EduFarming
Your list · 0हिं

Type at least two letters. Press Esc to close.

↑↓ navigate↵ openTAB cycle filter

Continuity & Differentiability · Question 44 of 125

Question 44

MediumOriginal question

f(x)=tan⁡4xsin⁡2xf(x) = \frac{\tan 4x}{\sin 2x} for x≠0x \ne 0, and f(0)=kf(0) = k. For which kk is ff continuous at x=0x = 0?

Options for question 44

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. tan⁡4x≈4x\tan 4x \approx 4x and sin⁡2x≈2x\sin 2x \approx 2x near 0.

  2. The limit is 42=2\frac{4}{2} = 2.

Worth noting

1 cancels tan⁡\tan against sin⁡\sin and ignores the 4 and the 2.

Concept
A constant from a limit
Typical time
90 s
Your time
—
The rule this testsChoosing a constant for continuity
Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.

Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.