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Mensuration: Areas and Volumes · Question 17 of 68

Question 17

EasyOriginal question

A slice of a round cake is a sector of radius 21 cm with an angle of 60° at the centre. What is the area of the top of the slice? Take π=227\pi = \frac{22}{7}.

Options for question 17

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Sector area = θ360∘×πr2\frac{\theta}{360^\circ} \times \pi r^2.

  2. = 60360×227×21×21=16×1386=231\frac{60}{360} \times \frac{22}{7} \times 21 \times 21 = \frac{1}{6} \times 1386 = 231 cm².

Worth noting

462 cm² uses 120° in place of 60°, 693 cm² is a semicircle and 1,386 cm² is the whole cake. A 60° slice is one-sixth of it.

Concept
Area of a sector
Typical time
40 s
Your time
—
The rule this testsCircles, rings and sectors
Practise this chapter →

Ten questions from Mensuration: Areas and Volumes, at your own pace.

Practise this chapter →

Ten questions from Mensuration: Areas and Volumes, at your own pace.