For $f(x) = \lvert x - 2 \rvert + [x]$, what is $\lim_{h \to 0^{+}} f(2 - h)$?

Explanation

1. 01

   $\lim_{h \to 0^{+}} f(2 - h)$ is the left-hand limit at 2: $x = 2 - h$ is just below 2.

2. 02

   There $\lvert x - 2 \rvert = h \to 0$ and $[x] = 1$, so the limit is 1.