51}$; the third must avoid both suits drawn, $\frac{26}{50}$.

2. 02

   $\frac{39}{51} \times \frac{26}{50} = \frac{13}{17} \times \frac{13}{25} = \frac{169}{425}$.