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Chain Rule, Log Differentiation & Rate of Change · Question 69 of 130

How fast is the population growing at the moment it reaches 75,000?

Question 69

MediumOriginal question

A town's population tt years from now is modelled by P(t)=50,000 e0.02tP(t) = 50{,}000\,e^{0.02t}.

How fast is the population growing at the moment it reaches 75,000?

Options for question 69

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. P′(t)=0.02×50,000 e0.02t=0.02 P(t)P'(t) = 0.02 \times 50{,}000\,e^{0.02t} = 0.02\,P(t): the rate is 0.02 times the population.

  2. When P=75,000P = 75{,}000: 0.02×75,000=15000.02 \times 75{,}000 = 1500 people per year.

Worth noting

1,000 is the rate at t=0t = 0; the rate grows with the population, so it is not the same later.

Concept
A rate proportional to the amount present
Typical time
120 s
Your time
—
The rule this testsExponential and logarithmic functions
Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.