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Time & Work · Question 60 of 61

Question 60

HardOriginal question

A pipe can fill a tank in 30 minutes. After it has been running for 10 minutes, a leak starts at the bottom, and because of it the tank fills 10 minutes later than it should have. How long would the leak alone take to empty the full tank?

Options for question 60

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. In the first 10 minutes the pipe fills 13\frac{1}{3} of the tank.

  2. The remaining 23\frac{2}{3} should take 20 minutes but takes 30, so the net rate is 23÷30=145\frac{2}{3} \div 30 = \frac{1}{45}.

  3. Leak = 130−145=3−290=190\frac{1}{30} - \frac{1}{45} = \frac{3-2}{90} = \frac{1}{90}, so it empties the tank in 90 minutes.

Worth noting

45 minutes is the time the pipe-with-leak would take for a full tank, not the leak alone. Measure the net rate only over the part when the leak is actually running.

Concept
Leak starting partway through filling
Typical time
120 s
Your time
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The rule this testsPipes and cisterns
Practise this chapter →

Ten questions from Time & Work, at your own pace.

Practise this chapter →

Ten questions from Time & Work, at your own pace.