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Random Variables, Expectation & Variance · Question 58 of 68

Question 58

MediumOriginal question

XX takes the values −1-1, 0 and 1 with probabilities 14\frac{1}{4}, 12\frac{1}{2} and 14\frac{1}{4}. What is the standard deviation of XX?

Options for question 58

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. E(X)=−14+0+14=0E(X) = -\frac{1}{4} + 0 + \frac{1}{4} = 0 and E(X2)=14+0+14=12E(X^{2}) = \frac{1}{4} + 0 + \frac{1}{4} = \frac{1}{2}.

  2. Var(X)=12\text{Var}(X) = \frac{1}{2}, so the standard deviation is 12=12\sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}}.

Worth noting

12\frac{1}{2} is the variance; the standard deviation is its square root.

Concept
The standard deviation
Typical time
90 s
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The rule this testsVariance and standard deviation
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Ten questions from Random Variables, Expectation & Variance, at your own pace.

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Ten questions from Random Variables, Expectation & Variance, at your own pace.