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Ratio and Proportion for CUET General Aptitude

About 10 min to learn · 67 questions

Ratio and proportion sit under many CUET aptitude questions: sharing money, changing a ratio, coins in a bag, map scales, workers and days, and partners splitting a profit. The ideas are simple, but the questions are built around a few predictable slips: mixed units, the wrong order, direct taken for inverse, and time ignored in a partnership. This lesson gives the ideas, the fastest methods and the traps, with worked examples.

Syllabus area
General Mental Ability, Numerical Ability
On this page · 9 sections
  1. 01The core idea
  2. 02Ratios
  3. 03Proportion
  4. 04Variation
  5. 05Partnership
  6. 06Exam shortcuts
  7. 07Common mistakes
  8. 08Quick revision
  9. 09Check your understanding

The core idea

A ratio compares two quantities of the same kind by division, and a proportion says two ratios are equal. Almost every question in this chapter is fastest in "parts": write each quantity as so many parts, find what one part is worth, and read off everything else.

Before any arithmetic, check two things: that both quantities are in the same unit, and which way round the ratio goes. "Girls to boys" and "boys to girls" are different ratios, and both are usually among the options.

Ratios

What is a ratio and how do you simplify it?

A ratio a:ba : b means a÷ba \div b. To simplify it, divide both terms by their HCF, exactly as you would reduce a fraction: 84:12684 : 126 has HCF 42, so it is 2:32 : 3.

  • Put both quantities in the same unit first: 40 minutes to 2 hours is 40:120=1:340 : 120 = 1 : 3, not 40:240 : 2.
  • A ratio has no unit, so 3:53 : 5 of rupees and 3:53 : 5 of kilograms are the same ratio.
  • With fractions or decimals, multiply every term by the LCM of the denominators or by a power of 10: 13:14:16\tfrac{1}{3} : \tfrac{1}{4} : \tfrac{1}{6} times 12 is 4:3:24 : 3 : 2, and 0.4:1.50.4 : 1.5 times 10 is 4:154 : 15.

Watch out

Fractions inside a ratio do not keep their denominators' order: 12:13:14\tfrac{1}{2} : \tfrac{1}{3} : \tfrac{1}{4} becomes 6:4:36 : 4 : 3, not 2:3:42 : 3 : 4.

How do you compare two ratios quickly?

Cross-multiply. For a:ba : b and c:dc : d, a:ba : b is larger when a×da \times d is greater than b×cb \times c. With four or more ratios, decimals are usually faster.

Example 1 · Comparing ratios

Which is larger, 5:95 : 9 or 4:74 : 7?

  1. Cross-multiply: 5×7=355 \times 7 = 35 and 9×4=369 \times 4 = 36.

  2. 35 is less than 36, so 5:95 : 9 is the smaller ratio.

Answer
4:74 : 7

As decimals: 5÷9≈0.5565 \div 9 \approx 0.556 and 4÷7≈0.5714 \div 7 \approx 0.571.

How do you divide an amount in a given ratio?

Add the ratio terms to get the number of parts, find the value of one part, and multiply. If an amount TT is shared in a:b:ca : b : c, one part is Ta+b+c\tfrac{T}{a + b + c}.

Example 2 · Sharing in a ratio

₹4,500 is shared among three cousins in the ratio 3:5:73 : 5 : 7. What does the middle cousin get?

  1. Parts: 3+5+7=153 + 5 + 7 = 15.

  2. One part: 4,500÷15=3004{,}500 \div 15 = 300.

  3. Middle share: 5×300=1,5005 \times 300 = 1{,}500.

Answer

₹1,500

Check: 900+1,500+2,100=4,500900 + 1{,}500 + 2{,}100 = 4{,}500.

Exam shortcut

Parts work backwards too. If boys to girls is 7:47 : 4 and there are 28 girls, 4 parts are 28, one part is 7, and there are 49 boys.

How do you combine ratios like a : b and b : c?

Make the common term equal, then read off the combined ratio. If a:b=2:3a : b = 2 : 3 and b:c=5:4b : c = 5 : 4, change bb to 15, the LCM of 3 and 5: a:b=10:15a : b = 10 : 15 and b:c=15:12b : c = 15 : 12, so a:b:c=10:15:12a : b : c = 10 : 15 : 12.

Exam shortcut

If you only need a:ca : c, multiply the fractions: ac=ab×bc=23×54=56\tfrac{a}{c} = \tfrac{a}{b} \times \tfrac{b}{c} = \tfrac{2}{3} \times \tfrac{5}{4} = \tfrac{5}{6}. The compound ratio of two ratios multiplies them term by term: 3:43 : 4 and 8:98 : 9 give 24:36=2:324 : 36 = 2 : 3.

How do you solve "add a number to change the ratio" questions?

Write the quantities as multiples of one unknown, apply the change, and set the result equal to the new ratio. Anything the question does not mention stays the same.

Example 3 · Changing a ratio

Two numbers are in the ratio 5:85 : 8. If 6 is added to each, the ratio becomes 2:32 : 3. Find the numbers.

  1. Let them be 5x5x and 8x8x. Then 5x+68x+6=23\tfrac{5x + 6}{8x + 6} = \tfrac{2}{3}.

  2. Cross-multiply: 15x+18=16x+1215x + 18 = 16x + 12, so x=6x = 6.

Answer

30 and 48

Check: 36:54=2:336 : 54 = 2 : 3.

Ages and mixtures

  • "4 years ago" subtracts 4 from both ages, because everyone ages equally.
  • In a mixture, the ingredient you do not add stays fixed. 30 litres of milk and water in 4:14 : 1 has 24 L of milk and 6 L of water. For 3:13 : 1, the water must become 24÷3=824 \div 3 = 8 L, so add 2 L. The answer is the amount added, not the final amount.

How do you solve coins-in-a-bag questions?

Keep the ratio of the number of coins apart from the ratio of their values. If the ratio is by number, multiply each term by the coin's face value to get the value of one set. If it is by value, divide each share of the money by the face value to get the count.

Example 4 · Coins by number

A bag has ₹1, ₹2 and ₹10 coins in the ratio 4:3:14 : 3 : 1 by number, worth ₹200 in all. How many ₹2 coins are there?

  1. One set is worth 4×1+3×2+1×10=204 \times 1 + 3 \times 2 + 1 \times 10 = 20 rupees.

  2. Number of sets: 200÷20=10200 \div 20 = 10.

  3. ₹2 coins: 3×10=303 \times 10 = 30.

Answer

30

Watch out

If the values, not the numbers, are in 5:4:15 : 4 : 1, split ₹200 into ₹100, ₹80 and ₹20 and divide by the face values: 100 coins of ₹1, 40 of ₹2 and 2 of ₹10. And convert paise to rupees before adding: a 50-paise coin is ₹0.5.

Proportion

What is a proportion, and what are the fourth, third and mean proportionals?

Four numbers are in proportion, written a:b::c:da : b :: c : d, when a:b=c:da : b = c : d. The key fact is that the product of the extremes equals the product of the means: a×d=b×ca \times d = b \times c.

TermConditionFormula
Fourth proportional to a,b,ca, b, ca:b=c:xa : b = c : xx=bcax = \tfrac{bc}{a}
Third proportional to a,ba, ba:b=b:xa : b = b : xx=b2ax = \tfrac{b^2}{a}
Mean proportional between a,ba, ba:x=x:ba : x = x : bx=abx = \sqrt{ab}

Example 5 · Proportionals

Find the fourth proportional to 8, 12 and 18, and the mean proportional between 8 and 18.

  1. Fourth proportional: 12×18÷8=2712 \times 18 \div 8 = 27.

  2. Mean proportional: 8×18=144=12\sqrt{8 \times 18} = \sqrt{144} = 12.

Answer

27 and 12

Watch out

The mean proportional is not the average. The average of 8 and 18 is 13, a common wrong option.

Exam shortcut

Three numbers are in continued proportion when a:b=b:ca : b = b : c, so b2=acb^2 = ac. Then (a+b):(b+c)=a:b(a + b) : (b + c) = a : b and a:c=a2:b2a : c = a^2 : b^2.

What is the unitary method?

Find the value of one unit first, then scale up. If 15 pens cost ₹255, one pen costs ₹17, so 22 pens cost ₹374. It is the safest way through any direct proportion, and it never adds where it should multiply.

  • On a map of scale 1:50,0001 : 50{,}000, 1 cm stands for 50,000 cm, which is 0.5 km, so 7 cm stands for 3.5 km.
  • With a limiting ingredient, work out what each ingredient allows and take the smaller. A recipe with rice and dal in 3:13 : 1 can use at most 1.2 kg of rice if you have only 400 g of dal, however much rice you own.

Variation

What is the difference between direct and inverse variation?

In direct variation the ratio is constant: y=kxy = kx, and when one doubles, so does the other. In inverse variation the product is constant: y=kxy = \tfrac{k}{x}, and when one doubles, the other halves.

Direct: ratio constantInverse: product constant
Cost and quantity boughtWorkers and days for a fixed job
Distance and petrol usedSpeed and time for a fixed distance
Wages and days workedPeople and days a food stock lasts

Example 6 · Inverse variation

The time to cook rice for a function varies inversely with the number of cookers. Four cookers take 45 minutes. How long do 6 cookers take?

  1. The product is fixed: 4×45=1804 \times 45 = 180 cooker-minutes.

  2. Six cookers: 180÷6=30180 \div 6 = 30 minutes.

Answer

30 minutes

Exam shortcut

Ask one question: if this goes up, does the other go up or down? Up means direct, down means inverse. Variation can also be with a square: a plate with 1.5 times the diameter has 1.52=2.251.5^2 = 2.25 times the area. For joint variation such as y∝xz2y \propto \tfrac{x}{z^2}, write y=kxz2y = \tfrac{kx}{z^2}, find kk, then substitute.

How do you solve men-days-food and work questions?

Treat the job, or the food stock, as a fixed total of person-days, then divide by the new number of people. Men times days times hours, divided by the work, stays constant. If something changes partway through, subtract the part already used first.

Work and people

M1×D1×H1W1=M2×D2×H2W2\frac{M_1 \times D_1 \times H_1}{W_1} = \frac{M_2 \times D_2 \times H_2}{W_2}

Example 7 · Rations after people leave

A relief camp has rations for 300 people for 40 days. After 10 days, 60 people leave. How long will the rest of the rations last?

  1. Rations left: 300×30=9,000300 \times 30 = 9{,}000 person-days.

  2. People now: 300−60=240300 - 60 = 240.

  3. Days: 9,000÷240=37.59{,}000 \div 240 = 37.5.

Answer

37.5 days

Key idea

With both size and time, use the whole formula. Ten workers who build 50 m of drain in 6 days need 10×6÷50=1.210 \times 6 \div 50 = 1.2 worker-days a metre, so 90 m in 9 days needs 90×1.2÷9=1290 \times 1.2 \div 9 = 12 workers.

Partnership

How is profit shared in a partnership?

Profit is shared in the ratio of capital times time for each partner. If everyone stays for the same time, use the capital ratio; if the capital is the same, use the time ratio.

  • A partner who joins after mm months has money in for 12−m12 - m months.
  • A partner who leaves or adds money partway through has two blocks: capital times months for each.
  • A working partner's salary is paid out first, and only the rest is shared. Their total is the salary plus their share.

Example 8 · A late partner

Rekha starts a shop with ₹48,000. After 3 months Dinesh joins with ₹64,000. The year's profit is ₹42,000. How is it shared?

  1. Rekha: 48,000×12=5,76,00048{,}000 \times 12 = 5{,}76{,}000.

  2. Dinesh: 64,000×9=5,76,00064{,}000 \times 9 = 5{,}76{,}000.

  3. The ratio is 1:11 : 1, so each gets half.

Answer

₹21,000 each

Exam shortcut

To work backwards, divide: capital is proportional to profit divided by time. If profits are 3:43 : 4 and times 3:23 : 2, the capitals are 33:42=1:2\tfrac{3}{3} : \tfrac{4}{2} = 1 : 2.

Exam shortcuts

  • Work in parts. Find one part, then read off every share.
  • Check with the total. The shares must add back to the amount.
  • Equal products, equal shares. In a partnership, compute each capital times time early.
  • Person-days. One multiplication and one division solve most men-days-food questions.
  • Direction first. Decide direct or inverse before you calculate.

Common mistakes

  • Mixed units. Minutes against hours, paise against rupees, map centimetres against kilometres.
  • The wrong order. "A to B" is not "B to A".
  • Answering the wrong quantity. Final water instead of water added, present age instead of age in 4 years.
  • Adding instead of multiplying. Proportion scales by a factor.
  • Direct for inverse. More workers means fewer days.
  • Forgetting the part already done in work and food questions.
  • Ignoring time in a partnership.
  • Forgetting the salary of a working partner.
  • The average as the mean proportional.
  • Fractions in a ratio. 12:13:14\tfrac{1}{2} : \tfrac{1}{3} : \tfrac{1}{4} is 6:4:36 : 4 : 3.

Quick revision

Ratios

  • Simplify by the HCF, same units first
  • Compare by cross-multiplying
  • One part =Ta+b+c= \tfrac{T}{a + b + c}
  • Combine: make the common term equal

Proportion

  • a:b::c:da : b :: c : d means ad=bcad = bc
  • Fourth bca\tfrac{bc}{a}, third b2a\tfrac{b^2}{a}, mean ab\sqrt{ab}
  • Continued: b2=acb^2 = ac

Variation and work

  • Direct: ratio constant. Inverse: product constant
  • M1D1H1W1=M2D2H2W2\tfrac{M_1 D_1 H_1}{W_1} = \tfrac{M_2 D_2 H_2}{W_2}
  • Subtract what was used before a change

Partnership

  • Share in capital × time
  • Joins after mm months: 12−m12 - m months
  • Salary first, then share the rest

Mixing liquids at different strengths is worked in mixtures and alligation, rates of work in time and work, and age ratios in ages and number problems.

Next · 08Quick revision

Check your understanding

67 questions, grouped by type, easy to hard. Pick an answer and check it. The worked solution opens when you ask for it.

Ratios and sharingQ1 of 67Q1

Ratios and sharing

25 questions

An amount of ₹3,150 is shared between three people in the ratio 2:3:42 : 3 : 4. How much does the second person receive?

Options for question 1

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AnswerC · ₹1,050

  1. The ratio has 2+3+4=92 + 3 + 4 = 9 parts in total.

  2. One part is worth 3,150÷9=3503{,}150 \div 9 = 350.

  3. The second person has 3 parts, so receives 3×350=1,0503 \times 350 = 1{,}050.

  4. Check: 700+1,050+1,400=3,150700 + 1{,}050 + 1{,}400 = 3{,}150.

A school has 84 girls and 126 boys in Class 11. What is the ratio of girls to boys in its simplest form?

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AnswerD · 2:32 : 3

  1. Girls : boys = 84:12684 : 126.

  2. The HCF of 84 and 126 is 42, so divide both terms by 42: 84:126=2:384 : 126 = 2 : 3.

Worth noting

The order matters: girls come first, so 3:23 : 2 is the ratio of boys to girls.

Meenakshi spends 45 minutes on her commute and 2 hours on homework every day. What is the ratio of her commute time to her homework time?

Options for question 3

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AnswerD · 3:83 : 8

  1. Put both quantities in the same unit: 2 hours = 120 minutes.

  2. Ratio = 45:12045 : 120. Divide by 15: 3:83 : 8.

Worth noting

A ratio compares like with like. Writing 45:245 : 2 mixes minutes with hours; using 1 hour instead of 2 gives 3:43 : 4.

Which of the following ratios is the greatest?

Options for question 4

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AnswerD · 7:117 : 11

  1. Write each ratio as a decimal: 35=0.6\frac{3}{5} = 0.6, 47≈0.571\frac{4}{7} \approx 0.571, 58=0.625\frac{5}{8} = 0.625, 711≈0.636\frac{7}{11} \approx 0.636.

  2. The largest value is 0.636, so 7:117 : 11 is the greatest.

Worth noting

To compare two ratios quickly, cross-multiply: 7:117 : 11 vs 5:85 : 8 gives 7×8=567 \times 8 = 56 against 5×11=555 \times 11 = 55, so 7:117 : 11 is larger.

Aarav and Fatima share a prize of ₹2,400 in the ratio 5:35 : 3. How much does Fatima get?

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AnswerB · ₹900

  1. Total parts = 5+3=85 + 3 = 8, so one part = ₹2,400 ÷ 8 = ₹300.

  2. Fatima gets 3 parts = 3 × ₹300 = ₹900.

Worth noting

₹1,500 is Aarav's share. ₹1,440 comes from dividing by 5 instead of by the total 8 parts.

If a:b=2:3a : b = 2 : 3 and b:c=4:5b : c = 4 : 5, what is a:ca : c?

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AnswerD · 8:158 : 15

  1. ac=ab×bc=23×45=815\frac{a}{c} = \frac{a}{b} \times \frac{b}{c} = \frac{2}{3} \times \frac{4}{5} = \frac{8}{15}.

  2. So a:c=8:15a : c = 8 : 15.

Worth noting

Simply joining the outer numbers gives 2:52 : 5, which ignores that b has different values in the two ratios.

In a hostel mess the ratio of vegetarians to non-vegetarians is 7:57 : 5. If 35 residents are non-vegetarian, how many are vegetarian?

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AnswerC · 49

  1. 5 parts = 35, so 1 part = 7.

  2. Vegetarians = 7 parts = 7×7=497 \times 7 = 49.

Worth noting

84 is the total number of residents, and 25 comes from turning the ratio upside down.

Two numbers are in the ratio 4:94 : 9 and their sum is 195. What is the larger number?

Options for question 8

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AnswerD · 135

  1. Total parts = 4+9=134 + 9 = 13, so one part = 195÷13=15195 \div 13 = 15.

  2. Larger number = 9×15=1359 \times 15 = 135.

Worth noting

60 is the smaller number and 75 is their difference.

What is the compound ratio of 2:32 : 3 and 9:109 : 10?

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AnswerD · 3:53 : 5

  1. Compound ratio = product of the first terms : product of the second terms = (2×9):(3×10)(2 \times 9) : (3 \times 10).

  2. 18:30=3:518 : 30 = 3 : 5.

Worth noting

Adding the terms gives 11:1311 : 13, and cross-multiplying gives 20:2720 : 27; neither is a compound ratio.

The angles of a triangle are in the ratio 2:3:72 : 3 : 7. What is the largest angle?

Options for question 10

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AnswerC · 105°

  1. The angles add up to 180°. Total parts = 2+3+7=122 + 3 + 7 = 12, so one part = 15°.

  2. Largest angle = 7×15∘=105∘7 \times 15^\circ = 105^\circ.

Worth noting

30° and 45° are the other two angles; 126° comes from taking one part as 18°.

A cricket academy has batters and bowlers in the ratio 3:53 : 5. After 9 new batters join, the ratio becomes 3:43 : 4. How many batters does the academy have now?

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AnswerB · 45

  1. Let the batters be 3x and the bowlers 5x. The bowlers do not change.

  2. 3x+95x=34\frac{3x + 9}{5x} = \frac{3}{4} gives 12x+36=15x12x + 36 = 15x, so x=12x = 12.

  3. Batters now = 3×12+9=453 \times 12 + 9 = 45.

Worth noting

36 is the number of batters before the new players joined; 60 is the number of bowlers.

A money box contains ₹1, ₹2 and ₹5 coins in the ratio 5:3:25 : 3 : 2 by number. The total value of the coins is ₹210. How many ₹2 coins are there?

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AnswerB · 30

  1. Take the coins as 5x, 3x and 2x.

  2. Value = 1×5x+2×3x+5×2x=21x1 \times 5x + 2 \times 3x + 5 \times 2x = 21x rupees.

  3. 21x=21021x = 210 gives x=10x = 10, so ₹2 coins = 3×10=303 \times 10 = 30.

Worth noting

60 is the VALUE of the ₹2 coins in rupees, not their number; 63 comes from splitting ₹210 in the ratio 5:3:25 : 3 : 2 directly.

A piggy bank holds 50-paise, ₹1 and ₹2 coins in the ratio 6:3:26 : 3 : 2 by number. The coins are worth ₹150 in all. How many 50-paise coins are in the piggy bank?

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AnswerD · 90

  1. Take the coins as 6x, 3x and 2x.

  2. Value in rupees = 0.5×6x+1×3x+2×2x=3x+3x+4x=10x0.5 \times 6x + 1 \times 3x + 2 \times 2x = 3x + 3x + 4x = 10x.

  3. 10x=15010x = 150 gives x=15x = 15, so 50-paise coins = 6×15=906 \times 15 = 90.

Worth noting

45 is the value of the 50-paise coins in rupees. Always convert paise to rupees before adding values.

The monthly salaries of Ravi and Joseph are in the ratio 3:43 : 4, and those of Joseph and Harpreet are in the ratio 6:56 : 5. Together the three earn ₹77,500 a month. What is Harpreet's salary?

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AnswerB · ₹25,000

  1. Make Joseph's term equal: 3:4=9:123 : 4 = 9 : 12 and 6:5=12:106 : 5 = 12 : 10.

  2. Ravi : Joseph : Harpreet = 9:12:109 : 12 : 10, a total of 31 parts.

  3. One part = ₹77,500 ÷ 31 = ₹2,500, so Harpreet earns 10 × ₹2,500 = ₹25,000.

Worth noting

₹22,500 is Ravi's salary and ₹30,000 is Joseph's.

A container has 40 litres of a mixture of milk and water in the ratio 3:13 : 1. How many litres of water must be added to make the ratio of milk to water 5:35 : 3?

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AnswerA · 8

  1. Milk = 30 litres and water = 10 litres. The milk stays the same.

  2. For milk : water = 5:35 : 3, water must be 30×3÷5=1830 \times 3 \div 5 = 18 litres.

  3. Water to add = 18−10=818 - 10 = 8 litres.

Worth noting

18 litres is the water needed in the final mixture, not the amount to add.

₹5,200 is divided among Priya, Kabir and Ananya in the ratio 12:13:14\frac{1}{2} : \frac{1}{3} : \frac{1}{4}. How much does Priya get?

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AnswerC · ₹2,400

  1. Multiply each fraction by the LCM 12: 12:13:14=6:4:3\frac{1}{2} : \frac{1}{3} : \frac{1}{4} = 6 : 4 : 3.

  2. Total parts = 13, so one part = ₹5,200 ÷ 13 = ₹400.

  3. Priya gets 6 × ₹400 = ₹2,400.

Worth noting

₹1,200 is Ananya's share. Clear the fractions first; never treat 1/2:1/3:1/41/2 : 1/3 : 1/4 as 2:3:42 : 3 : 4.

In a class the ratio of boys to girls is 4:54 : 5. After 8 boys move to another section, the ratio becomes 2:32 : 3. How many girls are in the class?

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AnswerC · 60

  1. Let boys = 4x and girls = 5x.

  2. 4x−85x=23\frac{4x - 8}{5x} = \frac{2}{3} gives 12x−24=10x12x - 24 = 10x, so x=12x = 12.

  3. Girls = 5×12=605 \times 12 = 60.

Worth noting

48 is the original number of boys and 40 is the number left after the transfer.

The ratio of Zoya's marks to Nikhil's marks was 5:85 : 8. Zoya's marks then rose by 20% and Nikhil's fell by 25%. What is the new ratio of Zoya's marks to Nikhil's?

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AnswerD · 1:11 : 1

  1. Take Zoya = 5 and Nikhil = 8.

  2. Zoya's new marks = 5×1.2=65 \times 1.2 = 6; Nikhil's new marks = 8×0.75=68 \times 0.75 = 6.

  3. New ratio = 6:6=1:16 : 6 = 1 : 1.

Worth noting

Treating Nikhil's change as a 25% rise gives 6:10=3:56 : 10 = 3 : 5.

₹1,460 is shared among Kiran, Lata and Mohan. Kiran gets ₹60 more than Lata, and the ratio of Lata's share to Mohan's share is 2:32 : 3. How much does Kiran get?

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AnswerB · ₹460

  1. Let Lata = 2k and Mohan = 3k; then Kiran = 2k+602k + 60.

  2. 2k+60+2k+3k=1,4602k + 60 + 2k + 3k = 1{,}460 gives 7k=1,4007k = 1{,}400, so k=200k = 200.

  3. Kiran = 2×200+602 \times 200 + 60 = ₹460.

Worth noting

₹400 is Lata's share and ₹600 is Mohan's.

Can P holds 24 litres of a drink with juice and water in the ratio 5:35 : 3. Can Q holds 36 litres with juice and water in the ratio 1:21 : 2. Both cans are emptied into one tank. What is the ratio of juice to water in the tank?

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AnswerD · 9:119 : 11

  1. Can P: juice = 24×5/8=1524 \times 5/8 = 15 L, water = 9 L.

  2. Can Q: juice = 36×1/3=1236 \times 1/3 = 12 L, water = 24 L.

  3. Tank: juice = 27 L, water = 33 L, so the ratio is 27:33=9:1127 : 33 = 9 : 11.

Worth noting

Adding the ratio terms, (5+1):(3+2)=6:5(5 + 1) : (3 + 2) = 6 : 5, is wrong because the cans hold different amounts.

The monthly incomes of Anjali and Bhavesh are in the ratio 5:45 : 4 and their monthly expenses are in the ratio 3:23 : 2. Each of them saves ₹8,000 a month. What is Anjali's monthly income?

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AnswerC · ₹20,000

  1. Let incomes be 5x and 4x, expenses 3y and 2y.

  2. Savings: 5x−3y=8,0005x - 3y = 8{,}000 and 4x−2y=8,0004x - 2y = 8{,}000.

  3. From the second, y=2x−4,000y = 2x - 4{,}000. Substituting: 5x−6x+12,000=8,0005x - 6x + 12{,}000 = 8{,}000, so x=4,000x = 4{,}000.

  4. Anjali's income = 5×4,0005 \times 4{,}000 = ₹20,000.

Worth noting

₹16,000 is Bhavesh's income and ₹12,000 is Anjali's expense (y=4,000y = 4{,}000, so 3y=12,0003y = 12{,}000).

If A:B=2:3A : B = 2 : 3, B:C=4:5B : C = 4 : 5 and C:D=6:7C : D = 6 : 7, what is A:DA : D?

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AnswerD · 16:3516 : 35

  1. AD=AB×BC×CD=23×45×67\frac{A}{D} = \frac{A}{B} \times \frac{B}{C} \times \frac{C}{D} = \frac{2}{3} \times \frac{4}{5} \times \frac{6}{7}.

  2. =48105=1635= \frac{48}{105} = \frac{16}{35}.

  3. So A:D=16:35A : D = 16 : 35.

Worth noting

8:158 : 15 is A:CA : C, where students stop one ratio too early; 2:72 : 7 just joins the outer numbers.

A charity box holds ₹1, ₹2 and ₹5 coins. The total VALUES of the three kinds of coin are in the ratio 3:4:53 : 4 : 5, and the box holds ₹360 in all. How many ₹2 coins are in the box?

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AnswerB · 60

  1. Split the value: ₹360 in the ratio 3:4:53 : 4 : 5 gives ₹90, ₹120 and ₹150.

  2. Number of coins = value ÷ face value: 90÷1=9090 \div 1 = 90, 120÷2=60120 \div 2 = 60, 150÷5=30150 \div 5 = 30.

  3. So there are 60 coins of ₹2.

Worth noting

The ratio is of VALUES, not of numbers. Treating 3:4:53 : 4 : 5 as the number of coins gives 40; 120 is the value of the ₹2 coins.

The numbers of students in three sections of a coaching centre are in the ratio 3:4:53 : 4 : 5. The sections grow by 20%, 25% and 40% respectively. What is the new ratio of students in the three sections?

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AnswerA · 18:25:3518 : 25 : 35

  1. New terms: 3×1.2=3.63 \times 1.2 = 3.6, 4×1.25=54 \times 1.25 = 5, 5×1.4=75 \times 1.4 = 7.

  2. 3.6:5:73.6 : 5 : 7. Multiply by 5 to clear the decimal: 18:25:3518 : 25 : 35.

Worth noting

Adding the percentages to the ratio terms (3+203 + 20, 4+254 + 25, 5+405 + 40) gives 23:29:4523 : 29 : 45, which has no meaning.

The present ages of Ishaan and his mother are in the ratio 2:72 : 7. Six years ago the ratio was 1:51 : 5. How old will his mother be 4 years from now?

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AnswerC · 60

  1. Let the present ages be 2x and 7x.

  2. 2x−67x−6=15\frac{2x - 6}{7x - 6} = \frac{1}{5} gives 10x−30=7x−610x - 30 = 7x - 6, so x=8x = 8.

  3. Mother's present age = 56, so in 4 years she will be 60.

Worth noting

56 is her age now; the question asks for her age 4 years from now.

Proportion

14 questions

What is the fourth proportional to 6, 9 and 14?

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AnswerB · 21

  1. If x is the fourth proportional, then 6:9=14:x6 : 9 = 14 : x.

  2. x=9×146=1266=21x = \frac{9 \times 14}{6} = \frac{126}{6} = 21.

Worth noting

17 comes from adding the difference 3 to 14; proportion is about multiplying, not adding.

What is the third proportional to 4 and 10?

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AnswerC · 25

  1. The third proportional x satisfies 4:10=10:x4 : 10 = 10 : x.

  2. x=10×104=25x = \frac{10 \times 10}{4} = 25.

Worth noting

40 is simply 4×104 \times 10; 16 comes from adding the difference 6 to 10.

What is the mean proportional between 9 and 25?

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AnswerA · 15

  1. The mean proportional of a and b is ab\sqrt{ab}.

  2. 9×25=225=15\sqrt{9 \times 25} = \sqrt{225} = 15.

Worth noting

17 is the ordinary average of 9 and 25, and 225 is their product before taking the square root.

Twelve notebooks cost ₹324. At the same rate, what do 20 notebooks cost?

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AnswerB · ₹540

  1. Cost of one notebook = ₹324 ÷ 12 = ₹27.

  2. Cost of 20 notebooks = 20 × ₹27 = ₹540.

Worth noting

₹648 is the cost of 24 notebooks (double 12), not 20.

Gurpreet's car runs 234 km on 13 litres of petrol. How far will it run on 20 litres?

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AnswerB · 360 km

  1. Distance per litre = 234÷13=18234 \div 13 = 18 km.

  2. On 20 litres: 20×18=36020 \times 18 = 360 km.

Worth noting

468 km is the distance on 26 litres; 351 km treats 20 litres as 1.5 times 13 litres.

A map is drawn to the scale 1:2,50,0001 : 2{,}50{,}000. Two towns are 6.4 cm apart on the map. What is the actual distance between them?

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AnswerB · 16 km

  1. Actual distance = 6.4×2,50,0006.4 \times 2{,}50{,}000 cm = 16,00,000 cm.

  2. 1 km = 1,00,000 cm, so the distance = 16,00,000÷1,00,000=1616{,}00{,}000 \div 1{,}00{,}000 = 16 km.

Worth noting

The scale is in centimetres. Dividing by 10,000 (as if 1 km were 10,000 cm) gives 160 km.

What number must be subtracted from each of 23, 30, 57 and 78 so that the four results are in proportion?

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AnswerC · 6

  1. Let the number be x. Then (23−x)(78−x)=(30−x)(57−x)(23 - x)(78 - x) = (30 - x)(57 - x) (product of extremes = product of means).

  2. 1794−101x+x2=1710−87x+x21794 - 101x + x^2 = 1710 - 87x + x^2, so 84=14x84 = 14x and x=6x = 6.

  3. Check: 17:2417 : 24 and 51:7251 : 72 are both 17:2417 : 24.

Worth noting

Always check by substituting: with 6 the numbers become 17, 24, 51, 72, and 17×72=24×51=1,22417 \times 72 = 24 \times 51 = 1{,}224.

What is the ratio of the fourth proportional to 4, 7 and 20 to the mean proportional between 7 and 28?

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AnswerD · 5:25 : 2

  1. Fourth proportional to 4, 7, 20: 7×204=35\frac{7 \times 20}{4} = 35.

  2. Mean proportional between 7 and 28: 7×28=196=14\sqrt{7 \times 28} = \sqrt{196} = 14.

  3. Required ratio = 35:14=5:235 : 14 = 5 : 2.

Worth noting

The question asks for the fourth proportional first, so the ratio is 35:1435 : 14, not 14:3514 : 35.

An office printer prints 1,080 pages in 45 minutes. At the same rate, how long will it take to print 1,800 pages?

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AnswerC · 1 hour 15 minutes

  1. Pages per minute = 1,080÷45=241{,}080 \div 45 = 24.

  2. Time for 1,800 pages = 1,800÷24=751{,}800 \div 24 = 75 minutes.

  3. 75 minutes = 1 hour 15 minutes.

Worth noting

Writing 75 minutes as '1.75 hours' or '1 hour 25 minutes' is a conversion slip: 75 minutes is 1¼ hours.

A cake recipe uses flour and sugar in the ratio 5:25 : 2 by weight. Sunita has 900 g of flour and 300 g of sugar. If she keeps the ratio exact, what is the most flour she can use?

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AnswerB · 750 g

  1. Using all 900 g of flour would need 900×2/5=360900 \times 2/5 = 360 g of sugar, but she has only 300 g.

  2. So sugar is the limit: flour = 300×5/2=750300 \times 5/2 = 750 g.

Worth noting

900 g ignores that the sugar runs out first; check which ingredient is the limiting one.

Eight metres of cloth cost ₹1,240. How many metres of the same cloth can be bought for ₹2,015?

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AnswerC · 13 m

  1. Cost of 1 metre = ₹1,240 ÷ 8 = ₹155.

  2. Metres for ₹2,015 = 2,015÷155=132{,}015 \div 155 = 13.

Worth noting

Check the answer: 13 × ₹155 = ₹2,015 exactly.

A 250 ml bottle of juice costs ₹30 and a 1.5 litre bottle of the same juice costs ₹160. How much more does it cost to buy 3 litres in 250 ml bottles than in 1.5 litre bottles?

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AnswerB · ₹40

  1. 3 litres = 3,000 ml = 12 small bottles, costing 12 × ₹30 = ₹360.

  2. 3 litres = 2 large bottles, costing 2 × ₹160 = ₹320.

  3. Extra cost = ₹360 − ₹320 = ₹40.

Worth noting

₹20 is the extra cost for only 1.5 litres; ₹200 subtracts the price of one large bottle from 3 litres of small bottles.

Three positive numbers a, b, c are in continued proportion, with a=12a = 12 and c=75c = 75. What is (a+b):(b+c)(a + b) : (b + c)?

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AnswerA · 2:52 : 5

  1. Continued proportion means a:b=b:ca : b = b : c, so b2=ac=12×75=900b^2 = ac = 12 \times 75 = 900 and b=30b = 30.

  2. (a+b):(b+c)=42:105=2:5(a + b) : (b + c) = 42 : 105 = 2 : 5.

Worth noting

Shortcut: in continued proportion, (a+b):(b+c)(a + b) : (b + c) always equals a:ba : b, here 12:30=2:512 : 30 = 2 : 5. 4:254 : 25 is a:ca : c.

The mean proportional between (x−2)(x - 2) and (x+7)(x + 7) is 6. If x is positive, what is x?

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AnswerB · 5

  1. (x−2)(x+7)=62=36(x - 2)(x + 7) = 6^2 = 36.

  2. x2+5x−14=36x^2 + 5x - 14 = 36, so x2+5x−50=0x^2 + 5x - 50 = 0.

  3. (x+10)(x−5)=0(x + 10)(x - 5) = 0, so x=5x = 5 (x must be positive).

  4. Check: the numbers are 3 and 12, and √(3×12)=6(3 \times 12) = 6.

Worth noting

10 comes from a sign slip in the factors; forgetting to square 6 leads to a different, non-factorable equation.

Direct and inverse variation

14 questions

y varies directly as x, and y=12y = 12 when x=4x = 4. What is y when x=11x = 11?

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AnswerB · 33

  1. y=kxy = kx with 12=4k12 = 4k, so k=3k = 3.

  2. When x=11x = 11, y=3×11=33y = 3 \times 11 = 33.

Worth noting

19 comes from adding 7 (the increase in x) to 12; direct variation multiplies, it does not add.

Eight painters can paint a school building in 15 days. How many days will 12 painters take, working at the same rate?

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AnswerA · 10

  1. More painters means fewer days, so this is inverse variation: painters × days stays constant.

  2. 8×15=1208 \times 15 = 120 painter-days, so 12 painters need 120÷12=10120 \div 12 = 10 days.

Worth noting

22.5 treats it as direct variation (15×12÷8)(15 \times 12 \div 8).

x varies inversely as y, and x=9x = 9 when y=4y = 4. What is x when y=6y = 6?

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AnswerB · 6

  1. xy=kxy = k, so k=9×4=36k = 9 \times 4 = 36.

  2. When y=6y = 6, x=36÷6=6x = 36 \div 6 = 6.

Worth noting

13.5 is what direct variation would give; in inverse variation, when y grows x must shrink.

A bus travelling at 48 km/h takes 5 hours for a journey. How long will the same journey take at 60 km/h?

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AnswerA · 4 hours

  1. For a fixed distance, speed × time is constant: distance = 48×5=24048 \times 5 = 240 km.

  2. Time at 60 km/h=240÷60=4h = 240 \div 60 = 4 hours.

Worth noting

6.25 hours comes from treating time as directly proportional to speed.

The stretch of a spring varies directly as the load hung on it. A 5 kg load stretches the spring by 3.5 cm. What load will stretch it by 9.8 cm?

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AnswerC · 14 kg

  1. Stretch = k × load, so k=3.55=0.7k = \frac{3.5}{5} = 0.7 cm per kg.

  2. Load = 9.80.7=14\frac{9.8}{0.7} = 14 kg.

Worth noting

11.3 kg adds the extra 6.3 cm to the load; 6.86 kg multiplies by 0.7 instead of dividing.

A school camp has food for 120 students for 25 days. After 5 days, 40 more students join. For how many more days will the remaining food last?

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AnswerB · 15

  1. After 5 days the food left would feed 120 students for 20 days = 120×20=2,400120 \times 20 = 2{,}400 student-days.

  2. Now there are 160 students, so it lasts 2,400÷160=152{,}400 \div 160 = 15 more days.

Worth noting

18.75 forgets the 5 days already used (120×25÷160)(120 \times 25 \div 160).

Twelve workers, working 8 hours a day, finish laying a road in 15 days. How many days will 18 workers take for the same job if they work 10 hours a day?

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AnswerA · 8

  1. Total work = 12×8×15=1,44012 \times 8 \times 15 = 1{,}440 worker-hours.

  2. 18 workers × 10 hours = 180 worker-hours per day.

  3. Days = 1,440÷180=81{,}440 \div 180 = 8.

Worth noting

10 days ignores the change in daily hours; 28.125 treats every quantity as directly proportional.

A restaurant prices its round pizzas in direct proportion to their area. A pizza of diameter 20 cm costs ₹300. What does a pizza of diameter 30 cm cost?

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AnswerB · ₹675

  1. Area varies as the square of the diameter.

  2. Price ratio = (3020)2=94\left(\frac{30}{20}\right)^2 = \frac{9}{4}.

  3. Price = ₹300 × 9/49/4 = ₹675.

Worth noting

₹450 scales by the diameter instead of the area; ₹1,012.50 cubes the ratio.

Six identical pumps can empty a tank in 14 hours. After they have run for 4 hours, 2 pumps break down. How many more hours will the remaining pumps take to empty the tank?

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AnswerC · 15

  1. The whole job = 6×14=846 \times 14 = 84 pump-hours. In 4 hours, 6×4=246 \times 4 = 24 pump-hours are done.

  2. Work left = 60 pump-hours, shared by 4 pumps: 60÷4=1560 \div 4 = 15 hours.

Worth noting

21 hours is how long 4 pumps would take for the WHOLE tank; the first 4 hours of work are already done.

A water tanker service has enough supply for 250 families for 36 days. How many families must be taken off the list so that the same supply lasts 45 days?

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AnswerB · 50

  1. Families × days is constant: 250×36=9,000250 \times 36 = 9{,}000 family-days.

  2. Families for 45 days = 9,000÷45=2009{,}000 \div 45 = 200.

  3. Families to remove = 250−200=50250 - 200 = 50.

Worth noting

200 is how many families remain, not how many must be removed.

The brightness of a lamp varies inversely as the square of the distance from it. At 2 m the brightness is 45 units. What is it at 3 m?

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AnswerA · 20 units

  1. B×d2B \times d^2 is constant: 45×22=18045 \times 2^2 = 180.

  2. At 3 m: B=180÷32=180÷9=20B = 180 \div 3^2 = 180 \div 9 = 20 units.

Worth noting

30 units forgets the square (45×2÷3)(45 \times 2 \div 3); the other two values treat brightness as rising with distance.

Twenty workers can build a 240 m long boundary wall in 18 days. How many workers are needed to build a 400 m wall of the same kind in 15 days?

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AnswerC · 40

  1. Work per metre = (20×18)÷240=1.5(20 \times 18) \div 240 = 1.5 worker-days.

  2. A 400 m wall needs 400×1.5=600400 \times 1.5 = 600 worker-days.

  3. In 15 days: 600÷15=40600 \div 15 = 40 workers.

Worth noting

24 ignores the longer wall (20×18÷15)(20 \times 18 \div 15); 34 rounds up 33.3, which ignores the shorter time.

Fifteen masons can finish a job in 24 days. They work together for 8 days, and then 5 of them leave. In how many more days will the rest finish the job?

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AnswerB · 24

  1. Whole job = 15×24=36015 \times 24 = 360 mason-days. After 8 days, 15×8=12015 \times 8 = 120 are done, leaving 240.

  2. 10 masons remain, so they need 240÷10=24240 \div 10 = 24 more days.

Worth noting

16 is the time left if all 15 had stayed; 36 is how long 10 masons would take for the whole job.

y varies directly as x and inversely as the square of z. When x=5x = 5 and z=2z = 2, y=10y = 10. What is y when x=12x = 12 and z=4z = 4?

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AnswerA · 6

  1. y=kxz2y = \frac{kx}{z^2}, so 10=5k410 = \frac{5k}{4} and k=8k = 8.

  2. When x=12x = 12 and z=4z = 4: y=8×1216=6y = \frac{8 \times 12}{16} = 6.

Worth noting

12 forgets to square z; 24 ignores z altogether.

Partnership

14 questions

Deepa and Farhan start a tuition centre with ₹40,000 and ₹60,000 respectively and run it together for a year. The year's profit is ₹15,000. What is Farhan's share?

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AnswerC · ₹9,000

  1. For the same period, profit is shared in the ratio of capital: 40,000:60,000=2:340{,}000 : 60{,}000 = 2 : 3.

  2. Farhan's share = ₹15,000 × 3/53/5 = ₹9,000.

Worth noting

₹6,000 is Deepa's share, and ₹7,500 is an equal split, which ignores the different capitals.

Rohan invests ₹50,000 in a business for 12 months and Sneha invests ₹50,000 in it for 8 months. The profit is ₹25,000. What is Sneha's share?

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AnswerA · ₹10,000

  1. The capitals are equal, so profit is shared in the ratio of time: 12:8=3:212 : 8 = 3 : 2.

  2. Sneha's share = ₹25,000 × 2/52/5 = ₹10,000.

Worth noting

₹15,000 is Rohan's share; ₹12,500 splits equally, forgetting that Sneha's money was in for less time.

Three friends start a food stall with ₹12,000, ₹18,000 and ₹30,000 for the same period. They make a profit of ₹9,000. What is the smallest share?

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AnswerA · ₹1,800

  1. Capital ratio = 12,000:18,000:30,000=2:3:512{,}000 : 18{,}000 : 30{,}000 = 2 : 3 : 5, a total of 10 parts.

  2. Smallest share = ₹9,000 × 2/102/10 = ₹1,800.

Worth noting

₹3,000 is an equal three-way split; ₹4,500 is the largest share.

In a partnership for a fixed period, Anand invested ₹36,000. His share of a ₹12,000 profit was ₹4,800. How much did his partner invest for the same period?

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AnswerB · ₹54,000

  1. Anand's share : partner's share = 4,800:7,200=2:34{,}800 : 7{,}200 = 2 : 3.

  2. Capitals are in the same ratio, so partner's capital = ₹36,000 × 3/23/2 = ₹54,000.

Worth noting

₹90,000 is the total capital; ₹24,000 comes from using 2/32/3 instead of 3/23/2.

Vikram invests ₹25,000 for 12 months and Lakshmi invests ₹30,000 for 10 months. In what ratio should they share the profit?

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AnswerD · 1:11 : 1

  1. Profit ratio = capital × time.

  2. Vikram: 25,000×12=3,00,00025{,}000 \times 12 = 3{,}00{,}000. Lakshmi: 30,000×10=3,00,00030{,}000 \times 10 = 3{,}00{,}000.

  3. Ratio = 3,00,000:3,00,000=1:13{,}00{,}000 : 3{,}00{,}000 = 1 : 1.

Worth noting

5:65 : 6 uses capital alone and 6:56 : 5 uses time alone; profit depends on both.

Nandini starts a business with ₹60,000. After 4 months Kabir joins her with ₹90,000. At the end of the year the profit is ₹34,000. What is Kabir's share?

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AnswerC · ₹17,000

  1. Nandini: 60,000×12=7,20,00060{,}000 \times 12 = 7{,}20{,}000. Kabir: 90,000×8=7,20,00090{,}000 \times 8 = 7{,}20{,}000.

  2. The ratio is 1:11 : 1, so Kabir gets ₹34,000 ÷ 2 = ₹17,000.

Worth noting

₹20,400 splits by capital alone (3/53/5 of ₹34,000), forgetting that Kabir's money was in for only 8 months.

Asha, Bilal and Chitra invest ₹20,000, ₹30,000 and ₹40,000 in a business. After 6 months Chitra withdraws her capital. The year's profit is ₹56,000. What is Chitra's share?

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AnswerA · ₹16,000

  1. Capital × months: Asha 20,000×12=2,40,00020{,}000 \times 12 = 2{,}40{,}000; Bilal 30,000×12=3,60,00030{,}000 \times 12 = 3{,}60{,}000; Chitra 40,000×6=2,40,00040{,}000 \times 6 = 2{,}40{,}000.

  2. Ratio = 2:3:22 : 3 : 2, a total of 7 parts.

  3. Chitra's share = ₹56,000 × 2/72/7 = ₹16,000.

Worth noting

₹24,889 (approximately) comes from using capital alone; ₹24,000 is Bilal's share.

Meera and Tenzin invest ₹1,00,000 and ₹1,50,000 in a café. Meera runs the café and takes 10% of the profit as her salary; the rest is shared in the ratio of their capitals. The profit is ₹80,000. How much does Meera receive in all?

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AnswerC · ₹36,800

  1. Meera's salary = 10% of ₹80,000 = ₹8,000. Profit left = ₹72,000.

  2. Capital ratio = 1,00,000:1,50,000=2:31{,}00{,}000 : 1{,}50{,}000 = 2 : 3, so Meera's share = ₹72,000 × 2/52/5 = ₹28,800.

  3. Meera's total = ₹8,000 + ₹28,800 = ₹36,800.

Worth noting

₹28,800 forgets to add her salary; ₹32,000 ignores the salary and splits the whole profit.

Arjun invests ₹15,000 for 12 months, Bindu invests ₹20,000 for 9 months and Charan invests ₹25,000 for 6 months. The total profit is ₹34,000. What is Arjun's share?

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AnswerD · ₹12,000

  1. Capital × months: 15,000×12=1,80,00015{,}000 \times 12 = 1{,}80{,}000; 20,000×9=1,80,00020{,}000 \times 9 = 1{,}80{,}000; 25,000×6=1,50,00025{,}000 \times 6 = 1{,}50{,}000.

  2. Ratio = 6:6:56 : 6 : 5, a total of 17 parts; one part = ₹2,000.

  3. Arjun's share = 6 × ₹2,000 = ₹12,000.

Worth noting

₹8,500 comes from using capital alone (15/6015/60 of the profit); ₹10,000 is Charan's share.

Harsh starts a business with ₹30,000. Some months later Pooja joins with ₹45,000. At the end of the year they share the profit equally. After how many months did Pooja join?

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AnswerA · 4

  1. Equal shares mean equal capital × time: 30,000×12=45,000×t30{,}000 \times 12 = 45{,}000 \times t.

  2. t=3,60,000÷45,000=8t = 3{,}60{,}000 \div 45{,}000 = 8, so Pooja's money was in for 8 months.

  3. She joined after 12−8=412 - 8 = 4 months.

Worth noting

8 is how long Pooja's money stayed in the business, not when she joined.

Two partners share profit in the ratio 5:35 : 3. Their capitals were invested for periods in the ratio 2:32 : 3. What is the ratio of their capitals?

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AnswerA · 5:25 : 2

  1. Profit ∝ capital × time, so capital ∝ profit ÷ time.

  2. Capital ratio = 52:33=52:1=5:2\frac{5}{2} : \frac{3}{3} = \frac{5}{2} : 1 = 5 : 2.

Worth noting

10:910 : 9 multiplies profit by time instead of dividing.

Kavya invests ₹40,000 in a business and adds ₹20,000 more after 6 months. Irfan invests ₹75,000 for the whole year. The year's profit is ₹45,000. What is Kavya's share?

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AnswerA · ₹18,000

  1. Kavya: 40,000×6+60,000×6=2,40,000+3,60,000=6,00,00040{,}000 \times 6 + 60{,}000 \times 6 = 2{,}40{,}000 + 3{,}60{,}000 = 6{,}00{,}000.

  2. Irfan: 75,000×12=9,00,00075{,}000 \times 12 = 9{,}00{,}000. Ratio = 6:9=2:36 : 9 = 2 : 3.

  3. Kavya's share = ₹45,000 × 2/52/5 = ₹18,000.

Worth noting

₹20,000 counts Kavya's ₹60,000 for the whole year; ₹27,000 is Irfan's share.

Ali, Bina and Charu start a business with capitals in the ratio 2:3:42 : 3 : 4. After 3 months Ali doubles his capital, and after 6 months Bina withdraws half of hers. The year's profit is ₹78,000. What is Charu's share?

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AnswerC · ₹32,000

  1. Take the capitals as 2, 3 and 4 units.

  2. Ali: 2×3+4×9=422 \times 3 + 4 \times 9 = 42. Bina: 3×6+1.5×6=273 \times 6 + 1.5 \times 6 = 27. Charu: 4×12=484 \times 12 = 48.

  3. Ratio = 42:27:48=14:9:1642 : 27 : 48 = 14 : 9 : 16, a total of 39 parts; one part = ₹2,000.

  4. Charu's share = 16 × ₹2,000 = ₹32,000.

Worth noting

₹34,667 (approximately) uses the starting ratio 2:3:42 : 3 : 4 and ignores the changes; ₹28,000 is Ali's share.

Salim invests ₹2,40,000 in a shop but takes no part in running it. Priyanka invests ₹1,60,000 and manages the shop, for which she is paid ₹5,000 a month out of the profit. The rest of the profit is shared in the ratio of capitals. The year's profit is ₹1,50,000. How much does Priyanka receive in all?

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AnswerD · ₹96,000

  1. Priyanka's salary for the year = 12 × ₹5,000 = ₹60,000. Profit left = ₹90,000.

  2. Capital ratio = 2,40,000:1,60,000=3:22{,}40{,}000 : 1{,}60{,}000 = 3 : 2, so her share = ₹90,000 × 2/52/5 = ₹36,000.

  3. Priyanka's total = ₹60,000 + ₹36,000 = ₹96,000.

Worth noting

₹63,000 counts the salary for only one month; ₹36,000 forgets the salary altogether.

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