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Three-Dimensional Geometry · Question 75 of 120

Question 75

MediumOriginal question

What is the angle between the lines with direction ratios a,b,ca, b, c and b−c,c−a,a−bb - c, c - a, a - b, where a,b,ca, b, c are not all equal?

Options for question 75

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. a(b−c)+b(c−a)+c(a−b)=ab−ac+bc−ab+ca−bc=0a(b - c) + b(c - a) + c(a - b) = ab - ac + bc - ab + ca - bc = 0.

  2. So cos⁡θ=0\cos \theta = 0 and θ=π2\theta = \frac{\pi}{2}, whatever a,b,ca, b, c are.

Worth noting

0 would need the two sets of ratios in proportion; their dot product is 0 instead.

Concept
Perpendicular lines
Typical time
90 s
Your time
—
The rule this testsThe angle between two lines
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Ten questions from Three-Dimensional Geometry, at your own pace.

Practise this chapter →

Ten questions from Three-Dimensional Geometry, at your own pace.