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Three-Dimensional Geometry · Question 101 of 120

Question 101

MediumOriginal question

What is the perpendicular distance of the point (5,1,5)(5, 1, 5) from the line r⃗=(i^−j^)+λ(2i^−2j^+k^)\vec{r} = (\hat{i} - \hat{j}) + \lambda(2\hat{i} - 2\hat{j} + \hat{k})?

Options for question 101

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. p⃗−a⃗=4i^+2j^+5k^\vec{p} - \vec{a} = 4\hat{i} + 2\hat{j} + 5\hat{k} and b⃗×(p⃗−a⃗)=−12i^−6j^+12k^\vec{b} \times (\vec{p} - \vec{a}) = -12\hat{i} - 6\hat{j} + 12\hat{k}, of length 18.

  2. d=18∣b⃗∣=183=6d = \frac{18}{\lvert \vec{b} \rvert} = \frac{18}{3} = 6.

Worth noting

18 is ∣b⃗×(p⃗−a⃗)∣\lvert \vec{b} \times (\vec{p} - \vec{a}) \rvert before it is divided by ∣b⃗∣=3\lvert \vec{b} \rvert = 3.

Concept
The distance of a point from a line
Typical time
90 s
Your time
—
The rule this testsSkew lines and the shortest distance
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Ten questions from Three-Dimensional Geometry, at your own pace.

Practise this chapter →

Ten questions from Three-Dimensional Geometry, at your own pace.