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Derivatives & Second-Order Derivatives · Question 80 of 96

Question 80

HardOriginal question

If y=x2log⁡xy = x^{2} \log x, what is d2ydx2\frac{d^2y}{dx^2}?

Options for question 80

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. First derivative: dydx=x(2log⁡x+1)\frac{dy}{dx} = x \left(2 \log x + 1\right).

  2. Differentiate again: d2ydx2=2log⁡x+3\frac{d^2y}{dx^2} = 2 \log x + 3.

Worth noting

x(2log⁡x+1)x \left(2 \log x + 1\right) stops at the first derivative; d2ydx2\frac{d^2y}{dx^2} differentiates it once more.

Concept
Second derivative of a product
Typical time
120 s
Your time
—
The rule this testsSecond-order derivatives
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Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.