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Three-Dimensional Geometry · Question 109 of 120

Question 109

HardOriginal question

What is the distance between the parallel lines r⃗=λ(i^+2j^+2k^)\vec{r} = \lambda(\hat{i} + 2\hat{j} + 2\hat{k}) and r⃗=3i^+μ(i^+2j^+2k^)\vec{r} = 3\hat{i} + \mu(\hat{i} + 2\hat{j} + 2\hat{k})?

Options for question 109

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. b⃗×(a2⃗−a1⃗)=6j^−6k^\vec{b} \times (\vec{a_2} - \vec{a_1}) = 6\hat{j} - 6\hat{k}, of length 626\sqrt{2}; ∣b⃗∣=3\lvert \vec{b} \rvert = 3.

  2. d=623=22d = \frac{6\sqrt{2}}{3} = 2\sqrt{2}.

Worth noting

3 is the distance between the two given points, measured along the xx-axis, not across the lines.

Concept
The distance between parallel lines
Typical time
120 s
Your time
—
The rule this testsSkew lines and the shortest distance
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Ten questions from Three-Dimensional Geometry, at your own pace.

Practise this chapter →

Ten questions from Three-Dimensional Geometry, at your own pace.