What is $\frac{d}{dx}\left(\log_{2}(3x + 1)\right)$ for $x > -\frac{1}{3}$?

Explanation

1. 01

   $\log_{2} u = \frac{\log u}{\log 2}$, and $\log 2$ is a constant.

2. 02

   $\frac{1}{\log 2} \cdot \frac{3}{3x + 1} = \frac{3}{(3x + 1)\log 2}$.