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Time and Work for CUET General Aptitude

About 10 min to learn · 61 questions

Time and work questions come as painters, tailors, machines, taps and leaking tanks, but almost all of them run on one idea: turn every time into a rate, add or subtract the rates, then turn the answer back into a time. This lesson covers rates, working together, finding one worker's time, joining and leaving, alternate days, efficiency and the units method, the M₁D₁H₁ rule, sharing wages, and pipes and cisterns, with worked examples and traps.

Syllabus area
General Mental Ability, Numerical Ability
On this page · 9 sections
  1. 01The core idea
  2. 02Rates
  3. 03Changing teams
  4. 04Efficiency
  5. 05Pipes and cisterns
  6. 06Exam shortcuts
  7. 07Common mistakes
  8. 08Quick revision
  9. 09Check your understanding

The core idea

Times cannot be added; rates can. If a job takes 8 days, the worker does 18\tfrac{1}{8} of it each day, and that fraction is the only thing you ever add or subtract. Turn every time into a rate, combine the rates, then turn the answer back into a time.

The quickest way to keep the fractions tidy is the units method: take the whole job as the LCM of the given times, so that every rate becomes a whole number of units a day.

Rates

What does "work as a rate" mean in time and work problems?

It means measuring how much of the job someone finishes in one unit of time. A person who finishes a job in 8 days does 18\tfrac{1}{8} of it a day. The whole job counts as 1, or as a convenient number of units.

Rate, work and time

Rate=1time for the whole jobWork=rate×time\text{Rate} = \frac{1}{\text{time for the whole job}} \qquad \text{Work} = \text{rate} \times \text{time}

Exam shortcut

Turn a part-job into a full-job rate before combining it with anyone else. Someone who does 27\tfrac{2}{7} of a job in 6 days has a rate of 27÷6=121\tfrac{2}{7} \div 6 = \tfrac{1}{21}, so the whole job would take them 21 days.

How do you find the time when two people work together?

Add their rates and flip the result. If A takes aa days and B takes bb days, together they take aba+b\tfrac{ab}{a + b} days.

Example 1 · Working together

Harpreet can service a car in 9 hours and Dev in 18 hours. How long do they take together?

  1. Rates: 19\tfrac{1}{9} and 118\tfrac{1}{18}.

  2. Together: 218+118=318=16\tfrac{2}{18} + \tfrac{1}{18} = \tfrac{3}{18} = \tfrac{1}{6} an hour.

  3. Time: 6 hours. Shortcut: 9×1827=6\tfrac{9 \times 18}{27} = 6.

Answer

6 hours

Watch out

The together time must be less than the faster worker's time. An answer bigger than the quicker worker's time means days were added instead of rates. For three people, add three rates: 8, 12 and 24 days give 3+2+124=14\tfrac{3 + 2 + 1}{24} = \tfrac{1}{4}, so 4 days.

How do you find one person's time when you know the together time?

Subtract rates. If A and B together take tt days and A alone takes aa, B's rate is 1t−1a\tfrac{1}{t} - \tfrac{1}{a}.

Example 2 · One worker's time

Two cooks together prepare a wedding lunch in 10 hours. One of them alone would take 14 hours. How long would the other take?

  1. Other cook's rate: 110−114=7−570=135\tfrac{1}{10} - \tfrac{1}{14} = \tfrac{7 - 5}{70} = \tfrac{1}{35}.

  2. So the other cook needs 35 hours.

Answer

35 hours

Subtracting the times, 14−10=414 - 10 = 4, is the classic wrong answer, and it is always far too small.

Exam shortcut

Given all three pair times, A with B, B with C and C with A, add the three pair rates and halve, because everyone appears in two pairs. That gives all three together; subtract a pair to find the third person.

Changing teams

How do you solve questions where someone joins or leaves midway?

Split the job into phases. Work out what each phase does at its own rate, and let the last phase finish whatever is left.

Example 3 · A worker joins

Mehul can build a bookshelf in 15 days and Zoya in 10. Mehul works alone for 5 days, then Zoya joins him. How many more days to finish?

  1. Mehul's 5 days: 515=13\tfrac{5}{15} = \tfrac{1}{3} done, so 23\tfrac{2}{3} is left.

  2. Together: 115+110=230+330=16\tfrac{1}{15} + \tfrac{1}{10} = \tfrac{2}{30} + \tfrac{3}{30} = \tfrac{1}{6} a day.

  3. Time for 23\tfrac{2}{3}: 23÷16=4\tfrac{2}{3} \div \tfrac{1}{6} = 4 days.

Answer

4 more days

The whole job takes 9 days.

Watch out

"How many more days", "after how many days did she leave" and "in how many days was the job finished" are three different numbers, and all three are usually among the options. When someone stops kk days before the end, let the total be TT and write T−ka+Tb=1\tfrac{T - k}{a} + \tfrac{T}{b} = 1.

How do you handle people working on alternate days?

Treat one turn each as a cycle. Find what a cycle does, count whole cycles until you are close to the end, and finish the last scrap carefully; it may take only part of a day.

Example 4 · Alternate days

Pallavi can paint a room in 4 days and Tushar in 6. They paint on alternate days, Pallavi first. How long does the room take?

  1. One 2-day cycle: 14+16=512\tfrac{1}{4} + \tfrac{1}{6} = \tfrac{5}{12}.

  2. Two cycles, 4 days: 1012\tfrac{10}{12} done, 16\tfrac{1}{6} left.

  3. Day 5 is Pallavi's. At 14\tfrac{1}{4} a day, 16\tfrac{1}{6} takes 16÷14=23\tfrac{1}{6} \div \tfrac{1}{4} = \tfrac{2}{3} of a day.

Answer

4234\tfrac{2}{3} days

Watch out

Who starts matters: with Tushar first, the answer changes. And never just double the together time, because the job often ends part-way through a turn.

Efficiency

What is efficiency, and how does it relate to time?

Efficiency is the rate, work per day, and it is inversely proportional to time: twice as efficient means half as long. The ratio of efficiencies is the ratio of times flipped. The fastest method is to give the slower worker a convenient number of units a day.

Example 5 · The units method

Farida is 60% more efficient than Bhushan. Together they paint a hall in 13 days. How long would Farida take alone?

  1. Let Bhushan do 5 units a day. Farida does 60% more: 8 units a day.

  2. Together: 13 units a day, so the job is 13×13=16913 \times 13 = 169 units.

  3. Farida alone: 169÷8=2118169 \div 8 = 21\tfrac{1}{8} days.

Answer

211821\tfrac{1}{8} days

A is … more efficient than BA's time as a fraction of B's
25%45\tfrac{4}{5}
50%23\tfrac{2}{3}
100%, twice as efficient12\tfrac{1}{2}
200%, three times as efficient13\tfrac{1}{3}

Watch out

Percentage efficiency is not percentage time. If A is 25% more efficient than B and B takes 20 days, A takes 45\tfrac{4}{5} of 20, which is 16 days, only 20% less.

What is the M₁D₁H₁ = M₂D₂H₂ rule?

The total work, measured in person-hours, stays the same however it is split: workers times days times hours a day is equal on both sides. If the amount of work changes too, divide each side by its work.

Workers, days and hours

M1×D1×H1W1=M2×D2×H2W2\frac{M_1 \times D_1 \times H_1}{W_1} = \frac{M_2 \times D_2 \times H_2}{W_2}

Example 6 · More workers, more cable

14 workers, working 5 hours a day, lay 350 m of cable in 10 days. How many days will 20 workers, working 7 hours a day, take to lay 600 m?

  1. 14×10×5350=20×D×7600\tfrac{14 \times 10 \times 5}{350} = \tfrac{20 \times D \times 7}{600}.

  2. The left side is 700350=2\tfrac{700}{350} = 2, so 140D=1200140D = 1200.

  3. D=1200140=847D = \tfrac{1200}{140} = 8\tfrac{4}{7}.

Answer

8478\tfrac{4}{7} days

Exam shortcut

More workers or more hours mean fewer days; more work means more days. If your answer moves the wrong way, a factor is on the wrong side. When workers join partway, count worker-days: 25 workers for 36 days is 900 worker-days; after 12 days, 300 are done, and 40 workers finish the other 600 in 15 more days, 27 in all.

How are wages shared when people work together?

Wages are paid for work done, never for time spent or split equally. Each share is the fraction of the job that person did, times the total. With equal days, work done follows efficiency; with different days, it is efficiency times days.

Example 7 · Splitting the pay

Uma can stitch a set of costumes in 8 days and Vikram in 12. Uma works 2 days alone and Vikram finishes. The payment is ₹6,000. What does each get?

  1. Uma's 2 days: 28=14\tfrac{2}{8} = \tfrac{1}{4} of the job, so Vikram does 34\tfrac{3}{4}.

  2. Uma: 14×6,000=1,500\tfrac{1}{4} \times 6{,}000 = 1{,}500. Vikram: 34×6,000=4,500\tfrac{3}{4} \times 6{,}000 = 4{,}500.

Answer

Uma ₹1,500, Vikram ₹4,500

The efficiency ratio 3:23 : 2 would be wrong, because they did not work for the same time.

Pipes and cisterns

How do pipes and cisterns questions work?

They are time and work questions in which the workers are pipes. An inlet has a positive rate and an outlet or leak a negative one. Add the inlets, subtract the outlets, and flip.

Example 8 · Inlet and outlet

A tank has an inlet that fills it in 6 hours and an outlet that empties it in 10 hours. Both are opened on an empty tank. How long does it take to fill?

  1. Net rate: 16−110=5−330=115\tfrac{1}{6} - \tfrac{1}{10} = \tfrac{5 - 3}{30} = \tfrac{1}{15} an hour.

  2. The tank fills in 15 hours.

Answer

15 hours

Exam shortcut

  • A leak: a pipe that should fill a tank in 4 hours but takes 5 has a leak of 14−15=120\tfrac{1}{4} - \tfrac{1}{5} = \tfrac{1}{20}, so the leak alone empties it in 20 hours.
  • A tank that starts half full needs only half the net time.
  • With flows in litres a minute, work in litres: time = litres needed ÷ net flow.
  • Pipes opened or closed at different times are workers joining or leaving: go phase by phase.

Exam shortcuts

  • LCM units. For 12, 15 and 20 days take 60 units: rates 5, 4 and 3 a day.
  • Two workers. aba+b\tfrac{ab}{a + b}.
  • Three pairs. Add and halve.
  • Efficiency. Time is the efficiency ratio flipped.
  • Sense check. Together is faster than the fastest worker.

Common mistakes

  • Adding days instead of rates. 10 and 15 days together is 6 days, not 25 or 12.5.
  • Subtracting days to find one person.
  • Answering the wrong question. More days, total days, or when someone left.
  • Forgetting the part already done.
  • Doubling the together time for alternate days.
  • Forgetting to halve the pair total.
  • Percentage efficiency as percentage time.
  • Splitting wages equally or by days alone.
  • A factor on the wrong side in M1D1H1M_1 D_1 H_1.
  • Adding an outlet. A leak always subtracts.

Quick revision

Rates

  • Rate =1time= \tfrac{1}{\text{time}}. Add rates, never times
  • Together: aba+b\tfrac{ab}{a + b}
  • One worker: subtract rates
  • Pairs: add and halve

Changing teams

  • Phase by phase, finishing what is left
  • Alternate days: cycle, then the last part-day

Efficiency and wages

  • Efficiency ∝ 1time\tfrac{1}{\text{time}}
  • M1D1H1W1=M2D2H2W2\tfrac{M_1 D_1 H_1}{W_1} = \tfrac{M_2 D_2 H_2}{W_2}
  • Wages follow work done

Pipes

  • Inlets +, outlets and leaks −
  • Leak rate =1p−1q= \tfrac{1}{p} - \tfrac{1}{q}

Rates in a moving setting are worked in time, speed and distance, and the ratio skills behind wage-sharing in ratio and proportion.

Next · 08Quick revision

Check your understanding

61 questions, grouped by type, easy to hard. Pick an answer and check it. The worked solution opens when you ask for it.

Work rate and working togetherQ1 of 61Q1

Work rate and working together

25 questions

Meenakshi can paint a boundary wall on her own in 10 days. What fraction of the wall does she paint in 3 days?

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AnswerC · 310\frac{3}{10}

  1. In one day she paints 110\frac{1}{10} of the wall.

  2. In 3 days she paints 3×110=3103 \times \frac{1}{10} = \frac{3}{10} of the wall.

Worth noting

710\frac{7}{10} is the part still left to paint, not the part done.

Aarav can tile a kitchen floor in 20 days and Gurpreet can tile the same floor in 30 days. If they work together, in how many days will the floor be tiled?

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AnswerB · 12 days

  1. Aarav's rate = 120\frac{1}{20} of the floor per day; Gurpreet's = 130\frac{1}{30}.

  2. Together: 120+130=3+260=112\frac{1}{20} + \frac{1}{30} = \frac{3 + 2}{60} = \frac{1}{12} per day.

  3. So they need 12 days.

Worth noting

Add the RATES, never the days. 25 days is the average of the two times and 50 is their sum — both ignore that working together is faster than either alone.

Fatima can type a project report in 6 hours and Joseph can type it in 12 hours. How long will they take if they split the typing and work at the same time?

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AnswerB · 4 hours

  1. Fatima's rate = 16\frac{1}{6} per hour; Joseph's = 112\frac{1}{12} per hour.

  2. Together: 16+112=2+112=312=14\frac{1}{6} + \frac{1}{12} = \frac{2+1}{12} = \frac{3}{12} = \frac{1}{4} per hour.

  3. So the report takes 4 hours.

Worth noting

The answer must be less than 6 hours, the faster person's time. That alone rules out 9 and 18 hours.

Two electricians, Harish and Nandini, together wire a house in 8 days. Harish alone would take 12 days. How many days would Nandini take alone?

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AnswerD · 24 days

  1. Together they do 18\frac{1}{8} of the job per day; Harish does 112\frac{1}{12}.

  2. Nandini's rate = 18−112=3−224=124\frac{1}{8} - \frac{1}{12} = \frac{3-2}{24} = \frac{1}{24} per day.

  3. So Nandini alone needs 24 days.

Worth noting

Subtracting the days (12−8=4)(12 - 8 = 4) is the common slip. Subtract the rates, then flip.

Mohit has sanded 38\frac{3}{8} of a wooden deck in 6 days. Working at the same rate, how many days does he need for the whole deck?

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AnswerC · 16 days

  1. 38\frac{3}{8} of the deck takes 6 days.

  2. Whole deck = 6÷38=6×83=166 \div \frac{3}{8} = 6 \times \frac{8}{3} = 16 days.

Worth noting

10 days is only the time for the remaining 58\frac{5}{8}. Multiplying 6×386 \times \frac{3}{8} gives 2142\frac{1}{4}, which is upside down.

Sana has completed 25\frac{2}{5} of a school survey in 8 days. At the same pace, how many more days will she need to finish it?

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AnswerB · 12 days

  1. 25\frac{2}{5} in 8 days means the whole survey takes 8×52=208 \times \frac{5}{2} = 20 days.

  2. The remaining 35\frac{3}{5} takes 35×20=12\frac{3}{5} \times 20 = 12 days.

Worth noting

20 days is the whole survey, and 28 days adds the 8 already spent. The question asks only for the days still needed.

Rekha can pack a consignment of parcels in 4 hours and Prakash in 6 hours. What fraction of the consignment do they pack together in 1 hour?

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AnswerD · 512\frac{5}{12}

  1. Rekha packs 14\frac{1}{4} per hour; Prakash packs 16\frac{1}{6}.

  2. Together: 14+16=3+212=512\frac{1}{4} + \frac{1}{6} = \frac{3+2}{12} = \frac{5}{12}.

Worth noting

110\frac{1}{10} comes from adding the hours (4+6)(4 + 6) instead of the rates. 712\frac{7}{12} is what is left, not what is done.

Lalremsiami can weave a shawl in 5 days and her apprentice Anjali in 20 days. Weaving together on the same loom, how many days will the shawl take?

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AnswerA · 4 days

  1. Rates: 15\frac{1}{5} and 120\frac{1}{20} per day.

  2. Together: 420+120=520=14\frac{4}{20} + \frac{1}{20} = \frac{5}{20} = \frac{1}{4} per day, so 4 days.

Worth noting

Together must be quicker than 5 days, the faster weaver's time.

Neha can check a pile of 60 answer sheets in 4 hours and Manoj can check the same pile in 6 hours. If they share the pile and work at the same time, how long will it take?

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AnswerB · 2 hours 24 minutes

  1. Together: 14+16=512\frac{1}{4} + \frac{1}{6} = \frac{5}{12} of the pile per hour.

  2. Time = 125\frac{12}{5} hours = 2 hours + 25×60\frac{2}{5} \times 60 minutes = 2 hours 24 minutes.

Worth noting

0.4 hour is 24 minutes, not 40 minutes. 5 hours is the average of the two times, and 10 hours is their sum.

A can finish a piece of work in 12 days and B can finish the same work in 18 days. Working together, how long will they take?

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AnswerA · 7.2 days

  1. Work in one day rather than in whole jobs. A does 112\frac{1}{12} of the work each day and B does 118\frac{1}{18}.

  2. Together they do 112+118=336+236=536\frac{1}{12} + \frac{1}{18} = \frac{3}{36} + \frac{2}{36} = \frac{5}{36} of the work per day.

  3. The whole job therefore takes 365=7.2\frac{36}{5} = 7.2 days.

Worth noting

The answer must be less than 12, the faster worker's time alone. Averaging the two times gives 15 days, which is longer than either of them working alone.

Three volunteers are cleaning a beach. Priya alone would take 10 days, Tenzin 15 days and Omar 30 days. How many days will the job take if all three work together?

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AnswerA · 5 days

  1. Rates per day: 110,115,130\frac{1}{10}, \frac{1}{15}, \frac{1}{30}.

  2. With LCM 30: 330+230+130=630=15\frac{3}{30} + \frac{2}{30} + \frac{1}{30} = \frac{6}{30} = \frac{1}{5}.

  3. All three together finish in 5 days.

Worth noting

6 days is what Priya and Tenzin need without Omar. Every extra worker, however slow, shortens the time.

Ravi can repair a road stretch in 20 days and Sunita in 30 days. They work together for 6 days, after which Ravi is moved to another site and Sunita finishes the rest alone. How many days does the whole repair take?

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AnswerD · 21 days

  1. Together they do 120+130=112\frac{1}{20} + \frac{1}{30} = \frac{1}{12} per day.

  2. In 6 days: 6×112=126 \times \frac{1}{12} = \frac{1}{2} of the road.

  3. Sunita does the other 12\frac{1}{2} at 130\frac{1}{30} per day: 12×30=15\frac{1}{2} \times 30 = 15 days.

  4. Total = 6+15=216 + 15 = 21 days.

Worth noting

15 days is only Sunita's part; the question asks for the whole repair, so add the first 6 days.

Kavya starts writing code for an app on her own; she could finish it alone in 24 days. After 6 days, Rohan joins her; he could finish the whole app alone in 12 days. How many days after Rohan joins is the app finished?

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AnswerA · 6 days

  1. In 6 days Kavya does 624=14\frac{6}{24} = \frac{1}{4} of the app, leaving 34\frac{3}{4}.

  2. Together: 124+112=324=18\frac{1}{24} + \frac{1}{12} = \frac{3}{24} = \frac{1}{8} per day.

  3. Time for 34\frac{3}{4}: 34÷18=6\frac{3}{4} \div \frac{1}{8} = 6 days.

Worth noting

12 days is the total from the start (6+6)(6 + 6). 9 days is Rohan alone doing the remaining three-quarters, forgetting Kavya keeps working.

Sneha can plaster a room in 6 days and Irfan in 9 days. They work on alternate days, with Sneha working on the first day. In how many days is the room plastered?

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AnswerD · 7 days

  1. Two-day cycle: 16+19=3+218=518\frac{1}{6} + \frac{1}{9} = \frac{3+2}{18} = \frac{5}{18}.

  2. 3 cycles (6 days) finish 1518\frac{15}{18}, leaving 318=16\frac{3}{18} = \frac{1}{6}.

  3. Day 7 is Sneha's, and she does exactly 16\frac{1}{6} in a day.

  4. So the room is done in 7 days.

Worth noting

Alternate-day work is not the same as working together. 3353\frac{3}{5} days is the together time and doubling it gives 7157\frac{1}{5}, which is wrong because the last day finishes the job early.

Three friends are building a model city for an exhibition. Ananya and Bilal together would take 10 days, Bilal and Charu 15 days, and Charu and Ananya 12 days. How many days would all three take working together?

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AnswerB · 8 days

  1. Add the three pair rates: 110+115+112=6+4+560=14\frac{1}{10} + \frac{1}{15} + \frac{1}{12} = \frac{6+4+5}{60} = \frac{1}{4}.

  2. Each person is counted twice, so the three together do 14÷2=18\frac{1}{4} \div 2 = \frac{1}{8} per day.

  3. All three finish in 8 days.

Worth noting

Forgetting to halve gives 4 days. 12⅓ days is just the average of the three pair times.

Working in pairs on a mural, Deepa and Elango take 12 days, Elango and Farhan take 20 days, and Deepa and Farhan take 15 days. How many days would Farhan take working alone?

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AnswerD · 60 days

  1. Sum of pair rates: 112+120+115=5+3+460=15\frac{1}{12} + \frac{1}{20} + \frac{1}{15} = \frac{5+3+4}{60} = \frac{1}{5}.

  2. All three together: 15÷2=110\frac{1}{5} \div 2 = \frac{1}{10} per day.

  3. Farhan = all three − (Deepa + Elango) = 110−112=160\frac{1}{10} - \frac{1}{12} = \frac{1}{60}.

  4. Farhan alone takes 60 days.

Worth noting

Subtract the pair that does NOT contain Farhan. Removing the wrong pair gives Deepa's 20 days or Elango's 30 days instead.

Varun can dig a garden bed in 10 days and Lakshmi in 15 days. They start together, but Varun stops 5 days before the digging is finished and Lakshmi completes it. How many days does the digging take in all?

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AnswerC · 9 days

  1. Let the total be TT days. Lakshmi works all TT days; Varun works T−5T - 5.

  2. T−510+T15=1\frac{T-5}{10} + \frac{T}{15} = 1. Multiply by 30: 3(T−5)+2T=303(T - 5) + 2T = 30.

  3. 5T=455T = 45, so T=9T = 9 days.

Worth noting

8 days comes from letting the wrong person stop early. 11 days wrongly adds the 5 days to the together time of 6 days.

Aditi can knit a blanket in 16 days. She knits for 4 days and then hands it to her grandmother, who finishes the rest in 18 days. How many days would the grandmother take to knit a whole blanket?

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AnswerC · 24 days

  1. Aditi's 4 days = 416=14\frac{4}{16} = \frac{1}{4} of the blanket.

  2. The grandmother does 34\frac{3}{4} in 18 days.

  3. Whole blanket: 18÷34=2418 \div \frac{3}{4} = 24 days.

Worth noting

18 days is the time for only 34\frac{3}{4} of the blanket. 27 days comes from multiplying by 32\frac{3}{2} instead of 43\frac{4}{3}.

Three workers, Salim, Tanya and Uday, can build a shed alone in 30, 40 and 60 days. All three begin together, but after 4 days Uday leaves. How many more days do Salim and Tanya need to finish the shed?

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AnswerA · 12 days

  1. All three: 4+3+2120=9120=340\frac{4 + 3 + 2}{120} = \frac{9}{120} = \frac{3}{40} per day.

  2. In 4 days: 1240=310\frac{12}{40} = \frac{3}{10} done, so 710\frac{7}{10} remains.

  3. Salim + Tanya: 4+3120=7120\frac{4+3}{120} = \frac{7}{120} per day.

  4. Time: 710÷7120=12\frac{7}{10} \div \frac{7}{120} = 12 days.

Worth noting

16 days is the total from the start; the question asks for the days after Uday leaves.

Nikhil finishes 13\frac{1}{3} of a data-entry job in 5 days, and Pooja finishes 25\frac{2}{5} of the same job in 8 days. Working together, how long will they take for the whole job?

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AnswerA · 8478\frac{4}{7} days

  1. Nikhil's whole job: 5×3=155 \times 3 = 15 days, rate 115\frac{1}{15}.

  2. Pooja's whole job: 8×52=208 \times \frac{5}{2} = 20 days, rate 120\frac{1}{20}.

  3. Together: 115+120=4+360=760\frac{1}{15} + \frac{1}{20} = \frac{4+3}{60} = \frac{7}{60} per day.

  4. Time = 607=847\frac{60}{7} = 8\frac{4}{7} days.

Worth noting

Convert each part-job into a full-job rate first. 13 days just adds the 5 and 8 days given.

Jaya can sew a set of curtains in 25 days and Karthik in 20 days. They work together for 5 days. What fraction of the job is still left?

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AnswerB · 1120\frac{11}{20}

  1. Together: 125+120=4+5100=9100\frac{1}{25} + \frac{1}{20} = \frac{4+5}{100} = \frac{9}{100} per day.

  2. In 5 days: 45100=920\frac{45}{100} = \frac{9}{20} done.

  3. Left: 1−920=11201 - \frac{9}{20} = \frac{11}{20}.

Worth noting

920\frac{9}{20} is the part finished; the question asks what is left.

A printing machine M can print a batch of posters in 5 hours and an older machine N in 8 hours. Only one machine runs at a time: they take turns for one hour each, and N runs the first hour. How long does the batch take?

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AnswerB · 6156\frac{1}{5} hours

  1. One two-hour cycle prints 18+15=1340\frac{1}{8} + \frac{1}{5} = \frac{13}{40}.

  2. 3 cycles (6 hours) print 3940\frac{39}{40}, leaving 140\frac{1}{40}.

  3. Hour 7 belongs to N, which prints 18=540\frac{1}{8} = \frac{5}{40} per hour.

  4. Time for 140\frac{1}{40}: 1/401/8=15\frac{1/40}{1/8} = \frac{1}{5} hour, so the total is 6156\frac{1}{5} hours.

Worth noting

Who starts matters. If M ran first, the last scrap would be done by M in 18\frac{1}{8} hour, giving 6186\frac{1}{8} hours. Rounding up to 7 hours ignores that the job ends part-way through an hour.

Two tailors together stitch a batch of school uniforms in 6 days. Working alone, one of them takes 5 days more than the other. How many days would the slower tailor take alone?

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AnswerC · 15 days

  1. Let the faster tailor take xx days; the slower takes x+5x + 5.

  2. 1x+1x+5=16\frac{1}{x} + \frac{1}{x+5} = \frac{1}{6}, so 6(2x+5)=x(x+5)6(2x + 5) = x(x + 5).

  3. x2−7x−30=0x^2 - 7x - 30 = 0, i.e. (x−10)(x+3)=0(x - 10)(x + 3) = 0, so x=10x = 10.

  4. The slower tailor takes 10+5=1510 + 5 = 15 days.

Worth noting

Check the answer: 1/10+1/15=1/61/10 + 1/15 = 1/6. 10 days is the faster tailor; 12 days wrongly assumes both are equal (2×6)(2 \times 6).

Two carpenters, Manoj and Rehana, can make a set of classroom benches together in 12 days. They work together for 5 days, then Rehana leaves and Manoj finishes the rest alone in 21 days. How many days would Rehana take to make the whole set alone?

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AnswerA · 18 days

  1. In 5 days together: 512\frac{5}{12} done, leaving 712\frac{7}{12}.

  2. Manoj does 712\frac{7}{12} in 21 days, so his rate is 712÷21=136\frac{7}{12} \div 21 = \frac{1}{36} per day.

  3. Rehana's rate = 112−136=236=118\frac{1}{12} - \frac{1}{36} = \frac{2}{36} = \frac{1}{18}.

  4. Rehana alone takes 18 days.

Worth noting

36 days is Manoj's time, not Rehana's. 28 days comes from treating Manoj's 21 days as the whole job instead of the remaining seven-twelfths.

Gopal can whitewash a school building in 16 days. Two helpers, Hema and Iqbal, could do it alone in 24 and 48 days. Gopal works every day, but the helpers join him only on every third day (day 3, day 6, day 9, …). In how many days is the building whitewashed?

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AnswerB · 12 days

  1. In each 3-day block Gopal does 3×116=9483 \times \frac{1}{16} = \frac{9}{48}; the helpers add 124+148=348\frac{1}{24} + \frac{1}{48} = \frac{3}{48}.

  2. One block = 1248=14\frac{12}{48} = \frac{1}{4} of the building.

  3. 4 blocks finish it, and the 4th block ends on a helper day, so the time is 4×3=124 \times 3 = 12 days.

Worth noting

8 days would be right only if all three worked every day. Always check that the last block really ends on the day you count.

Efficiency and wages

18 questions

A new harvesting machine works twice as fast as an old one. The old machine takes 30 days to harvest a farm. How many days does the new machine take?

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AnswerA · 15 days

  1. Twice as fast means twice the work per day.

  2. So it needs half the time: 30÷2=1530 \div 2 = 15 days.

Worth noting

Time and efficiency are inversely related: double the speed, half the days. 60 days multiplies instead of dividing, and 45 days adds 50% instead of halving.

Asha can prepare a science exhibit in 18 days and Deepa can prepare it in 24 days. What is the ratio of Asha's efficiency to Deepa's efficiency?

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AnswerB · 4:34 : 3

  1. Efficiency is work per day: Asha 118\frac{1}{18}, Deepa 124\frac{1}{24}.

  2. Ratio = 118:124=24:18=4:3\frac{1}{18} : \frac{1}{24} = 24 : 18 = 4 : 3.

Worth noting

Efficiency is the inverse of time, so the ratio flips. 3:43 : 4 is the ratio of their times.

A team of 12 workers can build a compound wall in 15 days. How many workers are needed to build the same wall in 9 days?

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AnswerC · 20

  1. Total work = 12×15=18012 \times 15 = 180 worker-days.

  2. Workers for 9 days = 180÷9=20180 \div 9 = 20.

Worth noting

Fewer days need MORE workers. 7.2 comes from 12×91512 \times \frac{9}{15}, treating it as direct proportion.

Rakesh can assemble a cupboard in 20 hours. Tanvi is 25% more efficient than Rakesh. How long will Tanvi take to assemble the same cupboard?

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AnswerB · 16 hours

  1. 25% more efficient: Tanvi does 54\frac{5}{4} of Rakesh's work per hour.

  2. Time = 20÷54=20×45=1620 \div \frac{5}{4} = 20 \times \frac{4}{5} = 16 hours.

Worth noting

25% more efficient does NOT mean 25% less time. 20−25%=1520 - 25\% = 15 hours is the trap; the time falls by only 20%.

8 tailors stitch 120 shirts in 5 days. How many shirts will 10 tailors stitch in 6 days at the same rate?

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AnswerD · 180

  1. One tailor stitches 1208×5=3\frac{120}{8 \times 5} = 3 shirts a day.

  2. 10 tailors in 6 days: 3×10×6=1803 \times 10 \times 6 = 180 shirts.

Worth noting

150 shirts accounts only for the extra tailors, and 144 only for the extra day. Both changes increase the output.

Rajesh works three times as fast as his trainee Sameer. Together they can service all the fans in a hostel in 14 days. How many days would Sameer take alone?

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AnswerD · 56 days

  1. Let Sameer do 1 unit per day; Rajesh does 3 units. Together: 4 units per day.

  2. Total work = 4×14=564 \times 14 = 56 units.

  3. Sameer alone: 56÷1=5656 \div 1 = 56 days.

Worth noting

182318\frac{2}{3} days is Rajesh's time. 42 days multiplies the together time by 3 instead of by 4 — the together rate is 3+1=43 + 1 = 4 shares.

16 labourers working 9 hours a day can finish a building's flooring in 20 days. How many days will 24 labourers working 8 hours a day take for the same flooring?

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AnswerB · 15 days

  1. Total work = 16×9×20=288016 \times 9 \times 20 = 2880 labour-hours.

  2. New team per day: 24×8=19224 \times 8 = 192 labour-hours.

  3. Days = 2880÷192=152880 \div 192 = 15.

Worth noting

Ignoring the change in hours gives 131313\frac{1}{3} days. Use M1D1H1=M2D2H2M_1D_1H_1 = M_2D_2H_2 with every factor.

Anil can paint a house in 10 days and Bharti in 15 days. They paint it together and are paid ₹4,500 in all. If the money is shared by the work each does, how much does Anil get?

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AnswerC · ₹2,700

  1. Working the same number of days, work done is in the ratio of rates: 110:115=3:2\frac{1}{10} : \frac{1}{15} = 3 : 2.

  2. Anil's share = 35×4500=₹2,700\frac{3}{5} \times 4500 = ₹2{,}700.

Worth noting

Share by work, i.e. by efficiency, not by days. ₹1,800 is Bharti's share; splitting equally gives ₹2,250.

Ishita is 50% more efficient than Farooq. Together they can catalogue a library in 18 days. How many days would Ishita take alone?

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AnswerB · 30 days

  1. Let Farooq do 2 units per day; Ishita does 3 units. Together: 5 units per day.

  2. Total work = 5×18=905 \times 18 = 90 units.

  3. Ishita alone: 90÷3=3090 \div 3 = 30 days.

Worth noting

45 days is Farooq's time. 27 days (18×1.5)(18 \times 1.5) wrongly treats efficiency as if it were time.

At a pottery unit, 3 men or 5 women can glaze a batch of pots in 20 hours. How long will 6 men and 5 women take together?

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AnswerA · 6236\frac{2}{3} hours

  1. 6 men are twice 3 men, so 6 men alone take 10 hours: rate 110\frac{1}{10}.

  2. 5 women alone take 20 hours: rate 120\frac{1}{20}.

  3. Together: 110+120=320\frac{1}{10} + \frac{1}{20} = \frac{3}{20}, so time = 203=623\frac{20}{3} = 6\frac{2}{3} hours.

Worth noting

Averaging 10 and 20 hours gives 15 hours and adding them gives 30 hours — both slower than the men alone, which is impossible when helpers are added.

Arjun can tile a terrace in 16 days and Bina in 24 days. Arjun works alone for 4 days, and then Bina finishes the job alone. The total payment is ₹7,200, shared by the work each did. How much does Bina get?

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AnswerD · ₹5,400

  1. Arjun's 4 days = 416=14\frac{4}{16} = \frac{1}{4} of the job.

  2. Bina does the remaining 34\frac{3}{4}.

  3. Bina's share = 34×7200=₹5,400\frac{3}{4} \times 7200 = ₹5{,}400.

Worth noting

They did not work for the same time, so the efficiency ratio 3:23 : 2 does not apply here; ₹2,880 comes from wrongly using it. ₹1,800 is Arjun's share.

An experienced mason is three times as efficient as a new mason and so takes 24 days less to build a wall. In how many days can they build the wall working together?

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AnswerA · 9 days

  1. If the experienced mason takes xx days, the new one takes 3x3x.

  2. 3x−x=243x - x = 24, so x=12x = 12 and 3x=363x = 36.

  3. Together: 112+136=436=19\frac{1}{12} + \frac{1}{36} = \frac{4}{36} = \frac{1}{9}, i.e. 9 days.

Worth noting

12 days is the experienced mason alone; together must be faster than that.

A contractor estimates that 45 workers will finish a metro-station floor in 32 days. If he hires 60 workers instead, how many days earlier will the floor be finished?

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AnswerA · 8 days

  1. Total work = 45×32=144045 \times 32 = 1440 worker-days.

  2. With 60 workers: 1440÷60=241440 \div 60 = 24 days.

  3. Days saved = 32−24=832 - 24 = 8 days.

Worth noting

24 days is the new time, not the saving. The question asks how many days EARLIER.

10 workers, working 6 hours a day, dig a 60 m long drainage trench in 12 days. How many days will 15 workers, working 8 hours a day, take to dig a 90 m trench of the same width and depth?

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AnswerB · 9 days

  1. Use M1D1H1W1=M2D2H2W2\frac{M_1D_1H_1}{W_1} = \frac{M_2D_2H_2}{W_2}.

  2. 10×12×660=15×D×890\frac{10 \times 12 \times 6}{60} = \frac{15 \times D \times 8}{90}, so 12=120D9012 = \frac{120D}{90}.

  3. D=12×90120=9D = \frac{12 \times 90}{120} = 9 days.

Worth noting

Forgetting that the second trench is longer gives 6 days. Putting the hours on the wrong side gives 16 days.

Chitra can plaster a hall in 12 days and Dinesh in 16 days. With the help of Ezhil, all three finish it in 4 days. The ₹3,600 payment is shared by the work each did. What is Ezhil's share?

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AnswerC · ₹1,500

  1. In 4 days Chitra does 412=13\frac{4}{12} = \frac{1}{3}; Dinesh does 416=14\frac{4}{16} = \frac{1}{4}.

  2. Ezhil does the rest: 1−13−14=5121 - \frac{1}{3} - \frac{1}{4} = \frac{5}{12}.

  3. Ezhil's share = 512×3600=₹1,500\frac{5}{12} \times 3600 = ₹1{,}500.

Worth noting

All three worked the same 4 days, but that does not mean equal pay: splitting three ways gives ₹1,200, which is Chitra's share, not Ezhil's.

A contractor plans to lay a road with 30 workers in 40 days. After 16 days, 10 more workers join. In how many days in all is the road finished?

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AnswerC · 34 days

  1. Total work = 30×40=120030 \times 40 = 1200 worker-days.

  2. In 16 days: 30×16=48030 \times 16 = 480 worker-days, leaving 720.

  3. Now 40 workers: 720÷40=18720 \div 40 = 18 more days.

  4. Total = 16+18=3416 + 18 = 34 days.

Worth noting

18 days counts only the time after the new workers join. 30 days (1200÷40)(1200 \div 40) assumes all 40 workers were there from day 1.

Kiran, Leela and Mustafa can build a stage alone in 10, 12 and 15 days. All three start together. Kiran leaves after 2 days, Leela leaves 3 days after that, and Mustafa finishes the stage. The ₹9,000 payment is shared by the work done. What is Mustafa's share?

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AnswerC · ₹3,450

  1. First 2 days, all three: 2×6+5+460=30602 \times \frac{6+5+4}{60} = \frac{30}{60}.

  2. Next 3 days, Leela + Mustafa: 3×5+460=27603 \times \frac{5+4}{60} = \frac{27}{60}. Total so far 5760\frac{57}{60}.

  3. Mustafa does the last 360\frac{3}{60} in 34\frac{3}{4} day, so he worked 5345\frac{3}{4} days.

  4. Mustafa's work = 234×115=2360\frac{23}{4} \times \frac{1}{15} = \frac{23}{60}; share = 2360×9000=₹3,450\frac{23}{60} \times 9000 = ₹3{,}450.

Worth noting

Check: Kiran did 12/6012/60 and Leela 25/6025/60, and 12+25+23=6012 + 25 + 23 = 60. ₹3,750 is Leela's share and ₹1,800 is Kiran's.

Rupa works twice as efficiently as Sanjay. To finish a contract, Rupa works for 5 days and Sanjay for 8 days. The ₹5,400 payment is shared by the work each did. What is Rupa's share?

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AnswerD · ₹3,000

  1. Let Sanjay do 1 unit per day; Rupa does 2 units.

  2. Rupa's work = 2×5=102 \times 5 = 10 units; Sanjay's=1×8=8s = 1 \times 8 = 8 units.

  3. Rupa's share = 1018×5400=₹3,000\frac{10}{18} \times 5400 = ₹3{,}000.

Worth noting

Pay follows work = efficiency × days. Using only the efficiency ratio 2:12 : 1 gives ₹3,600; using only the days 5:85 : 8 ignores that Rupa is faster. ₹2,400 is Sanjay's share.

Pipes and cisterns

18 questions

An overhead tank can be filled by pipe P in 12 hours and by pipe Q in 15 hours. If both pipes are opened together on an empty tank, how long will it take to fill?

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AnswerA · 6 hours 40 minutes

  1. Together: 112+115=5+460=960=320\frac{1}{12} + \frac{1}{15} = \frac{5+4}{60} = \frac{9}{60} = \frac{3}{20} per hour.

  2. Time = 203\frac{20}{3} hours = 6 hours 40 minutes.

Worth noting

27 hours adds the two times and 13 hours 30 minutes averages them. Two pipes must fill faster than the quicker pipe alone.

A tap fills a water drum in 10 hours, but a crack at the bottom would empty the full drum in 30 hours. With the tap on and the crack leaking, how long does the empty drum take to fill?

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AnswerA · 15 hours

  1. Net rate = 110−130=3−130=115\frac{1}{10} - \frac{1}{30} = \frac{3-1}{30} = \frac{1}{15} per hour.

  2. So the drum fills in 15 hours.

Worth noting

A leak works against the tap, so subtract its rate. Subtracting the hours (30−10)(30 - 10) gives 20 hours, and 40 hours adds them.

A garden tap fills 34\frac{3}{4} of a tub in 9 minutes. How long does it take to fill the whole tub?

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AnswerC · 12 minutes

  1. 34\frac{3}{4} of the tub takes 9 minutes, so 14\frac{1}{4} takes 3 minutes.

  2. The whole tub takes 4×3=124 \times 3 = 12 minutes.

Worth noting

3 minutes is only the last quarter. 6346\frac{3}{4} minutes comes from multiplying 9 by 34\frac{3}{4} instead of dividing.

A 1,200-litre tank is being filled at 40 litres per minute, but a leak lets out 10 litres per minute. How many minutes does the empty tank take to fill?

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AnswerC · 40 minutes

  1. Net inflow = 40−10=3040 - 10 = 30 litres per minute.

  2. Time = 1200÷30=401200 \div 30 = 40 minutes.

Worth noting

30 minutes ignores the leak, and 24 minutes adds the leak to the inflow.

An outlet can empty a full swimming-pool tank in 18 minutes. What fraction of the water is still in the tank after the outlet has run for 6 minutes?

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AnswerD · 23\frac{2}{3}

  1. In 6 minutes the outlet removes 618=13\frac{6}{18} = \frac{1}{3} of the water.

  2. Water left = 1−13=231 - \frac{1}{3} = \frac{2}{3}.

Worth noting

13\frac{1}{3} is the fraction drained, not the fraction left.

One pipe fills a water tanker in 9 hours. How long will three identical pipes working together take to fill it?

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AnswerA · 3 hours

  1. Each pipe fills 19\frac{1}{9} per hour; three fill 39=13\frac{3}{9} = \frac{1}{3} per hour.

  2. Time = 3 hours.

Worth noting

More identical pipes mean less time: divide, don't multiply. 27 hours multiplies by 3.

A 900-litre tank already holds 300 litres. An inlet adds 25 litres per minute while an outlet removes 15 litres per minute. With both open, how many minutes will the tank take to fill?

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AnswerD · 60 minutes

  1. Water still needed = 900−300=600900 - 300 = 600 litres.

  2. Net inflow = 25−15=1025 - 15 = 10 litres per minute.

  3. Time = 600÷10=60600 \div 10 = 60 minutes.

Worth noting

36 minutes fills the whole 900 litres with the inlet alone; 24 minutes ignores the outlet. Use the space left and the net flow.

A school's water tank has two inlet pipes that fill it in 20 and 30 minutes, and an outlet that empties it in 15 minutes. If all three are opened on an empty tank, how long will it take to fill?

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AnswerD · 60 minutes

  1. Inlets: 120+130=3+260=560\frac{1}{20} + \frac{1}{30} = \frac{3+2}{60} = \frac{5}{60} per minute.

  2. Outlet: 115=460\frac{1}{15} = \frac{4}{60} per minute.

  3. Net: 5−460=160\frac{5 - 4}{60} = \frac{1}{60}, so 60 minutes.

Worth noting

12 minutes ignores the outlet; 6236\frac{2}{3} minutes treats the outlet as a third filler. An outlet's rate is always subtracted.

Pipe A can fill a cistern in 8 hours and pipe B in 12 hours. Both are opened, and after 2 hours pipe A is shut. How many more hours does pipe B take to fill the cistern?

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AnswerA · 7 hours

  1. Both together: 18+112=524\frac{1}{8} + \frac{1}{12} = \frac{5}{24} per hour.

  2. In 2 hours: 1024=512\frac{10}{24} = \frac{5}{12} filled, leaving 712\frac{7}{12}.

  3. B alone: 712×12=7\frac{7}{12} \times 12 = 7 hours.

Worth noting

9 hours is the total from the start. 10 hours (12−2)(12 - 2) forgets that A also filled part of the cistern in the first 2 hours.

A pump can normally fill a sump in 6 hours. Because of a leak, it now takes 8 hours to fill. If the sump is full and the pump is off, how long will the leak take to empty it?

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AnswerD · 24 hours

  1. Pump alone: 16\frac{1}{6} per hour. Pump with leak: 18\frac{1}{8} per hour.

  2. Leak's rate = 16−18=4−324=124\frac{1}{6} - \frac{1}{8} = \frac{4-3}{24} = \frac{1}{24}.

  3. The leak empties the full sump in 24 hours.

Worth noting

2 hours subtracts the times (8−6)(8 - 6). 3373\frac{3}{7} hours adds the rates, as if the leak helped the pump.

Pipes A and B can fill a tank in 30 and 45 minutes. Both are opened on an empty tank, and B is closed after some time. The tank is full exactly 20 minutes after the pipes were opened. For how many minutes was B open?

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AnswerC · 15 minutes

  1. A runs all 20 minutes: 2030=23\frac{20}{30} = \frac{2}{3} of the tank.

  2. B filled the rest, 13\frac{1}{3}: time = 13×45=15\frac{1}{3} \times 45 = 15 minutes.

Worth noting

18 minutes is how long both together would take for the whole tank. 10 minutes uses A's 30 minutes instead of B's 45 when converting B's third.

A full tank has an outlet that can empty it in 10 hours and an inlet that can fill it in 15 hours. If both are opened at the same time, how long will the tank take to become empty?

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AnswerD · 30 hours

  1. Emptying beats filling: net emptying rate = 110−115=3−230=130\frac{1}{10} - \frac{1}{15} = \frac{3-2}{30} = \frac{1}{30} per hour.

  2. The tank empties in 30 hours.

Worth noting

6 hours adds both rates as if both were emptying. 5 hours subtracts the times. Check: 30 hours is slower than the outlet alone, as it should be.

Two pipes can fill a storage tank in 20 minutes and 24 minutes. A drain at the bottom lets out 3 litres per minute. With both pipes and the drain open, the empty tank fills in 15 minutes. What is the capacity of the tank?

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AnswerB · 120 litres

  1. Pipes together: 120+124=11120\frac{1}{20} + \frac{1}{24} = \frac{11}{120} of the tank per minute.

  2. With the drain the net is 115=8120\frac{1}{15} = \frac{8}{120}, so the drain removes 3120=140\frac{3}{120} = \frac{1}{40} of the tank per minute.

  3. 140\frac{1}{40} of the tank = 3 litres, so the tank holds 3×40=1203 \times 40 = 120 litres.

Worth noting

Check: the pipes add 6 and 5 litres a minute, the drain removes 3, net 8 litres a minute, and 120÷8=15120 \div 8 = 15 minutes. 40 is the drain's emptying time in minutes, not the capacity.

A cistern has two inlets, which fill it in 15 minutes and 10 minutes, and one outlet. With all three open, the empty cistern fills in 18 minutes. How long would the outlet alone take to empty the full cistern?

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AnswerC · 9 minutes

  1. Inlets together: 115+110=2+330=16\frac{1}{15} + \frac{1}{10} = \frac{2+3}{30} = \frac{1}{6} per minute.

  2. Outlet = inlets − net = 16−118=3−118=218=19\frac{1}{6} - \frac{1}{18} = \frac{3-1}{18} = \frac{2}{18} = \frac{1}{9}.

  3. The outlet empties it in 9 minutes.

Worth noting

4124\frac{1}{2} minutes comes from adding 16\frac{1}{6} and 118\frac{1}{18}. 6 minutes is just the two inlets together.

A tank is half full. Pipe X can fill the whole tank in 16 minutes and pipe Y can empty the whole tank in 24 minutes. If both are opened now, in how many minutes will the tank be full?

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AnswerC · 24 minutes

  1. Net fill rate = 116−124=3−248=148\frac{1}{16} - \frac{1}{24} = \frac{3-2}{48} = \frac{1}{48} per minute.

  2. Only half the tank needs filling: 12×48=24\frac{1}{2} \times 48 = 24 minutes.

Worth noting

48 minutes fills an empty tank; this one is already half full. 8 minutes ignores pipe Y.

A reservoir has two inlets that fill it in 10 hours and 15 hours, and an outlet that empties it in 12 hours. At 8 am the two inlets are opened on the empty reservoir. At 10 am the outlet is also opened by mistake and left open. At what time is the reservoir full?

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AnswerB · 6 pm

  1. Inlets together: 110+115=16\frac{1}{10} + \frac{1}{15} = \frac{1}{6} per hour; in 2 hours 13\frac{1}{3} is full.

  2. With the outlet: 6+4−560=560=112\frac{6 + 4 - 5}{60} = \frac{5}{60} = \frac{1}{12} per hour.

  3. The remaining 23\frac{2}{3} takes 23×12=8\frac{2}{3} \times 12 = 8 hours.

  4. Full at 10 am + 8 hours = 6 pm.

Worth noting

2 pm ignores the outlet completely. 8 pm assumes the outlet was open from 8 am, and 10 pm counts 12 hours from 10 am as if nothing had been filled before.

A pipe can fill a tank in 30 minutes. After it has been running for 10 minutes, a leak starts at the bottom, and because of it the tank fills 10 minutes later than it should have. How long would the leak alone take to empty the full tank?

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AnswerD · 90 minutes

  1. In the first 10 minutes the pipe fills 13\frac{1}{3} of the tank.

  2. The remaining 23\frac{2}{3} should take 20 minutes but takes 30, so the net rate is 23÷30=145\frac{2}{3} \div 30 = \frac{1}{45}.

  3. Leak = 130−145=3−290=190\frac{1}{30} - \frac{1}{45} = \frac{3-2}{90} = \frac{1}{90}, so it empties the tank in 90 minutes.

Worth noting

45 minutes is the time the pipe-with-leak would take for a full tank, not the leak alone. Measure the net rate only over the part when the leak is actually running.

Pipe A fills a tank in 12 minutes and pipe B in 20 minutes. They are opened one at a time for a minute each, in turn, starting with A. How long does the empty tank take to fill?

Options for question 61

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AnswerA · 144514\frac{4}{5} minutes

  1. Each 2-minute cycle fills 112+120=5+360=860\frac{1}{12} + \frac{1}{20} = \frac{5+3}{60} = \frac{8}{60}.

  2. 7 cycles (14 minutes) fill 5660\frac{56}{60}, leaving 460\frac{4}{60}.

  3. Minute 15 is A's, and A fills 560\frac{5}{60} per minute, so it needs 45\frac{4}{5} of that minute.

  4. Total = 144514\frac{4}{5} minutes.

Worth noting

Doubling the together time (712×2=157\frac{1}{2} \times 2 = 15 minutes) ignores that the tank fills before the 8th cycle ends. Starting with B instead would give a different answer, so read who goes first.

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