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Vectors · Question 62 of 125

Question 62

EasyOriginal question

Read the two statements and choose the correct option.

I. If a⃗⋅b⃗=0\vec{a} \cdot \vec{b} = 0 and neither vector is 0⃗\vec{0}, the vectors are perpendicular.

II. a⃗⋅b⃗=b⃗⋅a⃗\vec{a} \cdot \vec{b} = \vec{b} \cdot \vec{a}, and likewise a⃗×b⃗=b⃗×a⃗\vec{a} \times \vec{b} = \vec{b} \times \vec{a}.

Options for question 62

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. I: ∣a⃗∣∣b⃗∣cos⁡θ=0\lvert \vec{a} \rvert \lvert \vec{b} \rvert \cos \theta = 0 with both magnitudes non-zero forces cos⁡θ=0\cos \theta = 0. True.

  2. II: the scalar product commutes, but b⃗×a⃗=−a⃗×b⃗\vec{b} \times \vec{a} = -\vec{a} \times \vec{b}. False.

Concept
Properties of the two products
Typical time
60 s
Your time
—
The rule this testsThe scalar product
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Ten questions from Vectors, at your own pace.

Practise this chapter →

Ten questions from Vectors, at your own pace.