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Differential Equations · Question 6 of 67

Question 6

MediumOriginal question

What is the product of the order and the degree of (d3ydx3)2+(d2ydx2)3+dydx=0\left(\frac{d^3y}{dx^3}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^3 + \frac{dy}{dx} = 0?

Options for question 6

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. The highest derivative is d3ydx3\frac{d^3y}{dx^3}: the order is 3.

  2. Its power is 2, so the degree is 2 (the cube on d2ydx2\frac{d^2y}{dx^2} does not count), and the product is 6.

Worth noting

9 takes the degree as 3, the power on d2ydx2\frac{d^2y}{dx^2}, a lower derivative.

Concept
Order and degree together
Typical time
90 s
Your time
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The rule this testsOrder and degree
Practise this chapter →

Ten questions from Differential Equations, at your own pace.

Practise this chapter →

Ten questions from Differential Equations, at your own pace.