A die is thrown three times. What is the probability that a six turns up at least once?

\frac{1}{216}

Correct answerYour answer

\frac{91}{216}

Correct answerYour answer

\frac{1}{2}

Correct answerYour answer

\frac{125}{216}

Correct answerYour answer

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CorrectNot quiteAnswer B

Correct answer: B

The throws are independent, so no six in all three has probability $\left(\frac{5}{6}\right)^{3} = \frac{125}{216}$ .
$1 - \frac{125}{216} = \frac{91}{216}$ .

Worth noting

$\frac{1}{2} = 3 \times \frac{1}{6}$ adds the three chances, counting the throws with two or three sixes more than once.

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Explanation