Mixture questions look as if they are about rice, tea, milk and acid, but they are about one idea: a mixture's value is a weighted average of its ingredients. Alligation is a fast way to find the weights, and repeated replacement is multiplying by the same fraction again and again. This lesson covers the alligation rule, mean prices, solutions and water, averages, profits and speeds, mixtures sold at a profit, replacement, and combining mixtures, with worked examples and traps.
A mixture's value, whether a price per kg or a strength in percent, is a weighted average of its ingredients, weighted by how much of each goes in. Every question in this chapter is that one idea seen from a different side.
If you know the amounts and want the mixture's value, multiply, add and divide. If you know the mixture's value and want the amounts, use alligation. And if liquid is drawn out and replaced again and again, multiply by the fraction kept each time.
It gives the ratio in which two ingredients must be mixed to reach a given mean value. With the cheaper value c, the dearer value d and the mean m between them, the cheaper part to the dearer part is (d−m):(m−c).
Alligation
Cheaper:Dearer=(d−m):(m−c)
Each ingredient's share is the gap on the other side: the cheaper one gets d − m, the dearer one gets m − c.
Watch out
Swapping the two gaps is the commonest slip. Say it to yourself: the cheaper one gets the dearer side's gap. And the mean must lie between c and d; if it does not, a profit or loss is hidden in the price, or something has gone wrong.
Around the mean, the gains and losses must balance. Mixing x kg at price c with y kg at price d to get price m means x(m−c)=y(d−m), which rearranges to x:y=(d−m):(m−c).
Key idea
The balance gives a quick check: the mean sits nearer the ingredient there is more of. A mean of ₹46 between ₹42 and ₹54 is much nearer ₹42, so there must be more of the ₹42 rice.
Treat each solution's strength, its percentage of acid, sugar, milk or alcohol, exactly like a price. The two strengths are the two values, and the target strength is the mean.
Example 2 · Two syrups
In what ratio should a 15% sugar syrup and a 45% syrup be mixed to get a 25% syrup?
15% part to 45% part: (45−25):(25−15)=20:10=2:1.
Check: 2 litres at 15% and 1 litre at 45% hold 0.3+0.45=0.75 litres of sugar in 3 litres, which is 25%.
Answer
2:1
Ingredient
Value to use
Pure water, in a price question
₹0 per litre
Pure water, in a strength question
0%
Pure acid, milk or juice
100%
Example 3 · Diluting with water
How much water must be added to 30 litres of a 40% salt solution to make it 25%?
Solution to water: (25−0):(40−25)=25:15=5:3.
5 parts are 30 litres, so 1 part is 6 litres and the water is 3×6=18 litres.
Yes. It works for any weighted average: average marks, salaries, interest rates, profit percentages, speeds. The only question is what the weights are, because the ratio you get is always a ratio of those weights.
Situation
The two values
The ratio you get is of
Class average
Boys' and girls' averages
Number of boys to girls
Profit on parts of a stock
The two profit percentages
The cost price of each part
Interest on two loans
The two rates
The two sums lent
Average speed
The two speeds
The two times, not distances
Example 4 · Two loans
Rafiq lends ₹20,000 in two parts at 6% and 11% simple interest and earns ₹1,600 in a year. How much did he lend at 6%?
Average rate: 20,0001,600×100=8%.
6% part to 11% part: (11−8):(8−6)=3:2.
Amount at 6%: 53×20,000=12,000.
Answer
₹12,000
Check: 720+880=1,600.
Losses and speeds
A loss is a negative profit. Sold partly at a 4% loss and partly at a 12% profit, the values are −4 and +12, so the gap from −4 up to a mean of +6 is 10, not 2.
Speeds give times, because average speed is total distance over total time. Averaging 50 km/h from 40 and 70 means time at 40 to time at 70 is (70−50):(50−40)=2:1. Multiply each time by its speed to get distances.
First turn the selling price into the cost price of the mixture, then use alligation on cost prices. Profit is on cost, so divide by 1+100profit, never multiply by 1−100profit.
Example 5 · Selling the mixture at a profit
A shopkeeper mixes pulses costing ₹80 and ₹110 a kg and sells the mixture at ₹108 a kg, making a 20% profit. Find the mixing ratio.
Cost of the mixture: 108÷1.2=90 rupees a kg.
Cheaper to dearer: (110−90):(90−80)=20:10=2:1.
Answer
2:1
Exam shortcut
A milkman who adds free water and sells at the cost price of milk gains water over milk, as a percentage. With milk to water 5:1 he gains 20%, because he pays for 5 litres and sells 6.
If a vessel holds V litres of a pure liquid, and each time x litres are drawn out and replaced with water, the liquid left after n operations is V(1−Vx)n. Each operation keeps the same fraction of whatever liquid is there.
Replacement
Liquid left=V(1−Vx)n
Example 6 · Three replacements
A 50-litre can is full of milk. 5 litres are drawn out and replaced with water, three times in all. How much milk is left?
Fraction kept each time: 45÷50=0.9.
Milk left: 50×0.93=50×0.729=36.45 litres.
Answer
36.45 litres of milk, and 13.55 litres of water
Subtracting 5 litres three times gives 35 litres, which is wrong: after the first draw, what comes out is partly water.
Exam shortcut
The formula works for a starting mixture too: apply it to the component that is drawn out and not put back. 40 litres of milk and water in 3:1 has 30 litres of milk, and after two replacements of 10 litres the milk is 30×0.752=16.875 litres.
Working backwards from a final ratio, the milk's fraction of the whole, not the milk-to-water ratio, equals (1−Vx)n.
Hold the ingredient you are not adding fixed and rebuild the total around it. Adding water or letting it evaporate keeps the solute fixed; adding milk to milk and water keeps the water fixed.
36 litres of milk and water in 7:2 has 28 litres of milk and 8 of water. For 7:4 the milk stays at 28, so the water must become 16: add 8 litres.
To strengthen by evaporation, new total = solute ÷ new strength, and the drop in total is the water lost.
Turn each mixture into actual quantities of each component, add, and simplify. Never add ratio terms unless the two mixtures have the same total.
Exam shortcut
To find the mixing ratio for a target, write one component as a fraction of each whole and use alligation on the fractions. Milk to water 1:1 is 21 milk and 5:1 is 65. For 3:1, which is 43: first to second is (65−43):(43−21)=121:41=1:3.
Kavya's grocery mixes rice costing ₹42 per kg with rice costing ₹54 per kg so that the mixture is worth ₹46 per kg. In what ratio (cheaper : dearer) must the two be mixed?
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AnswerD · 2:1
Cheaper share = dearer price − mean = 54−46=8.
Dearer share = mean − cheaper price = 46−42=4.
Cheaper : dearer = 8:4=2:1.
Worth noting
The difference on the dearer side belongs to the CHEAPER variety. Swapping them gives 1:2, the tempting slip.
A milkman buys milk at ₹60 per litre. In what ratio (water : milk) must he add water, which costs nothing, so that the mixture costs him ₹48 per litre?
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AnswerB · 1:4
Treat water as a liquid priced ₹0 per litre.
Water : milk = (60−48):(48−0)=12:48.
= 1:4.
Worth noting
4:1 is the reversed ratio — it would make the mixture mostly water.
Gurpreet mixes 2 kg of cashews at ₹900 per kg with 3 kg of a second variety. The mixture is worth ₹1,080 per kg. What is the price of the second variety per kg?
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AnswerC · ₹1,200
Cost of 5 kg of mixture = 5×1080=5400 rupees.
Cost of the 2 kg = 2×900=1800 rupees.
Second variety: 35400−1800=1200 rupees per kg.
Worth noting
₹1,260 comes from assuming the mean is the plain average, so the second price is 2×1,080−900.
A sports hostel has 30 students with an average weight of 48 kg and 20 students with an average weight of 58 kg. What is the average weight of all 50 students?
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AnswerB · 52 kg
Total weight = 30×48+20×58=1440+1160=2600 kg.
Average = 502600=52 kg.
Worth noting
53 kg is the simple average of 48 and 58, which ignores that the groups are of different sizes.
A café blends coffee beans costing ₹800 per kg with beans costing ₹500 per kg to make a blend worth ₹620 per kg. What is the ratio of the ₹800 beans to the ₹500 beans?
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AnswerB · 2:3
₹800 beans : ₹500 beans = (620−500):(800−620).
= 120:180=2:3.
Worth noting
3:2 reverses the ratio. The mean ₹620 is nearer ₹500, so there are more of the ₹500 beans.
Arjun sells 50 kg of rice, part of it at a 10% profit and the rest at a 25% profit. Overall he makes a 16% profit. How many kg did he sell at a 10% profit?
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AnswerC · 30 kg
Treat the profit percentages like prices: 10% and 25% around a mean of 16%.
10% part : 25% part = (25−16):(16−10)=9:6=3:2.
Quantity at 10%=53×50=30 kg.
Worth noting
20 kg is the quantity sold at 25% — it is what you get if the ratio is reversed.
Fatima mixes two teas costing ₹120 per kg and ₹150 per kg. She sells the mixture at ₹165 per kg and makes a 25% profit. In what ratio (cheaper : dearer) did she mix them?
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AnswerD · 3:2
Cost price of the mixture = 1.25165=132 rupees per kg.
Cheaper : dearer = (150−132):(132−120)=18:12.
= 3:2.
Worth noting
Taking the cost as 75% of ₹165 (₹123.75) is the common error — profit is on cost, so divide by 1.25. That error leads to 7:1.
A company has 120 employees with an average salary of ₹30,000 a month. Managers average ₹50,000 and all other employees average ₹25,000. How many managers are there?
Lalremsiami lends ₹12,000 in two parts, one at 8% simple interest a year and the other at 12% a year. Her total interest for one year is ₹1,140. How much did she lend at 8%?
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AnswerD · ₹7,500
Average rate = 120001140×100=9.5%.
8% part : 12% part = (12−9.5):(9.5−8)=2.5:1.5=5:3.
Amount at 8%=85×12000=7500 rupees.
Worth noting
₹4,500 is the amount at 12% (the ratio reversed). Check: 8% of 7,500+12% of 4,500=600+540 = ₹1,140.
Alloy P has copper and zinc in the ratio 3:1; alloy Q has them in the ratio 1:3. In what ratio must P and Q be melted together to get an alloy with copper and zinc in the ratio 5:3?
A shop has 30 litres of mustard oil at ₹150 per litre. How many litres of groundnut oil at ₹190 per litre must be mixed with it so that the blend costs ₹166 per litre?
Ramesh buys milk at ₹54 per litre, mixes water with it in the ratio milk : water = 4:1, and sells the mixture at 10% above ₹54 per litre. What is his profit percentage?
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AnswerD · 37.5%
Cost of 5 litres of mixture = cost of 4 litres of milk = 4×54=216 rupees, so ₹43.20 per litre.
The gains multiply, they do not add: 1.25 (from the free water) × 1.1 (from the higher price) = 1.375. Adding 25%+10% gives the tempting 35%, and 30% adds 10% to the 20% share of water in the mixture.
Deepa mixes 15 litres of a 40% sugar syrup with 10 litres of a second syrup. The mixture is 34% sugar. What is the sugar percentage of the second syrup?
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AnswerB · 25%
Sugar in the mixture = 0.34×25=8.5 litres.
Sugar from the first syrup = 0.40×15=6 litres.
Second syrup: 108.5−6=0.25, i.e. 25%.
Worth noting
28% assumes 34% is the simple average of the two strengths; the volumes are unequal. 10% divides the 2.5 litres of sugar by 25 litres instead of 10.
Shalini bought a phone and a tablet for ₹8,000 in all. She sold the phone at a 10% loss and the tablet at a 15% profit, and made a 5% profit overall. What did the phone cost her?
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AnswerB · ₹3,200
Write the loss as −10% and apply alligation to −10% and +15% around +5%.
Phone : tablet = (15−5) : (5−(−10))=10:15=2:3.
Phone = 52×8000=3200 rupees.
Worth noting
Check: −10% of 3,200=−320 and +15% of 4,800 = +720, net +400=5% of 8,000. ₹4,800 is the tablet's cost.
A milkman buys pure milk at ₹56 per litre. He adds water and sells the mixture at ₹60 per litre, making a profit of 25%. In what ratio (water : milk) is the mixture?
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AnswerC · 1:6
Cost price of the mixture = 1.2560=48 rupees per litre.
Water costs ₹0. Water : milk = (56−48):(48−0)=8:48.
= 1:6.
Worth noting
1:4 wrongly says 25% of the mixture's volume is water. 11:45 comes from taking cost as 75% of the selling price (₹45) instead of dividing by 1.25. 1:7 compares the ₹8 gap with ₹56 instead of ₹48.
Harish has 36 litres of a 30% acid solution. How many litres of pure acid must he add to raise the strength to 40%?
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AnswerC · 6 litres
Pure acid is a 100% solution.
Solution : pure acid = (100−40):(40−30)=60:10=6:1.
Pure acid = 636=6 litres.
Worth noting
Adding pure acid also increases the total volume. 3.6 litres simply takes 10% of 36; 4 litres makes the added acid 10% of the final volume, forgetting that the old acid already counts toward the 40%. Check: (10.8+6)÷42=40%.
Venkat sells 80 kg of onions. He sells some of them at a 5% loss (they were going soft) and the rest at a 15% profit. Overall he gains 9%. How many kg did he sell at a loss?
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AnswerA · 24 kg
Write the loss as −5%, and apply alligation to −5% and +15% around +9%.
Loss part : profit part = (15−9) : (9−(−5))=6:14=3:7.
Quantity sold at a loss = 103×80=24 kg.
Worth noting
Using +5% instead of −5% gives 6:4 and the wrong answer 48 kg. 56 kg is the quantity sold at a profit.
In a college quiz, the boys averaged 68 points and the girls averaged 78 points; the overall average was 72. There were 12 more boys than girls. How many students took the quiz?
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AnswerD · 60
Boys : girls = (78−72):(72−68)=6:4=3:2.
The difference of 3−2=1 part is 12 students.
Total = 5×12=60 students (36 boys and 24 girls).
Worth noting
36 and 24 are the boys and the girls separately. Check: 36×68+24×78=2,448+1,872=4,320=60×72.
When two teas are mixed in the ratio 3:2, the blend costs ₹176 per kg. When they are mixed in the ratio 2:3, the blend costs ₹184 per kg. What is the price per kg of the cheaper tea?
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AnswerA · ₹160
Let the prices be a (cheaper) and b. Then 3a+2b=5×176=880 and 2a+3b=5×184=920.
Adding: 5a+5b=1800, so a+b=360.
Subtracting: a−b=−40.
So a=160 and b=200; the cheaper tea costs ₹160 per kg.
Worth noting
₹180 is the average of the two blend prices — it equals the average of the two teas, not the cheaper one. ₹176 is just the first blend's price.
A bus covers 330 km in 6 hours. It travels part of the way at 40 km/h and the rest at 60 km/h. How many km does it travel at 40 km/h?
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AnswerA · 60 km
Average speed = 6330=55 km/h.
Time at 40 : time at 60=(60−55):(55−40)=5:15=1:3.
Time at 40 km/h = 41×6=1.5 hours.
Distance = 40×1.5=60 km.
Worth noting
With speeds, alligation gives the ratio of TIMES, because average speed is total distance ÷ total time. Applying 1:3 to the distance gives the wrong 82.5 km; 90 km uses 60 km/h for the 1.5 hours.
A tank holds a 40% sugar solution. Some of it is drained off and replaced with the same amount of a 16% sugar solution. The tank now holds a 25% solution. What fraction of the solution was replaced?
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AnswerD · 5/8
After replacement the tank is a mix of old 40% solution and new 16% solution, averaging 25%.
Old : new = (25−16):(40−25)=9:15=3:5.
Replaced fraction = 3+55=85.
Worth noting
3/8 is the fraction that stayed, and 3/5 is the ratio old : new read as a fraction. Check: 3/8×40+5/8×16=15+10=25.
A drum holds 80 litres of pure coconut oil. 8 litres are removed and replaced with a cheaper oil, and this is done three times in all. How much coconut oil is left in the drum?
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AnswerB · 58.32 litres
Each operation keeps 8080−8=0.9 of the coconut oil.
After three operations: 80×0.93=80×0.729=58.32 litres.
Worth noting
56 litres subtracts 8 litres three times, ignoring that later removals carry some cheaper oil. 64.8 litres stops after two operations.
A container is filled with 60 litres of pure milk. 12 litres are drawn out and replaced with water, and then this is repeated once. What is the ratio of milk to water now?
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AnswerD · 16:9
Each operation keeps 6048=54 of the milk.
Milk = 60×(54)2=38.4 litres; water = 60−38.4=21.6 litres.
Milk : water = 38.4:21.6=384:216=16:9.
Worth noting
Shortcut: milk fraction = (4/5)² = 16/25, so milk : water = 16:(25−16)=16:9. 3:2 comes from subtracting 12 litres of milk twice; 4:1 is the ratio after one operation.
Jar P has milk and water in the ratio 5:3, and jar Q has them in the ratio 7:1. In what ratio should the contents of P and Q be mixed to get milk and water in the ratio 2:1?
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AnswerC · 5:1
Milk fractions: P = 85, Q = 87, target = 32.
P:Q=(87−32):(32−85)=245:241.
= 5:1.
Worth noting
Write every mixture as the fraction of milk in the WHOLE before applying alligation. 1:5 is the reversed ratio; the target 2/3 is much nearer P's 5/8.
A vessel is full of pure milk. 9 litres are drawn out and replaced with water, and the operation is repeated once. The milk and water are now in the ratio 16:9. What is the capacity of the vessel?
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AnswerD · 45 litres
Milk fraction now = 16+916=2516.
So (1−C9)2=2516, giving 1−C9=54.
C9=51, so C=45 litres.
Worth noting
Take the square root of 16/25, not of 16:9 — the formula uses milk as a fraction of the WHOLE. Using 4:3 leads to 21 litres.
A 90-litre can holds milk and water in the ratio 7:2. Priya draws out 18 litres of the mixture and pours in 18 litres of water. What is the new ratio of milk to water?
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AnswerB · 28:17
At first: milk = 70 litres, water = 20 litres.
The 18 litres drawn out are in the ratio 7:2: milk 14 litres, water 4 litres.
Left: milk 56, water 16. After adding 18 litres of water: milk 56, water 34.
Milk : water = 56:34=28:17.
Worth noting
26:19 treats the 18 litres drawn out as pure milk; 28:19 forgets that 4 litres of water also left the can.
A chemist pours 12 litres of a solution with acid and water in the ratio 2:3 into 8 litres of a solution with acid and water in the ratio 4:1. What percentage of the combined solution is acid?
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AnswerB · 56%
Acid from the first = 52×12=4.8 litres.
Acid from the second = 54×8=6.4 litres.
Acid % = 204.8+6.4×100=2011.2×100=56%.
Worth noting
60% is the average of 40% and 80%, correct only for equal volumes. 64% swaps the volumes; 44% is the water percentage.
A tank holds 60 litres of a 40% acid solution. 15 litres are removed and replaced with 15 litres of an 80% acid solution. What is the strength of the solution now?
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AnswerC · 50%
Acid at first = 0.40×60=24 litres.
Removed: 0.40×15=6 litres of acid; added: 0.80×15=12 litres.
Acid now = 24−6+12=30 litres in 60 litres, i.e. 50%.
Worth noting
48% adds the 80% solution without removing the 15 litres first. 60% is the plain average of 40% and 80%, and 30% treats the added liquid as water.
A can holds 40 litres of pure juice. Some juice is drawn out and replaced with water, and the operation is repeated with the same amount. The can now has 25.6 litres of juice. How many litres were drawn out each time?
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AnswerA · 8 litres
40×(1−40x)2=25.6, so (1−40x)2=0.64.
1−40x=0.8, so 40x=0.2.
x=0.2×40=8 litres.
Worth noting
14.4 litres is the total juice lost (40−25.6), as if there were only one operation. 12.8 litres halves 25.6 instead of taking a square root.
A 50-litre mixture has milk and water in the ratio 3:2. By mistake, 10 litres of water are added. How much milk must now be added to bring the ratio back to 3:2?
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AnswerA · 15 litres
At first: milk 30 litres, water 20 litres. After the mistake: water 30 litres.
For 3:2, milk must be 23×30=45 litres.
Milk to add = 45−30=15 litres.
Worth noting
45 litres is the total milk needed, not the amount to add. Adding 10 litres of milk does not undo 10 litres of water, because the ratio is not 1:1.
Sunita pours 20 litres of a milk–water mixture in the ratio 3:1 and 30 litres of a milk–water mixture in the ratio 3:2 into one large pot. What is the ratio of milk to water in the pot?
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AnswerA · 33:17
First mixture: milk = 43×20=15, water = 5 litres.
Second mixture: milk = 53×30=18, water = 12 litres.
Total: milk 33, water 17, so milk : water = 33:17.
Worth noting
2:1 adds the ratio terms (3+3:1+2), which ignores the volumes. 69:31 swaps the two volumes.
A 60-litre mixture has milk and water in the ratio 4:1. How many litres of the mixture must be drawn off and replaced with water so that milk and water are in the ratio 1:1?
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AnswerD · 22.5 litres
Milk now = 48 litres. For 1:1 in 60 litres, milk must fall to 30 litres.
Drawing x litres removes the fraction 60x of the milk: 48(1−60x)=30.
1−60x=85, so x=60×83=22.5 litres.
Worth noting
18 litres (48−30) assumes the liquid drawn off is pure milk; it is four-fifths milk, so more must be drawn. Check: 22.5 litres carries 18 litres of milk away.
A drum holds 125 litres of pure milk. 25 litres are drawn out and replaced with water; this is done three times in all. What is the final ratio of milk to water?
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AnswerD · 64:61
Each operation keeps 125125−25=54 of the milk.
Milk after three operations = 125×(54)3=125×12564=64 litres.
Water = 125−64=61 litres, so milk : water = 64:61.
Worth noting
2:3 comes from subtracting 25 litres of milk three times (leaving 50 litres). 16:9 is the ratio after only two operations.
A 32-litre can is full of pure juice. Each time, 8 litres are drawn out and replaced with water. What is the fewest number of such operations after which juice makes up less than half of the can?
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AnswerB · 3
Each operation keeps 43 of the juice.
After 1 operation: 24 litres; after 2: 18 litres — still more than half of 32 (16 litres).
After 3 operations: 18×43=13.5 litres, which is less than 16.
Worth noting
Two operations would be the answer only if 8 litres of JUICE left each time (32−16=16). After the first operation the 8 litres drawn out are partly water.
Mixture A has milk and water in the ratio 3:1 and mixture B has them in the ratio 1:1. How many litres of A must be mixed with 18 litres of B to get a mixture with milk and water in the ratio 2:1?
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AnswerD · 36 litres
Milk fractions: A = 43, B = 21, target = 32.
A:B=(32−21):(43−32)=61:121=2:1.
A = 2×18=36 litres.
Worth noting
9 litres comes from reversing the ratio. Check: milk = 27+9=36, water = 9+9=18, and 36:18=2:1.
A 40-litre can holds milk and water in the ratio 3:1. Anil draws out 8 litres and replaces them with water, then does the same once more. What percentage of the can is now water?
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AnswerC · 52%
Milk at first = 43×40=30 litres.
Each operation keeps 4040−8=54 of the milk.
Milk left = 30×(54)2=19.2 litres, so water = 40−19.2=20.8 litres.
Water % = 4020.8×100=52%.
Worth noting
The formula applies to the milk even though the can did not start as pure milk. 48% is the milk percentage; 40% is the water after only one operation; 55% subtracts 6 litres of milk each time.
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