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Vectors · Question 95 of 125

Question 95

EasyOriginal question

What is (2i^−3k^)×j^(2\hat{i} - 3\hat{k}) \times \hat{j}?

Options for question 95

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. (2i^−3k^)×j^=2(i^×j^)−3(k^×j^)(2\hat{i} - 3\hat{k}) \times \hat{j} = 2(\hat{i} \times \hat{j}) - 3(\hat{k} \times \hat{j}).

  2. i^×j^=k^\hat{i} \times \hat{j} = \hat{k} and k^×j^=−i^\hat{k} \times \hat{j} = -\hat{i}, so it is 2k^+3i^=3i^+2k^2\hat{k} + 3\hat{i} = 3\hat{i} + 2\hat{k}.

Worth noting

−3i^−2k^-3\hat{i} - 2\hat{k} is j^×(2i^−3k^)\hat{j} \times (2\hat{i} - 3\hat{k}), the product in the other order.

Concept
Products of the unit vectors
Typical time
60 s
Your time
—
The rule this testsThe vector product
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Ten questions from Vectors, at your own pace.

Practise this chapter →

Ten questions from Vectors, at your own pace.