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Vectors · Question 109 of 125

Question 109

MediumOriginal question

∣a⃗∣=∣b⃗∣\lvert \vec{a} \rvert = \lvert \vec{b} \rvert, ∣a⃗×b⃗∣=12\lvert \vec{a} \times \vec{b} \rvert = 12 and a⃗⋅b⃗=5\vec{a} \cdot \vec{b} = 5. What is ∣a⃗∣\lvert \vec{a} \rvert?

Options for question 109

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. ∣a⃗×b⃗∣2+(a⃗⋅b⃗)2=∣a⃗∣2∣b⃗∣2=∣a⃗∣4\lvert \vec{a} \times \vec{b} \rvert^{2} + (\vec{a} \cdot \vec{b})^{2} = \lvert \vec{a} \rvert^{2}\lvert \vec{b} \rvert^{2} = \lvert \vec{a} \rvert^{4}.

  2. 144+25=169144 + 25 = 169, so ∣a⃗∣2=13\lvert \vec{a} \rvert^{2} = 13 and ∣a⃗∣=13\lvert \vec{a} \rvert = \sqrt{13}.

Worth noting

13 is ∣a⃗∣2\lvert \vec{a} \rvert^{2}: with equal magnitudes, 169 is the fourth power of ∣a⃗∣\lvert \vec{a} \rvert.

Concept
The two products together
Typical time
90 s
Your time
—
The rule this testsThe vector product
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Ten questions from Vectors, at your own pace.

Practise this chapter →

Ten questions from Vectors, at your own pace.