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Vectors · Question 71 of 125

Question 71

MediumOriginal question

∣a⃗∣=3\lvert \vec{a} \rvert = 3, ∣b⃗∣=4\lvert \vec{b} \rvert = 4 and a⃗⋅b⃗=6\vec{a} \cdot \vec{b} = 6. What is ∣a⃗+b⃗∣\lvert \vec{a} + \vec{b} \rvert?

Options for question 71

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. ∣a⃗+b⃗∣2=∣a⃗∣2+2a⃗⋅b⃗+∣b⃗∣2=9+12+16\lvert \vec{a} + \vec{b} \rvert^{2} = \lvert \vec{a} \rvert^{2} + 2\vec{a} \cdot \vec{b} + \lvert \vec{b} \rvert^{2} = 9 + 12 + 16.

  2. ∣a⃗+b⃗∣=37\lvert \vec{a} + \vec{b} \rvert = \sqrt{37}.

Worth noting

7 adds the magnitudes, which only works when the vectors point the same way.

Concept
Magnitudes from a scalar product
Typical time
90 s
Your time
—
The rule this testsThe scalar product
Practise this chapter →

Ten questions from Vectors, at your own pace.

Practise this chapter →

Ten questions from Vectors, at your own pace.