Triangle ABC is right-angled at C, with $AC = 6$ cm and $BC = 8$ cm. D is the midpoint of BC. What is the length of AD?

Explanation

1. 01

   $CD = 8 \div 2 = 4$ cm, and triangle ACD is right-angled at C.

2. 02

   $AD = \sqrt{6^2 + 4^2} = \sqrt{52} = 2\sqrt{13}$ cm (about 7.2 cm).