For which k are the lines (x - 1)/(-3) = (y - 2)/2k = (z - 3)/2 and (x - 1)/3k = (y - 1)/1 = (z - 6)/(-5) perpendicular?

Three-Dimensional Geometry · Question 80 of 120

Question 80

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For which $k$ are the lines $\frac{x - 1}{-3} = \frac{y - 2}{2k} = \frac{z - 3}{2}$ and $\frac{x - 1}{3k} = \frac{y - 1}{1} = \frac{z - 6}{-5}$ perpendicular?

- \frac{10}{7}

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- \frac{7}{10}

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\frac{7}{10}

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\frac{10}{7}

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CorrectNot quiteAnswer A

Correct answer: A

Worth noting

$\frac{10}{7}$ loses the sign when solving $-7k = 10$ .

Ten questions from Three-Dimensional Geometry, at your own pace.

Ten questions from Three-Dimensional Geometry, at your own pace.