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Derivatives & Second-Order Derivatives · Question 27 of 96

Question 27

HardOriginal question

What is ddx(sin⁡23x)\frac{d}{dx}\left(\sin^2 3x\right)?

Options for question 27

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Three layers: the square, then the sine, then 3x3x. Differentiate each and multiply.

  2. 2sin⁡3x⋅cos⁡3x⋅3=6sin⁡3xcos⁡3x=3sin⁡6x2\sin 3x \cdot \cos 3x \cdot 3 = 6\sin 3x\cos 3x = 3\sin 6x.

Worth noting

sin⁡6x\sin 6x is 2sin⁡3xcos⁡3x2\sin 3x\cos 3x: the factor 3 from the inner 3x3x is missing.

Concept
A chain of three functions
Typical time
120 s
Your time
—
The rule this testsThe rules of differentiation
Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.