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Three-Dimensional Geometry · Question 51 of 120

For which λ is PM perpendicular to L?

Question 51

MediumOriginal question

A point P(5,1,4)P(5, 1, 4) and the line L:x−12=y2=z−3−1L: \frac{x - 1}{2} = \frac{y}{2} = \frac{z - 3}{-1} are given. MM is the point of LL with parameter λ\lambda, and FF is the foot of the perpendicular from PP to LL.

For which λ\lambda is PMPM perpendicular to LL?

Options for question 51

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. PMPM has direction ratios 2λ−4,2λ−1,−1−λ2\lambda - 4, 2\lambda - 1, -1 - \lambda, and it must be perpendicular to 2,2,−12, 2, -1.

  2. 2(2λ−4)+2(2λ−1)−(−1−λ)=9λ−9=02(2\lambda - 4) + 2(2\lambda - 1) - (-1 - \lambda) = 9\lambda - 9 = 0, so λ=1\lambda = 1.

Worth noting

9 is (p⃗−a⃗)⋅b⃗(\vec{p} - \vec{a}) \cdot \vec{b}, which still has to be divided by ∣b⃗∣2=9\lvert \vec{b} \rvert^{2} = 9.

Concept
The foot of the perpendicular from a point to a line
Typical time
120 s
Your time
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The rule this testsThe equation of a line
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Ten questions from Three-Dimensional Geometry, at your own pace.

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Ten questions from Three-Dimensional Geometry, at your own pace.