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Continuity & Differentiability · Question 43 of 125

Question 43

MediumOriginal question

For which value of kk is f(x)={3ex+k,x≤0x+7,x>0f(x) = \begin{cases} 3e^{x} + k, & x \le 0 \\ x + 7, & x > 0 \end{cases} continuous at x=0x = 0?

Options for question 43

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. The pieces must meet at x=0x = 0: k+3=7k + 3 = 7.

  2. So k=4k = 4.

Worth noting

7 forgets that 3e0=33e^{0} = 3 is already on the left.

Concept
A constant that makes a function continuous
Typical time
90 s
Your time
—
The rule this testsChoosing a constant for continuity
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Ten questions from Continuity & Differentiability, at your own pace.

Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.