What is the value of $\cot^{-1}(-1) + \tan^{-1}(-1)$ ?

- \frac{\pi}{2}

Correct answerYour answer

0

Correct answerYour answer

\frac{\pi}{2}

Correct answerYour answer

\pi

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

Worth noting

0 takes $\cot^{-1}(-1)$ as $-\frac{\pi}{4}$ , off its branch $(0, \pi)$ .

Ten questions from Inverse Trigonometric Functions, at your own pace.

Ten questions from Inverse Trigonometric Functions, at your own pace.

What is the value of cot⁡−1(−1)+tan⁡−1(−1)\cot^{-1}(-1) + \tan^{-1}(-1)cot−1(−1)+tan−1(−1)?