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Differential Equations · Question 5 of 67

Question 5

MediumOriginal question

What is the degree of d2ydx2+sin⁡(dydx)=0\frac{d^2y}{dx^2} + \sin\left(\frac{dy}{dx}\right) = 0?

Options for question 5

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. The degree is defined only when the equation is a polynomial in its derivatives.

  2. Here a derivative sits inside sin⁡\sin, which is not a polynomial, so the degree is not defined.

Worth noting

The order is still defined: it is 2, from the highest derivative.

Concept
When the degree is not defined
Typical time
90 s
Your time
—
The rule this testsOrder and degree
Practise this chapter →

Ten questions from Differential Equations, at your own pace.

Practise this chapter →

Ten questions from Differential Equations, at your own pace.