EduFarming
Your list · 0हिं

Type at least two letters. Press Esc to close.

↑↓ navigate↵ openTAB cycle filter

Profit, Loss and Discount for CUET General Aptitude

About 10 min to learn · 72 questions

Profit, loss and discount questions are percentages with a price tag attached. The arithmetic is easy; most marks are lost by dividing by the wrong base. This lesson covers cost, selling and marked price, profit and loss percentages, finding the cost from a percentage, overheads, equal selling prices, false weights, discounts, markup with discount, free-item offers and successive discounts, with worked examples and the traps beside them.

Syllabus area
General Mental Ability, Numerical Ability
On this page · 7 sections
  1. 01The core idea
  2. 02Profit and loss
  3. 03Discounts
  4. 04Exam shortcuts
  5. 05Common mistakes
  6. 06Quick revision
  7. 07Check your understanding

The core idea

Profit, loss and discount are percentages with a price tag. What decides the answer is the base: profit and loss are percentages of the cost price, and a discount is a percentage of the marked price. Divide by the wrong one and you land on a planted option.

The second habit is to think in multipliers. A 15% profit is ×1.15\times 1.15 on the cost, a 12% discount is ×0.88\times 0.88 on the marked price, and a markup followed by a discount is one multiplier after another. When no rupee amounts are given, start from 100.

Profit and loss

What do CP, SP, MP, profit and loss mean?

The cost price is what the seller pays, the selling price is what the buyer pays, and the marked price is the price on the tag before any discount. If the selling price is above the cost price, the seller makes a profit; below it, a loss.

  • Profit = SP − CP, when the SP is higher.
  • Loss = CP − SP, when the CP is higher.
  • Discount = MP − SP.

Key idea

Anything the seller spends to get the item ready to sell, such as transport, repairs, packing or stall rent, is an overhead, and it is added to the cost price.

How do you calculate profit percentage and loss percentage?

Divide the profit or loss by the cost price and multiply by 100. Profit and loss percentages are on the cost price unless the question clearly says "on the selling price".

Profit and loss percentage

Profit %=profitCP×100Loss %=lossCP×100\text{Profit \%} = \frac{\text{profit}}{\text{CP}} \times 100 \qquad \text{Loss \%} = \frac{\text{loss}}{\text{CP}} \times 100

Example 1 · Profit percentage

Ishaan buys a guitar for ₹6,400 and sells it for ₹7,200. Find his profit percentage.

  1. Profit: 7,200−6,400=8007{,}200 - 6{,}400 = 800.

  2. Profit %: 8006,400×100=12.5%\tfrac{800}{6{,}400} \times 100 = 12.5\%.

Answer

12.5%

Dividing by ₹7,200 instead gives about 11.1%, which is wrong.

How do you find the selling price or the cost price from a percentage?

Use a multiplier. A profit of p%p\% means SP = CP ×(1+p100)\times (1 + \tfrac{p}{100}), and a loss of l%l\% means SP = CP ×(1−l100)\times (1 - \tfrac{l}{100}). To get from the SP back to the CP, divide by the same multiplier.

SituationMultiplier on CPCP from SP
20% profit×1.20\times 1.20÷1.20\div 1.20
15% profit×1.15\times 1.15÷1.15\div 1.15
8% loss×0.92\times 0.92÷0.92\div 0.92
25% loss×0.75\times 0.75÷0.75\div 0.75

Example 2 · Cost from selling price

Mariam sells a rug for ₹2,070 at a profit of 15%. What did it cost?

  1. SP = 1.15×1.15 \times CP.

  2. CP = 2,070÷1.15=1,8002{,}070 \div 1.15 = 1{,}800.

Answer

₹1,800

Taking 15% off ₹2,070 gives ₹1,759.50, which is wrong: the 15% was taken on the cost, not the selling price.

How do overheads change the profit percentage?

Overheads raise the cost price, so they lower the profit percentage. Add every expense to the purchase price before you work out the profit.

Example 3 · Overheads

Ramesh buys a used motorbike for ₹27,000, spends ₹3,000 on tyres, and sells it for ₹33,600. Find his profit percentage.

  1. CP: 27,000+3,000=30,00027{,}000 + 3{,}000 = 30{,}000.

  2. Profit: 33,600−30,000=3,60033{,}600 - 30{,}000 = 3{,}600.

  3. Profit %: 3,60030,000×100=12%\tfrac{3{,}600}{30{,}000} \times 100 = 12\%.

Answer

12%

Leaving out the tyres gives about 24.4%, far too high.

What happens when two items are sold at the same price, one at a profit and one at a loss?

If both sell at the same price, one at x%x\% profit and the other at x%x\% loss, the seller always makes an overall loss of x2100\tfrac{x^2}{100} percent. The item sold at a loss cost more, so the same percentage of it is a bigger amount.

Example 4 · Equal selling prices

Two lamps are sold for ₹1,800 each, one at 10% profit and one at 10% loss. Find the overall result.

  1. CP of the first: 1,800÷1.1≈1,636.361{,}800 \div 1.1 \approx 1{,}636.36. CP of the second: 1,800÷0.9=2,0001{,}800 \div 0.9 = 2{,}000.

  2. Total CP is about ₹3,636.36 against a total SP of ₹3,600, a loss.

  3. Loss %: 102100=1%\tfrac{10^2}{100} = 1\%.

Answer

A loss of 1%

Watch out

The shortcut works only when the two percentages are equal. For, say, 25% profit and 20% loss, find each cost separately and compare the totals.

How do you solve "bought x for ₹a, sold y for ₹b" questions?

Find the cost of one item and the selling price of one item, then compare them. Never compare the numbers of items directly.

Example 5 · Buying and selling in lots

Nandini buys pencils at 8 for ₹20 and sells them at 6 for ₹18. Find her profit percentage.

  1. CP of one: 20÷8=2.5020 \div 8 = 2.50. SP of one: 18÷6=318 \div 6 = 3.

  2. Profit %: 0.502.50×100=20%\tfrac{0.50}{2.50} \times 100 = 20\%.

Answer

20%

Exam shortcut

"The CP of mm items equals the SP of nn items": take each item's cost as ₹1, so nn items cost ₹nn and sell for ₹mm. The profit is m−nn×100\tfrac{m - n}{n} \times 100 percent. If the CP of 25 equals the SP of 20, the profit is 520=25%\tfrac{5}{20} = 25\%. Divide by nn, the number actually sold.

How do you find the gain of a dishonest dealer who uses a false weight?

Compare what the dealer actually gives with what he is paid for. The base is the quantity actually given: gain is the error divided by the true quantity given, times 100. A dealer who claims to sell at cost but gives 950 g for a kilogram gains 50950×100\tfrac{50}{950} \times 100, about 5.26%.

Example 6 · False weight with a loss

A trader sells at 5% below cost and gives 900 g for every kilogram. Find his gain or loss.

  1. He collects 0.95 times the cost of 1,000 g, which is the cost of 950 g.

  2. He gives only 900 g.

  3. Gain: 950−900900×100≈5.56%\tfrac{950 - 900}{900} \times 100 \approx 5.56\%.

Answer

A gain of about 5.56%

He claims a loss but makes a gain.

Watch out

Combine a markup or a loss with a false weight by multiplying the two factors, not adding them. And divide by the weight actually given, not the weight claimed.

Discounts

What is marked price and how is discount calculated?

A discount is always a percentage of the marked price. After a discount of d%d\%, the selling price is MP ×(1−d100)\times (1 - \tfrac{d}{100}), and the marked price is SP ÷(1−d100)\div (1 - \tfrac{d}{100}).

Example 7 · A discount

A cricket bat marked at ₹2,800 is sold at a 15% discount. Find the selling price.

  1. SP: 2,800×0.85=2,3802{,}800 \times 0.85 = 2{,}380.

  2. The discount is 2,800−2,380=4202{,}800 - 2{,}380 = 420.

Answer

₹2,380

How do you find the profit when a trader marks up and then gives a discount?

Multiply the markup factor by the discount factor and compare the result with 1. Taking the cost as ₹100 makes it quick.

Example 8 · Markup, then discount

A shop marks goods 30% above cost and gives a 15% discount. Find the profit percentage.

  1. Take CP = 100. Then MP = 130.

  2. SP: 130×0.85=110.50130 \times 0.85 = 110.50.

  3. Profit: 10.5%.

Answer

10.5%

The tempting 30−15=15%30 - 15 = 15\% is wrong, because the 15% is taken on 130, not on 100.

Exam shortcut

To find the markup needed for a target profit, divide the target selling price by the discount factor. For a 10% profit after a 12% discount: MP = 110÷0.88=125110 \div 0.88 = 125, so mark 25% above cost.

How do "buy x, get y free" offers work as a discount?

If all the items cost the same, the customer gets x+yx + y items and pays for xx, so the effective discount is yx+y×100\tfrac{y}{x + y} \times 100 percent.

OfferReceivedPaid forEffective discount
Buy 1 get 12150%
Buy 2 get 1323313%33\tfrac{1}{3}\%
Buy 4 get 15420%
Buy 5 get 38537.5%

Watch out

Divide the free items by all the items received, not by the items paid for: buy 3 get 1 is 25% off, not 3313%33\tfrac{1}{3}\%. If the free item has a different price, use values: the free item's value over the total value received.

What is a successive discount and how do you combine two discounts into one?

Successive discounts apply one after another, each on the price left by the one before. They are never simply added. Two discounts of a%a\% and b%b\% equal a single discount of a+b−ab100a + b - \tfrac{ab}{100} percent, and the order does not matter.

Two successive discounts

Single discount=a+b−ab100\text{Single discount} = a + b - \frac{ab}{100}

Example 9 · Combining discounts

Find the single discount equal to successive discounts of 30% and 10%.

  1. 30+10−30×10100=3730 + 10 - \tfrac{30 \times 10}{100} = 37.

  2. Check: 0.7×0.9=0.630.7 \times 0.9 = 0.63 is paid, so 37% is taken off.

Answer

37%

Exam shortcut

For three discounts, multiply three factors: 10%, 20% and 25% leave 0.9×0.8×0.75=0.540.9 \times 0.8 \times 0.75 = 0.54 paid, a single discount of 46%.

How do you compare two discount schemes?

Turn each scheme into the fraction of the marked price paid, and compare. The smaller fraction is better for the buyer, and the rupee gap is the difference between the fractions times the marked price.

  • A flat 40% leaves 0.60 paid, and 25% then 20% leaves 0.75×0.8=0.600.75 \times 0.8 = 0.60. The schemes are equal.
  • A flat 35% leaves 0.65 paid, so it is worse for the buyer than 25% then 20%.
  • To find a missing discount, divide the final fraction paid by the ones you know: 0.63 paid after a first discount of 10% means 0.63÷0.9=0.70.63 \div 0.9 = 0.7, a second discount of 30%.

Exam shortcuts

  • Base 100. With no rupee values, take CP = 100, or MP = 100 for discount-only questions.
  • Profit equal to loss at two prices. The cost is exactly halfway between the two selling prices.
  • An extra ₹k changes the profit from p%p\% to q%q\%. Then (q−p)%(q - p)\% of the cost is ₹k.
  • Profit on the SP. r%r\% on the SP is r100−r×100%\tfrac{r}{100 - r} \times 100\% on the CP, so 20% on the SP is 25% on the CP.
  • Fractions. 16=1623%\tfrac{1}{6} = 16\tfrac{2}{3}\%, 18=12.5%\tfrac{1}{8} = 12.5\%, 19=1119%\tfrac{1}{9} = 11\tfrac{1}{9}\%, 112=813%\tfrac{1}{12} = 8\tfrac{1}{3}\%.

Common mistakes

  • Dividing the profit by the SP.
  • Taking a percentage off the SP to get the CP. Divide by the multiplier.
  • Forgetting overheads.
  • Adding successive discounts. 20% then 10% is 28%, not 30%.
  • Cancelling a markup against an equal discount. 1.2×0.8=0.961.2 \times 0.8 = 0.96, a 4% loss.
  • Thinking equal profit and loss percentages cancel. At the same SP they always give a loss.
  • The wrong base for a false weight.
  • "Paid for" as the base in a free-item offer.
  • Giving the MP when the SP is asked, or the other way round.

Quick revision

Profit and loss

  • Profit % and loss % on the CP
  • Profit p%p\%: SP = CP ×(1+p100)\times (1 + \tfrac{p}{100}). Back: divide
  • Overheads go into the CP
  • Same SP, x%x\% up and x%x\% down: loss x2100%\tfrac{x^2}{100}\%

Tricks of the trade

  • Lots: compare one item's CP and SP
  • CP of mm = SP of nn: profit m−nn×100%\tfrac{m - n}{n} \times 100\%
  • False weight: error ÷ weight given

Discounts

  • Discount on the MP. SP = MP ×(1−d100)\times (1 - \tfrac{d}{100})
  • Markup then discount: multiply the factors
  • Buy xx get yy: yx+y×100%\tfrac{y}{x + y} \times 100\%
  • Successive: a+b−ab100a + b - \tfrac{ab}{100}

The multiplier method comes from percentages, and mixtures sold at a profit are worked in mixtures and alligation.

Next · 06Quick revision

Check your understanding

72 questions, grouped by type, easy to hard. Pick an answer and check it. The worked solution opens when you ask for it.

Profit and lossQ1 of 72Q1

Profit and loss

31 questions

An article bought for ₹450 is sold for ₹540. What is the profit percentage?

Options for question 1

Show the explanationHide the explanation

AnswerC · 20%

  1. Profit is 540−450=90540 - 450 = 90.

  2. Profit percentage is measured on the cost price, so divide by 450.

  3. 90450=0.2\frac{90}{450} = 0.2, which is 20%.

Worth noting

Dividing by the selling price gives 90540≈16.67%\frac{90}{540} \approx 16.67\%. That is the profit margin, a different measure with a different base.

Kavya buys a second-hand bicycle for ₹2,400 and sells it for ₹2,760. What is her profit percentage?

Options for question 2

Show the explanationHide the explanation

AnswerB · 15%

  1. Profit = ₹2,760 − ₹2,400 = ₹360.

  2. Profit % = 3602400×100=15%\frac{360}{2400} \times 100 = 15\%.

Worth noting

Profit % is measured on the cost price. Dividing ₹360 by the selling price gives about 13%, which is not the profit percentage.

Harpreet buys a phone cover for ₹250. It does not sell, so she finally sells it for ₹210. What is the result of the deal?

Options for question 3

Show the explanationHide the explanation

AnswerA · Loss of 16%

  1. Loss = ₹250 − ₹210 = ₹40.

  2. Loss % = 40250×100=16%\frac{40}{250} \times 100 = 16\%.

Worth noting

₹40 is the loss in rupees, not the loss percentage, and 84% is the SP as a percentage of the CP. The base for loss % is the cost price, ₹250.

A tailor spends ₹840 on material for a kurta and wants a profit of 25%. At what price should he sell it?

Options for question 4

Show the explanationHide the explanation

AnswerC · ₹1,050

  1. SP = CP × (100 + profit %) ÷ 100=840×125100100 = 840 \times \frac{125}{100}.

  2. SP = ₹1,050.

Worth noting

₹1,120 comes from dividing 840 by 0.75, which mixes up the formula. Adding 25 rupees (₹865) confuses per cent with rupees.

Joseph sells a table lamp for ₹1,380 and makes a profit of 15%. What did the lamp cost him?

Options for question 5

Show the explanationHide the explanation

AnswerB · ₹1,200

  1. SP is 115% of CP.

  2. CP = 1380×100115=12001380 \times \frac{100}{115} = 1200.

Worth noting

Taking 15% off the selling price gives ₹1,173. That is wrong because the 15% is a percentage of the CP, not of the SP.

A dealer bought a water purifier for ₹3,500. It is an old model, and he has to sell it at a loss of 12%. What is the selling price?

Options for question 6

Show the explanationHide the explanation

AnswerA · ₹3,080

  1. SP = 3500×881003500 \times \frac{88}{100}.

  2. SP = ₹3,080.

Worth noting

₹3,920 is a 12% profit, not a loss. ₹3,488 subtracts 12 rupees instead of 12%.

Meenakshi sold a wooden chair for ₹1,530 and lost 10% on the deal. What was its cost price?

Options for question 7

Show the explanationHide the explanation

AnswerD · ₹1,700

  1. At a 10% loss, SP = 90% of CP.

  2. CP = 1530×10090=17001530 \times \frac{100}{90} = 1700.

Worth noting

Adding 10% of the selling price gives ₹1,683. That is wrong because the loss is 10% of the CP, which is larger than the SP.

Tenzin buys an old scooter for ₹18,000, spends ₹2,000 on repairs and sells it for ₹23,000. What is his profit percentage?

Options for question 8

Show the explanationHide the explanation

AnswerA · 15%

  1. Total cost = ₹18,000 + ₹2,000 = ₹20,000.

  2. Profit = ₹23,000 − ₹20,000 = ₹3,000.

  3. Profit % = 300020000×100=15%\frac{3000}{20000} \times 100 = 15\%.

Worth noting

Repair money is part of the cost price. Leaving it out of the base gives 1623%16\frac{2}{3}\%.

A fruit-seller buys bananas at ₹60 a dozen and sells them at ₹6 each. What is her profit percentage?

Options for question 9

Show the explanationHide the explanation

AnswerD · 20%

  1. SP of a dozen = 12 × ₹6 = ₹72.

  2. Profit on a dozen = ₹72 − ₹60 = ₹12.

  3. Profit % = 1260×100=20%\frac{12}{60} \times 100 = 20\%.

Worth noting

Dividing ₹12 by the selling price of ₹72 gives 1623%16\frac{2}{3}\%. The base must be the cost, ₹60.

Anjali sells a saree for ₹4,410 and makes a profit of ₹630. What is her profit percentage?

Options for question 10

Show the explanationHide the explanation

AnswerC · 1623%16\frac{2}{3}\%

  1. CP = ₹4,410 − ₹630 = ₹3,780.

  2. Profit % = 6303780×100=503=1623%\frac{630}{3780} \times 100 = \frac{50}{3} = 16\frac{2}{3}\%.

Worth noting

6304410=1427%\frac{630}{4410} = 14\frac{2}{7}\% is the profit as a percentage of the SP. The question wants it on the cost price.

A shopkeeper says he sells sugar at cost price, but he gives only 900 g every time a customer pays for 1 kg. What is his gain percentage?

Options for question 11

Show the explanationHide the explanation

AnswerC · 1119%11\frac{1}{9}\%

  1. For every 900 g he gives, he is paid the cost of 1,000 g.

  2. Gain = 100 g on a cost of 900 g.

  3. Gain % = 100900×100=1119%\frac{100}{900} \times 100 = 11\frac{1}{9}\%.

Worth noting

The base is what he actually gives (900 g), not the 1,000 g he claims. Dividing by 1,000 gives 10%.

Lalremsiami buys guavas at 9 for ₹45 and sells them at 5 for ₹32. What is her profit percentage?

Options for question 12

Show the explanationHide the explanation

AnswerD · 28%

  1. CP of one guava = ₹45 ÷ 9 = ₹5.

  2. SP of one guava = ₹32 ÷ 5 = ₹6.40.

  3. Profit % = 6.40−55×100=28%\frac{6.40 - 5}{5} \times 100 = 28\%.

Worth noting

Change both rates to the price of ONE guava before comparing. 21.875% is the profit divided by the SP instead of the CP.

A vendor buys 40 mangoes for ₹1,000. How many mangoes must he sell for ₹1,000 to make a profit of 25%?

Options for question 13

Show the explanationHide the explanation

AnswerB · 32

  1. CP of one mango = ₹1,000 ÷ 40 = ₹25.

  2. For 25% profit, SP of one mango = ₹25 × 1.25 = ₹31.25.

  3. Mangoes for ₹1,000 = 1000÷31.25=321000 \div 31.25 = 32.

Worth noting

Cutting the number of mangoes by 25% (to 30) does not give 25% profit. Work with the price of one mango.

Gurpreet sells two phones for ₹9,600 each. On one he makes a profit of 20% and on the other he makes a loss of 20%. What is his overall result?

Options for question 14

Show the explanationHide the explanation

AnswerA · Loss of ₹800

  1. CP of the first phone = 9600×100120=80009600 \times \frac{100}{120} = 8000, that is ₹8,000.

  2. CP of the second phone = 9600×10080=120009600 \times \frac{100}{80} = 12000, that is ₹12,000.

  3. Total CP = ₹20,000 and total SP = ₹19,200.

  4. Overall loss = ₹800 (4% of the total cost).

Worth noting

The 20% gain and the 20% loss do not cancel out. The loss is on the larger cost price, so the deal as a whole always ends in a loss.

A trader sells pulses at 10% below cost price, but his scale gives only 800 g when it shows 1 kg. What is his overall result?

Options for question 15

Show the explanationHide the explanation

AnswerA · Gain of 12.5%

  1. Cost of what he gives = cost of 800 g.

  2. He collects 90% of the cost of 1,000 g = the cost of 900 g.

  3. Gain = 900−800800×100=12.5%\frac{900 - 800}{800} \times 100 = 12.5\%.

Worth noting

The 10% loss is only on paper. The short weight more than makes up for it. Compare what he collects with what he actually hands over.

The cost price of 18 notebooks equals the selling price of 15 notebooks. What is the profit percentage?

Options for question 16

Show the explanationHide the explanation

AnswerB · 20%

  1. Let each notebook cost ₹1. Then 15 notebooks sell for ₹18.

  2. CP of 15 notebooks = ₹15, SP = ₹18, profit = ₹3.

  3. Profit % = 315×100=20%\frac{3}{15} \times 100 = 20\%.

Worth noting

Dividing the difference 3 by 18 gives 1623%16\frac{2}{3}\%. The profit must be compared with the cost of the SAME 15 notebooks.

The profit Deepa makes by selling a fan for ₹1,340 equals the loss she makes by selling it for ₹1,060. At what price should she sell it to make a 15% profit?

Options for question 17

Show the explanationHide the explanation

AnswerC · ₹1,380

  1. Profit = loss means the CP is exactly halfway between the two prices.

  2. CP = 1340+10602=1200\frac{1340 + 1060}{2} = 1200, that is ₹1,200.

  3. SP for 15% profit = 1200×1.151200 \times 1.15 = ₹1,380.

Worth noting

₹1,200 is the cost price, not the answer. ₹1,541 wrongly adds 15% to ₹1,340.

Selling a pressure cooker for ₹720 gives a loss of 10%. What selling price would give a profit of 15%?

Options for question 18

Show the explanationHide the explanation

AnswerD · ₹920

  1. CP = 720×10090=800720 \times \frac{100}{90} = 800, that is ₹800.

  2. SP for 15% profit = 800×1.15800 \times 1.15 = ₹920.

Worth noting

Going straight from ₹720 by 25% gives ₹900. This is wrong: both percentages are on the CP, so find the CP first.

Arjun sells a cupboard at a profit of 8%. If he had sold it for ₹120 more, his profit would have been 12%. What is the cost price?

Options for question 19

Show the explanationHide the explanation

AnswerC · ₹3,000

  1. The extra ₹120 raises the profit from 8% to 12% of CP.

  2. So 4% of CP = ₹120.

  3. CP = 1204×100=3000\frac{120}{4} \times 100 = 3000, that is ₹3,000.

Worth noting

₹1,000 treats ₹120 as 12% of CP, and ₹1,500 treats it as 8%. Only the 4-point difference matches the ₹120. ₹3,240 is the original SP.

A trader's profit is 20% of his selling price. What is his profit as a percentage of the cost price?

Options for question 20

Show the explanationHide the explanation

AnswerD · 25%

  1. Take SP = ₹100. Then profit = ₹20.

  2. CP = ₹100 − ₹20 = ₹80.

  3. Profit % on CP = 2080×100=25%\frac{20}{80} \times 100 = 25\%.

Worth noting

A profit that is 20% of the SP is always a bigger percentage of the CP, because the CP is smaller than the SP.

A tea merchant buys 50 kg of tea at ₹360 per kg and pays ₹500 for transport. He sells all of it at ₹400 per kg. What is his profit percentage, correct to one decimal place?

Options for question 21

Show the explanationHide the explanation

AnswerB · 8.1%

  1. Total cost = 50 × ₹360 + ₹500 = ₹18,500.

  2. Selling price = 50 × ₹400 = ₹20,000.

  3. Profit = ₹1,500, so profit % = 150018500×100≈8.1%\frac{1500}{18500} \times 100 \approx 8.1\%.

Worth noting

Transport is an overhead and goes into the CP. Leaving it out gives 11.1%. 7.5% divides by the SP.

Rahul buys a laptop for ₹32,000, spends ₹1,600 on repairs and ₹400 on delivery, and then sells it for ₹30,600. What is his loss percentage?

Options for question 22

Show the explanationHide the explanation

AnswerB · 10%

  1. Total cost = ₹32,000 + ₹1,600 + ₹400 = ₹34,000.

  2. Loss = ₹34,000 − ₹30,600 = ₹3,400.

  3. Loss % = 340034000×100=10%\frac{3400}{34000} \times 100 = 10\%.

Worth noting

4.375% ignores the repair and delivery costs. 1119%11\frac{1}{9}\% divides the loss by the SP.

By selling 36 packets of biscuits, a shopkeeper gains the selling price of 6 packets. What is his profit percentage?

Options for question 23

Show the explanationHide the explanation

AnswerC · 20%

  1. Profit = SP of 6 packets, so CP of 36 packets = SP of 36−6=3036 - 6 = 30 packets.

  2. Profit ÷ CP = SP of 6 ÷ SP of 30.

  3. Profit % = 630×100=20%\frac{6}{30} \times 100 = 20\%.

Worth noting

636=1623%\frac{6}{36} = 16\frac{2}{3}\% compares the profit with the SP, not the CP.

A bakery sells a cake at a profit of 50%. The cost of making the cake rises by 20%, but the selling price stays the same. What is the new profit percentage?

Options for question 24

Show the explanationHide the explanation

AnswerA · 25%

  1. Take old CP = ₹100, so SP = ₹150.

  2. New CP = ₹120, and SP is still ₹150.

  3. New profit % = 30120×100=25%\frac{30}{120} \times 100 = 25\%.

Worth noting

Subtracting 20 from 50 gives 30%, but the new profit must be divided by the NEW, higher cost.

Selling a school bag for ₹x gives a profit of 20%. What is the profit percentage if the bag is sold for ₹2x?

Options for question 25

Show the explanationHide the explanation

AnswerD · 140%

  1. Take CP = ₹100. Then x = ₹120.

  2. 2x = ₹240.

  3. Profit % = 240−100100×100=140%\frac{240 - 100}{100} \times 100 = 140\%.

Worth noting

Doubling the SP does not double the profit % (40%), nor leave it at 20%. The CP stays at ₹100, so the profit grows from ₹20 to ₹140.

Fatima sells two sewing machines for ₹3,000 each. She makes a profit of 25% on the first and a loss of 20% on the second. What is her overall result?

Options for question 26

Show the explanationHide the explanation

AnswerD · Loss of ₹150

  1. CP of the first = 3000×100125=24003000 \times \frac{100}{125} = 2400, that is ₹2,400.

  2. CP of the second = 3000×10080=37503000 \times \frac{100}{80} = 3750, that is ₹3,750.

  3. Total CP = ₹6,150 and total SP = ₹6,000.

  4. She makes an overall loss of ₹150.

Worth noting

Many students subtract (25%−20%=5%)(25\% - 20\% = 5\%) and pick a profit of ₹300. That fails because the two percentages are on different cost prices. Find each CP.

A spice dealer charges 20% above cost price, and he also uses a weight of 960 g in place of 1 kg. What is his actual gain percentage?

Options for question 27

Show the explanationHide the explanation

AnswerD · 25%

  1. For 960 g of spice (cost of 960 g), he charges 1.2 × the cost of 1,000 g.

  2. Gain factor = 1.2×1000960=1.25\frac{1.2 \times 1000}{960} = 1.25.

  3. Gain = 25%.

Worth noting

Adding 20% and 4% gives 24%, which is wrong. The two effects multiply, and the weight gives 1000÷9601000 \div 960, not 1.04.

Irfan buys two cycles for a total of ₹12,000. He sells one at a loss of 20% and the other at a gain of 20%, and both sell for the same price. What did the cycle sold at a loss cost him?

Options for question 28

Show the explanationHide the explanation

AnswerD · ₹7,200

  1. Let the loss-making cycle cost ₹x. The other costs ₹(12,000−x)(12{,}000 - x).

  2. Same SP: 0.8x=1.2(12,000−x)0.8x = 1.2(12{,}000 - x).

  3. 0.8x+1.2x=14,4000.8x + 1.2x = 14{,}400, so 2x=14,4002x = 14{,}400 and x=7,200x = 7{,}200.

Worth noting

Equal selling prices do not mean equal costs. The cycle sold at a loss must have cost more. ₹6,000 splits the money equally, and ₹5,760 is the common SP.

A grain dealer cheats at both ends. When buying, he takes 1,200 g for every kilogram he pays for. When selling, he gives only 800 g for every kilogram he charges for. He buys and sells at the same price per kilogram. What is his gain percentage?

Options for question 29

Show the explanationHide the explanation

AnswerC · 50%

  1. Say the rate is ₹1 per kg. For ₹1 he gets 1,200 g, so 1 g costs him ₹1/1200.

  2. For 800 g he collects ₹1, but 800 g cost him 800/1200800/1200 = ₹2/3.

  3. Gain % = 1−2323×100=50%\frac{1 - \frac{2}{3}}{\frac{2}{3}} \times 100 = 50\%.

Worth noting

Adding 20%+20%20\% + 20\% gives 40%, and 1.2×1.21.2 \times 1.2 gives 44%. The right factor is 1200÷800=1.51200 \div 800 = 1.5.

Sneha sells a microwave at a profit of 10%. Had she bought it for 10% less and sold it for ₹44 less, she would have made a profit of 20%. What is the cost price?

Options for question 30

Show the explanationHide the explanation

AnswerB · ₹2,200

  1. Let CP = ₹x. Actual SP = 1.1x.

  2. New CP = 0.9x and new SP = 1.2×0.9x=1.08x1.2 \times 0.9x = 1.08x.

  3. The SP falls by 1.1x−1.08x=0.02x1.1x - 1.08x = 0.02x = ₹44.

  4. x=44÷0.02x = 44 \div 0.02 = ₹2,200.

Worth noting

₹2,420 is the actual selling price. ₹4,400 treats ₹44 as 1% of the CP.

A shopkeeper buys 200 eggs at ₹6 each and pays ₹60 to bring them to his shop. On the way, 20 eggs break. At what price must he sell each remaining egg to make a 20% profit on his total outlay?

Options for question 31

Show the explanationHide the explanation

AnswerD · ₹8.40

  1. Total cost = 200 × ₹6 + ₹60 = ₹1,260.

  2. Required SP = 1.2 × ₹1,260 = ₹1,512.

  3. Eggs left to sell = 200−20=180200 - 20 = 180.

  4. Price per egg = ₹1,512 ÷ 180 = ₹8.40.

Worth noting

₹7.56 spreads the takings over all 200 eggs, but the broken ones cannot be sold. ₹8.00 forgets the ₹60 transport cost.

Marked price and discount

25 questions

A pair of running shoes is marked at ₹1,500. The shop gives a discount of 12%. How much does Aarav pay?

Options for question 32

Show the explanationHide the explanation

AnswerB · ₹1,320

  1. Discount = 12% of ₹1,500 = ₹180.

  2. Price paid = ₹1,500 − ₹180 = ₹1,320.

Worth noting

₹180 is the discount, not the price paid. Discount is always taken on the marked price.

A backpack marked at ₹1,250 is sold for ₹1,000. What rate of discount was given?

Options for question 33

Show the explanationHide the explanation

AnswerB · 20%

  1. Discount = ₹1,250 − ₹1,000 = ₹250.

  2. Discount % = 2501250×100=20%\frac{250}{1250} \times 100 = 20\%.

Worth noting

Discount % is on the marked price. Dividing ₹250 by the selling price gives 25%. 80% is the price paid as a share of the MP.

After a discount of 10%, a mixer-grinder sells for ₹3,420. What is its marked price?

Options for question 34

Show the explanationHide the explanation

AnswerD · ₹3,800

  1. SP = 90% of MP.

  2. MP = 3420×10090=38003420 \times \frac{100}{90} = 3800, that is ₹3,800.

Worth noting

Adding 10% of ₹3,420 gives ₹3,762. That is wrong because the discount was 10% of the larger MP.

A shopkeeper buys a wall clock for ₹800, marks it 25% above cost and then gives a 10% discount. What is the selling price?

Options for question 35

Show the explanationHide the explanation

AnswerB · ₹900

  1. MP = 800×1.25800 \times 1.25 = ₹1,000.

  2. SP = 90% of ₹1,000 = ₹900.

Worth noting

₹920 comes from doing 25%−10%=15%25\% - 10\% = 15\% on the CP. The 10% discount is on the MP of ₹1,000, not on the CP.

A shop runs a 'buy 3, get 1 free' offer on soap bars of the same price. What is the effective discount percentage on the goods received?

Options for question 36

Show the explanationHide the explanation

AnswerB · 25%

  1. The customer takes 4 bars but pays for 3.

  2. 1 bar out of 4 is free.

  3. Discount % = 14×100=25%\frac{1}{4} \times 100 = 25\%.

Worth noting

The free bar must be compared with ALL the bars received (4), not with the bars paid for (3). 13\frac{1}{3} gives the tempting 3313%33\frac{1}{3}\%.

On a sale day, Priyanka gets a discount of ₹540 on a dinner set. This is 18% of its marked price. How much does she pay?

Options for question 37

Show the explanationHide the explanation

AnswerA · ₹2,460

  1. MP = 54018×100=3000\frac{540}{18} \times 100 = 3000, that is ₹3,000.

  2. Price paid = ₹3,000 − ₹540 = ₹2,460.

Worth noting

₹3,000 is the marked price. The question asks for the amount paid after the discount.

A trader marks his goods 50% above cost price and gives a discount of 20% on the marked price. What is his profit percentage?

Options for question 38

Show the explanationHide the explanation

AnswerB · 20%

  1. Take CP = ₹100, so MP = ₹150.

  2. SP = 80% of ₹150 = ₹120.

  3. Profit = 20%.

Worth noting

Subtracting 50%−20%50\% - 20\% gives 30%, which is wrong. The 20% discount is on ₹150, not on ₹100.

A toy costs a shopkeeper ₹600 and he puts a price tag of ₹840 on it. By what percentage is the tag above the cost price?

Options for question 39

Show the explanationHide the explanation

AnswerC · 40%

  1. Markup = ₹840 − ₹600 = ₹240.

  2. Markup % = 240600×100=40%\frac{240}{600} \times 100 = 40\%.

Worth noting

Markup is measured on the cost price. 240840=2847%\frac{240}{840} = 28\frac{4}{7}\% uses the wrong base. 140% is the tag as a percentage of cost.

A store takes ₹15 off every ₹100 of the marked price. Sandeep pays ₹1,105 for a jacket. What was its marked price?

Options for question 40

Show the explanationHide the explanation

AnswerD · ₹1,300

  1. ₹15 off every ₹100 is a 15% discount, so SP = 85% of MP.

  2. MP = 1105×10085=13001105 \times \frac{100}{85} = 1300, that is ₹1,300.

Worth noting

Adding 15% of ₹1,105 gives ₹1,270.75. The discount is 15% of the MP, so divide by 0.85 instead.

A trader marks an article 40% above its cost price and then allows a discount of 25% on the marked price. What is the profit percentage?

Options for question 41

Show the explanationHide the explanation

AnswerA · 5%

  1. Take the cost price as 100.

  2. Marking it 40% above cost gives a marked price of 140.

  3. The discount is taken off the marked price: 140×0.75=105140 \times 0.75 = 105, so the selling price is 105.

  4. Profit is 105−100=5105 - 100 = 5 on a cost of 100, which is 5%.

Worth noting

Subtracting the two percentages to get 15% is wrong because the 40% is taken on the cost and the 25% on the larger marked price.

Normally a bookseller sells at the marked price and earns 30% profit. During a book fair he gives a 10% discount. What is his profit percentage at the fair?

Options for question 42

Show the explanationHide the explanation

AnswerA · 17%

  1. Take CP = ₹100, so MP = ₹130.

  2. Fair price = 90% of ₹130 = ₹117.

  3. Profit = 17%.

Worth noting

30%−10%=20%30\% - 10\% = 20\% is the trap. The discount is 10% of ₹130, which is ₹13, not ₹10.

A cycle costs a dealer ₹1,200. He wants a profit of 20% even after giving a discount of 10%. What price should he mark on it?

Options for question 43

Show the explanationHide the explanation

AnswerD · ₹1,600

  1. Required SP = 1.2 × ₹1,200 = ₹1,440.

  2. This SP is 90% of the MP.

  3. MP = 1440×10090=16001440 \times \frac{100}{90} = 1600, that is ₹1,600.

Worth noting

₹1,440 is the SP, not the MP. ₹1,584 adds 10% to ₹1,440 instead of dividing by 0.9.

A shopkeeper wants a profit of 20% after giving a discount of 25%. By what percentage above cost should he mark his goods?

Options for question 44

Show the explanationHide the explanation

AnswerD · 60%

  1. Take CP = ₹100, so required SP = ₹120.

  2. SP = 75% of MP, so MP = 120÷0.75120 \div 0.75 = ₹160.

  3. MP is 60% above CP.

Worth noting

Adding 20%+25%=45%20\% + 25\% = 45\% is the trap. The discount is taken on the MP, which is bigger than the CP.

By giving a discount of 20%, a shopkeeper makes a loss of 4%. What would his result be if he gave no discount?

Options for question 45

Show the explanationHide the explanation

AnswerA · Profit of 20%

  1. Take CP = ₹100, so SP after discount = ₹96.

  2. ₹96 is 80% of MP, so MP = 96÷0.896 \div 0.8 = ₹120.

  3. Selling at MP gives a profit of ₹20 on ₹100, that is 20%.

Worth noting

Doing −4%+20%=16%-4\% + 20\% = 16\% is the trap. The 20% is on the MP, so work back to the MP first.

The cost price and marked price of a kettle are in the ratio 5:75 : 7. The shop gives a discount of 10%. What is the profit percentage?

Options for question 46

Show the explanationHide the explanation

AnswerA · 26%

  1. Take CP = ₹500 and MP = ₹700.

  2. SP = 90% of ₹700 = ₹630.

  3. Profit % = 130500×100=26%\frac{130}{500} \times 100 = 26\%.

Worth noting

40% is the markup, and 40%−10%=30%40\% - 10\% = 30\% forgets that the discount is on the MP.

A bookshelf is sold for ₹4,420 after a 15% discount. The seller still makes a profit of 4%. What is the cost price of the bookshelf?

Options for question 47

Show the explanationHide the explanation

AnswerD · ₹4,250

  1. SP = ₹4,420 gives a 4% profit, so SP = 104% of CP.

  2. CP = 4420×100104=42504420 \times \frac{100}{104} = 4250, that is ₹4,250.

  3. (The MP, ₹5,200, is not needed to find the CP.)

Worth noting

₹4,243.20 takes 4% off the SP. The profit is 4% of the CP, so divide by 1.04. ₹3,757 wrongly takes the 15% discount off the SP.

A stationer gives one pen free with every 3 notebooks bought. A notebook is priced at ₹60 and a pen at ₹20. What is the effective discount percentage on the goods received?

Options for question 48

Show the explanationHide the explanation

AnswerA · 10%

  1. Goods received = 3 notebooks + 1 pen, worth 3 × ₹60 + ₹20 = ₹200.

  2. Amount paid = ₹180, so the discount is ₹20.

  3. Discount % = 20200×100=10%\frac{20}{200} \times 100 = 10\%.

Worth noting

The free item is cheaper than the items bought, so '1 in 4 free' (25%) does not apply. 1119%11\frac{1}{9}\% divides by the amount paid instead of the value received.

A shopkeeper marks a lamp at ₹1,500, which is 25% above its cost price. He sells it after a discount of ₹150. What is his profit percentage?

Options for question 49

Show the explanationHide the explanation

AnswerC · 12.5%

  1. CP = 1500×100125=12001500 \times \frac{100}{125} = 1200, that is ₹1,200.

  2. SP = ₹1,500 − ₹150 = ₹1,350.

  3. Profit % = 1501200×100=12.5%\frac{150}{1200} \times 100 = 12.5\%.

Worth noting

25% of ₹1,500 is ₹375, but CP is not ₹1,500 − ₹375 = ₹1,125. The 25% is on the CP, so divide by 1.25. 1119%11\frac{1}{9}\% divides the profit by the SP.

A shop raises its discount on a sofa from 12% to 20%. A customer now saves ₹144 more than before. What is the marked price of the sofa?

Options for question 50

Show the explanationHide the explanation

AnswerD · ₹1,800

  1. Extra discount = 20%−12%=8%20\% - 12\% = 8\% of MP.

  2. 8% of MP = ₹144.

  3. MP = 1448×100=1800\frac{144}{8} \times 100 = 1800, that is ₹1,800.

Worth noting

₹1,200 treats ₹144 as 12% of MP. ₹720 treats it as 20%. Only the 8-point increase matches the ₹144.

A television marked at ₹42,000 is sold at a 5% discount. The dealer still makes a profit of 14%. What is the cost price?

Options for question 51

Show the explanationHide the explanation

AnswerB · ₹35,000

  1. SP = 95% of ₹42,000 = ₹39,900.

  2. SP = 114% of CP.

  3. CP = 39900×100114=3500039900 \times \frac{100}{114} = 35000, that is ₹35,000.

Worth noting

₹34,314 takes 14% off the SP, and ₹36,120 takes 14% off the MP. Profit is 14% of the CP, so divide by 1.14.

A trader marks a fridge 35% above cost price and gives a 20% discount. His profit on the sale is ₹96. What is the cost price?

Options for question 52

Show the explanationHide the explanation

AnswerC · ₹1,200

  1. Take CP = ₹100: MP = ₹135, SP = 80% of ₹135 = ₹108.

  2. So the profit is 8% of CP.

  3. 8% of CP = ₹96, so CP = 968×100=1200\frac{96}{8} \times 100 = 1200, that is ₹1,200.

Worth noting

₹640 uses 35%−20%=15%35\% - 20\% = 15\% as the profit rate. The real profit rate is 8%. ₹1,296 is the SP.

A shop offers 'buy 5, get 2 free' on identical towels and still makes a profit of 25%. By what percentage above cost price are the towels marked?

Options for question 53

Show the explanationHide the explanation

AnswerB · 75%

  1. For 7 towels the customer pays the MP of 5.

  2. Effective SP of one towel = 57\frac{5}{7} of MP.

  3. 57MP=1.25 CP\frac{5}{7}\text{MP} = 1.25\,\text{CP}, so MP = 1.75 CP.

  4. The towels are marked 75% above cost.

Worth noting

The offer is a discount of 27\frac{2}{7}, about 28.6%, not 25=40%\frac{2}{5} = 40\%. 25%+40%=65%25\% + 40\% = 65\% is the trap.

A trader marks his goods 50% above cost. He wants the discount percentage and his profit percentage to be the same number. What must that number be?

Options for question 54

Show the explanationHide the explanation

AnswerA · 20%

  1. Take CP = ₹100, so MP = ₹150. Let the discount be x%.

  2. SP = 150(1−x/100)(1 - x/100), and it must also equal 100(1+x/100)(1 + x/100).

  3. 150−1.5x=100+x150 - 1.5x = 100 + x, so 2.5x=502.5x = 50 and x=20x = 20.

  4. Check: 20% off ₹150 gives ₹120, a profit of 20%.

Worth noting

25% (half of 50%) looks symmetric but fails: 25% off ₹150 is ₹112.50, a profit of only 12.5%.

A shoe store offers 'buy 3 pairs, get 1 pair free' on pairs of the same price. It also takes an extra 10% off the bill. What is the effective discount on the pairs received?

Options for question 55

Show the explanationHide the explanation

AnswerA · 32.5%

  1. The customer takes 4 pairs and is billed for 3: the fraction paid is 3/43/4.

  2. The extra 10% off leaves 90% of that bill.

  3. Fraction paid = 34×0.9=0.675\frac{3}{4} \times 0.9 = 0.675.

  4. Effective discount = 1−0.675=32.5%1 - 0.675 = 32.5\%.

Worth noting

Adding 25%+10%=35%25\% + 10\% = 35\% overstates it. The extra 10% is taken on the reduced bill, not on the full value. 67.5% is the part paid, not the discount.

After a 15% discount, a seller makes a profit of 19%. What would his profit percentage be if he sold at the marked price?

Options for question 56

Show the explanationHide the explanation

AnswerC · 40%

  1. Take CP = ₹100, so SP = ₹119.

  2. ₹119 is 85% of MP, so MP = 119÷0.85119 \div 0.85 = ₹140.

  3. At the MP the profit is ₹40 on ₹100, that is 40%.

Worth noting

19%+15%=34%19\% + 15\% = 34\% is the trap. 36.85% adds 15% of ₹119 instead of dividing by 0.85.

Successive discounts

16 questions

A shop gives two successive discounts of 20% and 15% on a mattress. What single discount is equivalent to these two?

Options for question 57

Show the explanationHide the explanation

AnswerC · 32%

  1. Price after both discounts = 0.8×0.85=0.680.8 \times 0.85 = 0.68 of MP.

  2. Single equivalent discount = 1−0.68=0.32=32%1 - 0.68 = 0.32 = 32\%.

Worth noting

Successive discounts are not added: 20%+15%=35%20\% + 15\% = 35\% is too much, because the 15% is taken on an already reduced price.

A smartwatch is marked at ₹5,000. Tenzin gets successive discounts of 10% and 5%. How much does he pay?

Options for question 58

Show the explanationHide the explanation

AnswerB · ₹4,275

  1. After 10% off: 90% of ₹5,000 = ₹4,500.

  2. After a further 5% off: 95% of ₹4,500 = ₹4,275.

Worth noting

₹4,250 adds the two discounts into one of 15%. The second discount is on ₹4,500, not on ₹5,000.

What single discount is equivalent to successive discounts of 25% and 20%?

Options for question 59

Show the explanationHide the explanation

AnswerC · 40%

  1. Price paid = 0.75×0.8=0.60.75 \times 0.8 = 0.6 of MP.

  2. Single discount = 1−0.6=40%1 - 0.6 = 40\%.

Worth noting

Shortcut: a+b−ab100=25+20−25×20100=40%a + b - \frac{ab}{100} = 25 + 20 - \frac{25 \times 20}{100} = 40\%.

A wholesaler gives three successive discounts of 10% each. What is the single equivalent discount?

Options for question 60

Show the explanationHide the explanation

AnswerB · 27.1%

  1. Price paid = 0.9×0.9×0.9=0.7290.9 \times 0.9 \times 0.9 = 0.729 of MP.

  2. Single discount = 1−0.729=0.271=27.1%1 - 0.729 = 0.271 = 27.1\%.

Worth noting

72.9% is the part PAID, not the discount. 30% wrongly adds the three rates.

A carrom board marked at ₹2,500 is sold after successive discounts of 30% and 20%. What is the selling price?

Options for question 61

Show the explanationHide the explanation

AnswerB · ₹1,400

  1. After 30% off: 70% of ₹2,500 = ₹1,750.

  2. After 20% off: 80% of ₹1,750 = ₹1,400.

Worth noting

₹1,250 treats the offer as a single 50% discount. ₹1,750 stops after the first discount.

Store P offers a flat 30% off a cooler marked at ₹4,000. Store Q offers 20% off followed by a further 15% off on the same marked price. Which store is cheaper, and by how much?

Options for question 62

Show the explanationHide the explanation

AnswerD · Store Q, by ₹80

  1. Store P: 70% of ₹4,000 = ₹2,800.

  2. Store Q: 0.8×0.850.8 \times 0.85 × ₹4,000 = ₹2,720.

  3. Store Q is cheaper by ₹2,800 − ₹2,720 = ₹80.

Worth noting

Store Q's two discounts work out to a single 32%, which beats a flat 30%. ₹200 treats Store Q's offer as 35%.

A saree marked at ₹1,500 is sold for ₹1,080 after two successive discounts. The first discount is 20%. What is the second?

Options for question 63

Show the explanationHide the explanation

AnswerB · 10%

  1. After the first discount: 80% of ₹1,500 = ₹1,200.

  2. The second discount takes ₹1,200 down to ₹1,080, a cut of ₹120.

  3. Second discount = 1201200×100=10%\frac{120}{1200} \times 100 = 10\%.

Worth noting

28% is the total discount on ₹1,500. 8% (28%−20%)(28\% - 20\%) forgets that the second discount is on ₹1,200.

After successive discounts of 10% and 5%, Nirmala pays ₹2,052 for a sewing kit. What was its marked price?

Options for question 64

Show the explanationHide the explanation

AnswerC · ₹2,400

  1. Fraction paid = 0.9×0.95=0.8550.9 \times 0.95 = 0.855.

  2. MP = 20520.855=2400\frac{2052}{0.855} = 2400, that is ₹2,400.

Worth noting

₹2,359.80 adds 15% to ₹2,052. Increasing the SP by the discount rates never recovers the MP, because the discounts were on the larger price.

A trader marks his goods 50% above cost price and then allows successive discounts of 10% and 20%. What is his profit percentage?

Options for question 65

Show the explanationHide the explanation

AnswerA · 8%

  1. Take CP = ₹100, so MP = ₹150.

  2. After 10% off: ₹135. After 20% off: ₹108.

  3. Profit = ₹8 on ₹100, that is 8%.

Worth noting

50%−10%−20%=20%50\% - 10\% - 20\% = 20\% is the trap. Each discount is taken on a price, and the second is on the reduced price.

On a ₹3,000 item, Shop X gives 10% off and then 20% off. Shop Y gives 20% off and then 10% off. Which is true?

Options for question 66

Show the explanationHide the explanation

AnswerA · Both shops charge ₹2,160

  1. Shop X: 3000×0.9×0.83000 \times 0.9 \times 0.8 = ₹2,160.

  2. Shop Y: 3000×0.8×0.93000 \times 0.8 \times 0.9 = ₹2,160.

  3. Multiplication does not depend on order, so the final price is the same.

Worth noting

₹2,100 would need a flat 30%. The two successive discounts equal 28%, whatever the order.

A furniture shop gives successive discounts of 20%, 10% and 5%. What single discount is equivalent to them?

Options for question 67

Show the explanationHide the explanation

AnswerA · 31.6%

  1. Fraction paid = 0.8×0.9×0.95=0.6840.8 \times 0.9 \times 0.95 = 0.684.

  2. Single discount = 1−0.684=0.316=31.6%1 - 0.684 = 0.316 = 31.6\%.

Worth noting

35% adds the three rates. 68.4% is the part paid, not the discount.

A seller wants to replace two successive discounts of 15% each with one discount that gives the same final price. What should that single discount be?

Options for question 68

Show the explanationHide the explanation

AnswerA · 27.75%

  1. Fraction paid = 0.85×0.85=0.72250.85 \times 0.85 = 0.7225.

  2. Single discount = 1−0.7225=0.2775=27.75%1 - 0.7225 = 0.2775 = 27.75\%.

Worth noting

Shortcut: 15+15−15×15100=27.75%15 + 15 - \frac{15 \times 15}{100} = 27.75\%. The single discount is always less than the sum, and 72.25% is the part paid, not the discount.

A festival sale advertises '25% off, plus an extra discount on the reduced price'. What must the extra discount be for the deal to equal a flat 35% off?

Options for question 69

Show the explanationHide the explanation

AnswerC · 1313%13\frac{1}{3}\%

  1. Flat 35% off means paying 0.65 of the MP.

  2. After 25% off, the price is 0.75 of the MP.

  3. Second fraction paid = 0.650.75=1315\frac{0.65}{0.75} = \frac{13}{15}.

  4. Extra discount = 1−1315=215=1313%1 - \frac{13}{15} = \frac{2}{15} = 13\frac{1}{3}\%.

Worth noting

10% (35%−25%)(35\% - 25\%) is too small, because it is taken on the reduced price. 25% then 10% gives only 32.5%.

A dealer buys a guitar for ₹1,000. He offers successive discounts of 20% and 10% on the marked price and still wants a profit of 8%. By what percentage above cost must he mark the guitar?

Options for question 70

Show the explanationHide the explanation

AnswerD · 50%

  1. Required SP = 1.08 × ₹1,000 = ₹1,080.

  2. Fraction paid after both discounts = 0.8×0.9=0.720.8 \times 0.9 = 0.72.

  3. MP = ₹1,080 ÷ 0.72 = ₹1,500.

  4. MP is ₹500 above cost, that is 50%.

Worth noting

38% (8%+20%+10%)(8\% + 20\% + 10\%) is the trap, and 30% forgets the profit altogether. The discounts are on the MP, so divide the target SP by 0.72.

After three successive discounts, a customer pays 61.2% of the marked price of a dining table. The first two discounts are 20% and 15%. What is the third discount?

Options for question 71

Show the explanationHide the explanation

AnswerC · 10%

  1. After the first two discounts she would pay 0.8×0.85=0.680.8 \times 0.85 = 0.68 of the MP.

  2. Third fraction paid = 0.6120.68=0.9\frac{0.612}{0.68} = 0.9.

  3. Third discount = 1−0.9=10%1 - 0.9 = 10\%.

Worth noting

3.8% comes from 38.8%−35%38.8\% - 35\%, which adds and subtracts the discounts instead of multiplying the fractions paid.

On an air fryer, one offer is a single 30% discount and another is successive discounts of 20% and 10%. The difference between the two selling prices is ₹72. What is the marked price?

Options for question 72

Show the explanationHide the explanation

AnswerC · ₹3,600

  1. Single 30%: pay 0.70 of MP.

  2. 20% then 10%: pay 0.8×0.9=0.720.8 \times 0.9 = 0.72 of MP.

  3. Difference = 0.02 of MP = ₹72.

  4. MP = 72÷0.0272 \div 0.02 = ₹3,600.

Worth noting

₹7,200 assumes a 1% gap. ₹720 treats ₹72 as 10% of the MP.

The area names are NTA's. The chapters inside them are EduFarming's own division, not NTA's.