The figure shows the region bounded by y = 4 -…

The figure shows the region bounded by y = 4 - x^2, the x-axis and the lines x = -2 and x = 2.

Question 60

MediumOriginal question

The figure shows the region bounded by $y = 4 - x^{2}$ , the $x$ -axis and the lines $x = -2$ and $x = 2$ . What is its area?

$The graph of y = 4 - x^{2} with the region under it between x = -2 and x = 2 shaded, down to the x-axis.$

0

Correct answerYour answer

\frac{16}{3}

Correct answerYour answer

\frac{32}{3}

Correct answerYour answer

\frac{64}{3}

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

The curve stays above the $x$ -axis on $[-2, 2]$ , so the area is $\int_{-2}^{2} 4 - x^{2}\,dx$ .
That is $\frac{32}{3}$ square units.

Ten questions from Definite Integrals & Area, at your own pace.

Ten questions from Definite Integrals & Area, at your own pace.