For which k are the lines (x - 3)/2 = (y + 1)/k = z/(-1) and (x + 1)/3 = y/2 = (z - 2)/4 perpendicular?

Three-Dimensional Geometry · Question 68 of 120

Question 68

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For which $k$ are the lines $\frac{x - 3}{2} = \frac{y + 1}{k} = \frac{z}{-1}$ and $\frac{x + 1}{3} = \frac{y}{2} = \frac{z - 2}{4}$ perpendicular?

-5

Correct answerYour answer

-1

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1

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5

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Show the answer and explanation

CorrectNot quiteAnswer B

Correct answer: B

Worth noting

$-5$ takes $(-1)(4)$ as $+4$ .

Ten questions from Three-Dimensional Geometry, at your own pace.

Ten questions from Three-Dimensional Geometry, at your own pace.