AB is a diameter of a circle and C is another point on the circle. If $\angle CAB = 34^\circ$, what is $\angle CBA$?

Explanation

1. 01

   The angle in a semicircle is a right angle, so $\angle ACB = 90^\circ$.

2. 02

   $\angle CBA = 180^\circ - 90^\circ - 34^\circ = 56^\circ$.