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Chain Rule, Log Differentiation & Rate of Change · Question 62 of 130

Question 62

MediumOriginal question

Assertion (A): ddxlog⁡∣x∣=1x\frac{d}{dx}\log \lvert x \rvert = \frac{1}{x} for every x≠0x \ne 0.

Reason (R): For x<0x < 0, log⁡∣x∣=log⁡(−x)\log \lvert x \rvert = \log(-x), whose derivative is −1−x=1x\frac{-1}{-x} = \frac{1}{x}.

Options for question 62

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. A is true: for x>0x > 0 it is 1x\frac{1}{x} directly.

  2. R is true and supplies the negative half, so it explains A.

Concept
The derivative of \(\log \lvert x \rvert\)
Typical time
90 s
Your time
—
The rule this testsExponential and logarithmic functions
Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.