Profit, Loss and Discount for CUET General Aptitude
About 10 min to learn · 72 questions
Profit, loss and discount questions are percentages with a price tag attached. The arithmetic is easy; most marks are lost by dividing by the wrong base. This lesson covers cost, selling and marked price, profit and loss percentages, finding the cost from a percentage, overheads, equal selling prices, false weights, discounts, markup with discount, free-item offers and successive discounts, with worked examples and the traps beside them.
Profit, loss and discount are percentages with a price tag. What decides the answer is the base: profit and loss are percentages of the cost price, and a discount is a percentage of the marked price. Divide by the wrong one and you land on a planted option.
The second habit is to think in multipliers. A 15% profit is ×1.15 on the cost, a 12% discount is ×0.88 on the marked price, and a markup followed by a discount is one multiplier after another. When no rupee amounts are given, start from 100.
The cost price is what the seller pays, the selling price is what the buyer pays, and the marked price is the price on the tag before any discount. If the selling price is above the cost price, the seller makes a profit; below it, a loss.
Profit = SP − CP, when the SP is higher.
Loss = CP − SP, when the CP is higher.
Discount = MP − SP.
Key idea
Anything the seller spends to get the item ready to sell, such as transport, repairs, packing or stall rent, is an overhead, and it is added to the cost price.
Divide the profit or loss by the cost price and multiply by 100. Profit and loss percentages are on the cost price unless the question clearly says "on the selling price".
Profit and loss percentage
Profit %=CPprofit×100Loss %=CPloss×100
Example 1 · Profit percentage
Ishaan buys a guitar for ₹6,400 and sells it for ₹7,200. Find his profit percentage.
Profit: 7,200−6,400=800.
Profit %: 6,400800×100=12.5%.
Answer
12.5%
Dividing by ₹7,200 instead gives about 11.1%, which is wrong.
Use a multiplier. A profit of p% means SP = CP ×(1+100p), and a loss of l% means SP = CP ×(1−100l). To get from the SP back to the CP, divide by the same multiplier.
Situation
Multiplier on CP
CP from SP
20% profit
×1.20
÷1.20
15% profit
×1.15
÷1.15
8% loss
×0.92
÷0.92
25% loss
×0.75
÷0.75
Example 2 · Cost from selling price
Mariam sells a rug for ₹2,070 at a profit of 15%. What did it cost?
SP = 1.15× CP.
CP = 2,070÷1.15=1,800.
Answer
₹1,800
Taking 15% off ₹2,070 gives ₹1,759.50, which is wrong: the 15% was taken on the cost, not the selling price.
If both sell at the same price, one at x% profit and the other at x% loss, the seller always makes an overall loss of 100x2 percent. The item sold at a loss cost more, so the same percentage of it is a bigger amount.
Example 4 · Equal selling prices
Two lamps are sold for ₹1,800 each, one at 10% profit and one at 10% loss. Find the overall result.
CP of the first: 1,800÷1.1≈1,636.36. CP of the second: 1,800÷0.9=2,000.
Total CP is about ₹3,636.36 against a total SP of ₹3,600, a loss.
Loss %: 100102=1%.
Answer
A loss of 1%
Watch out
The shortcut works only when the two percentages are equal. For, say, 25% profit and 20% loss, find each cost separately and compare the totals.
Find the cost of one item and the selling price of one item, then compare them. Never compare the numbers of items directly.
Example 5 · Buying and selling in lots
Nandini buys pencils at 8 for ₹20 and sells them at 6 for ₹18. Find her profit percentage.
CP of one: 20÷8=2.50. SP of one: 18÷6=3.
Profit %: 2.500.50×100=20%.
Answer
20%
Exam shortcut
"The CP of m items equals the SP of n items": take each item's cost as ₹1, so n items cost ₹n and sell for ₹m. The profit is nm−n×100 percent. If the CP of 25 equals the SP of 20, the profit is 205=25%. Divide by n, the number actually sold.
Compare what the dealer actually gives with what he is paid for. The base is the quantity actually given: gain is the error divided by the true quantity given, times 100. A dealer who claims to sell at cost but gives 950 g for a kilogram gains 95050×100, about 5.26%.
Example 6 · False weight with a loss
A trader sells at 5% below cost and gives 900 g for every kilogram. Find his gain or loss.
He collects 0.95 times the cost of 1,000 g, which is the cost of 950 g.
He gives only 900 g.
Gain: 900950−900×100≈5.56%.
Answer
A gain of about 5.56%
He claims a loss but makes a gain.
Watch out
Combine a markup or a loss with a false weight by multiplying the two factors, not adding them. And divide by the weight actually given, not the weight claimed.
A discount is always a percentage of the marked price. After a discount of d%, the selling price is MP ×(1−100d), and the marked price is SP ÷(1−100d).
Example 7 · A discount
A cricket bat marked at ₹2,800 is sold at a 15% discount. Find the selling price.
Multiply the markup factor by the discount factor and compare the result with 1. Taking the cost as ₹100 makes it quick.
Example 8 · Markup, then discount
A shop marks goods 30% above cost and gives a 15% discount. Find the profit percentage.
Take CP = 100. Then MP = 130.
SP: 130×0.85=110.50.
Profit: 10.5%.
Answer
10.5%
The tempting 30−15=15% is wrong, because the 15% is taken on 130, not on 100.
Exam shortcut
To find the markup needed for a target profit, divide the target selling price by the discount factor. For a 10% profit after a 12% discount: MP = 110÷0.88=125, so mark 25% above cost.
If all the items cost the same, the customer gets x+y items and pays for x, so the effective discount is x+yy×100 percent.
Offer
Received
Paid for
Effective discount
Buy 1 get 1
2
1
50%
Buy 2 get 1
3
2
3331%
Buy 4 get 1
5
4
20%
Buy 5 get 3
8
5
37.5%
Watch out
Divide the free items by all the items received, not by the items paid for: buy 3 get 1 is 25% off, not 3331%. If the free item has a different price, use values: the free item's value over the total value received.
Successive discounts apply one after another, each on the price left by the one before. They are never simply added. Two discounts of a% and b% equal a single discount of a+b−100ab percent, and the order does not matter.
Two successive discounts
Single discount=a+b−100ab
Example 9 · Combining discounts
Find the single discount equal to successive discounts of 30% and 10%.
30+10−10030×10=37.
Check: 0.7×0.9=0.63 is paid, so 37% is taken off.
Answer
37%
Exam shortcut
For three discounts, multiply three factors: 10%, 20% and 25% leave 0.9×0.8×0.75=0.54 paid, a single discount of 46%.
Turn each scheme into the fraction of the marked price paid, and compare. The smaller fraction is better for the buyer, and the rupee gap is the difference between the fractions times the marked price.
A flat 40% leaves 0.60 paid, and 25% then 20% leaves 0.75×0.8=0.60. The schemes are equal.
A flat 35% leaves 0.65 paid, so it is worse for the buyer than 25% then 20%.
To find a missing discount, divide the final fraction paid by the ones you know: 0.63 paid after a first discount of 10% means 0.63÷0.9=0.7, a second discount of 30%.
The profit Deepa makes by selling a fan for ₹1,340 equals the loss she makes by selling it for ₹1,060. At what price should she sell it to make a 15% profit?
Show the explanationHide the explanation
AnswerC · ₹1,380
Profit = loss means the CP is exactly halfway between the two prices.
CP = 21340+1060=1200, that is ₹1,200.
SP for 15% profit = 1200×1.15 = ₹1,380.
Worth noting
₹1,200 is the cost price, not the answer. ₹1,541 wrongly adds 15% to ₹1,340.
A tea merchant buys 50 kg of tea at ₹360 per kg and pays ₹500 for transport. He sells all of it at ₹400 per kg. What is his profit percentage, correct to one decimal place?
Show the explanationHide the explanation
AnswerB · 8.1%
Total cost = 50 × ₹360 + ₹500 = ₹18,500.
Selling price = 50 × ₹400 = ₹20,000.
Profit = ₹1,500, so profit % = 185001500×100≈8.1%.
Worth noting
Transport is an overhead and goes into the CP. Leaving it out gives 11.1%. 7.5% divides by the SP.
A bakery sells a cake at a profit of 50%. The cost of making the cake rises by 20%, but the selling price stays the same. What is the new profit percentage?
Show the explanationHide the explanation
AnswerA · 25%
Take old CP = ₹100, so SP = ₹150.
New CP = ₹120, and SP is still ₹150.
New profit % = 12030×100=25%.
Worth noting
Subtracting 20 from 50 gives 30%, but the new profit must be divided by the NEW, higher cost.
Irfan buys two cycles for a total of ₹12,000. He sells one at a loss of 20% and the other at a gain of 20%, and both sell for the same price. What did the cycle sold at a loss cost him?
Show the explanationHide the explanation
AnswerD · ₹7,200
Let the loss-making cycle cost ₹x. The other costs ₹(12,000−x).
Same SP: 0.8x=1.2(12,000−x).
0.8x+1.2x=14,400, so 2x=14,400 and x=7,200.
Worth noting
Equal selling prices do not mean equal costs. The cycle sold at a loss must have cost more. ₹6,000 splits the money equally, and ₹5,760 is the common SP.
A grain dealer cheats at both ends. When buying, he takes 1,200 g for every kilogram he pays for. When selling, he gives only 800 g for every kilogram he charges for. He buys and sells at the same price per kilogram. What is his gain percentage?
Show the explanationHide the explanation
AnswerC · 50%
Say the rate is ₹1 per kg. For ₹1 he gets 1,200 g, so 1 g costs him ₹1/1200.
For 800 g he collects ₹1, but 800 g cost him 800/1200 = ₹2/3.
Gain % = 321−32×100=50%.
Worth noting
Adding 20%+20% gives 40%, and 1.2×1.2 gives 44%. The right factor is 1200÷800=1.5.
Sneha sells a microwave at a profit of 10%. Had she bought it for 10% less and sold it for ₹44 less, she would have made a profit of 20%. What is the cost price?
Show the explanationHide the explanation
AnswerB · ₹2,200
Let CP = ₹x. Actual SP = 1.1x.
New CP = 0.9x and new SP = 1.2×0.9x=1.08x.
The SP falls by 1.1x−1.08x=0.02x = ₹44.
x=44÷0.02 = ₹2,200.
Worth noting
₹2,420 is the actual selling price. ₹4,400 treats ₹44 as 1% of the CP.
A shopkeeper buys 200 eggs at ₹6 each and pays ₹60 to bring them to his shop. On the way, 20 eggs break. At what price must he sell each remaining egg to make a 20% profit on his total outlay?
Show the explanationHide the explanation
AnswerD · ₹8.40
Total cost = 200 × ₹6 + ₹60 = ₹1,260.
Required SP = 1.2 × ₹1,260 = ₹1,512.
Eggs left to sell = 200−20=180.
Price per egg = ₹1,512 ÷ 180 = ₹8.40.
Worth noting
₹7.56 spreads the takings over all 200 eggs, but the broken ones cannot be sold. ₹8.00 forgets the ₹60 transport cost.
Normally a bookseller sells at the marked price and earns 30% profit. During a book fair he gives a 10% discount. What is his profit percentage at the fair?
Show the explanationHide the explanation
AnswerA · 17%
Take CP = ₹100, so MP = ₹130.
Fair price = 90% of ₹130 = ₹117.
Profit = 17%.
Worth noting
30%−10%=20% is the trap. The discount is 10% of ₹130, which is ₹13, not ₹10.
A stationer gives one pen free with every 3 notebooks bought. A notebook is priced at ₹60 and a pen at ₹20. What is the effective discount percentage on the goods received?
The free item is cheaper than the items bought, so '1 in 4 free' (25%) does not apply. 1191% divides by the amount paid instead of the value received.
A shoe store offers 'buy 3 pairs, get 1 pair free' on pairs of the same price. It also takes an extra 10% off the bill. What is the effective discount on the pairs received?
Show the explanationHide the explanation
AnswerA · 32.5%
The customer takes 4 pairs and is billed for 3: the fraction paid is 3/4.
The extra 10% off leaves 90% of that bill.
Fraction paid = 43×0.9=0.675.
Effective discount = 1−0.675=32.5%.
Worth noting
Adding 25%+10%=35% overstates it. The extra 10% is taken on the reduced bill, not on the full value. 67.5% is the part paid, not the discount.
Store P offers a flat 30% off a cooler marked at ₹4,000. Store Q offers 20% off followed by a further 15% off on the same marked price. Which store is cheaper, and by how much?
Show the explanationHide the explanation
AnswerD · Store Q, by ₹80
Store P: 70% of ₹4,000 = ₹2,800.
Store Q: 0.8×0.85 × ₹4,000 = ₹2,720.
Store Q is cheaper by ₹2,800 − ₹2,720 = ₹80.
Worth noting
Store Q's two discounts work out to a single 32%, which beats a flat 30%. ₹200 treats Store Q's offer as 35%.
A festival sale advertises '25% off, plus an extra discount on the reduced price'. What must the extra discount be for the deal to equal a flat 35% off?
Show the explanationHide the explanation
AnswerC · 1331%
Flat 35% off means paying 0.65 of the MP.
After 25% off, the price is 0.75 of the MP.
Second fraction paid = 0.750.65=1513.
Extra discount = 1−1513=152=1331%.
Worth noting
10% (35%−25%) is too small, because it is taken on the reduced price. 25% then 10% gives only 32.5%.
A dealer buys a guitar for ₹1,000. He offers successive discounts of 20% and 10% on the marked price and still wants a profit of 8%. By what percentage above cost must he mark the guitar?
Show the explanationHide the explanation
AnswerD · 50%
Required SP = 1.08 × ₹1,000 = ₹1,080.
Fraction paid after both discounts = 0.8×0.9=0.72.
MP = ₹1,080 ÷ 0.72 = ₹1,500.
MP is ₹500 above cost, that is 50%.
Worth noting
38% (8%+20%+10%) is the trap, and 30% forgets the profit altogether. The discounts are on the MP, so divide the target SP by 0.72.
After three successive discounts, a customer pays 61.2% of the marked price of a dining table. The first two discounts are 20% and 15%. What is the third discount?
Show the explanationHide the explanation
AnswerC · 10%
After the first two discounts she would pay 0.8×0.85=0.68 of the MP.
Third fraction paid = 0.680.612=0.9.
Third discount = 1−0.9=10%.
Worth noting
3.8% comes from 38.8%−35%, which adds and subtracts the discounts instead of multiplying the fractions paid.
On an air fryer, one offer is a single 30% discount and another is successive discounts of 20% and 10%. The difference between the two selling prices is ₹72. What is the marked price?
Show the explanationHide the explanation
AnswerC · ₹3,600
Single 30%: pay 0.70 of MP.
20% then 10%: pay 0.8×0.9=0.72 of MP.
Difference = 0.02 of MP = ₹72.
MP = 72÷0.02 = ₹3,600.
Worth noting
₹7,200 assumes a 1% gap. ₹720 treats ₹72 as 10% of the MP.
The area names are NTA's. The chapters inside them are EduFarming's own division, not NTA's.