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Area of Bounded Regions · Question 92 of 115

Question 92

EasyOriginal question

What is the area of the part of the ellipse x2a2+y2b2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 that lies in the first quadrant?

Options for question 92

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. ∫0abaa2−x2 dx=ba⋅πa24\int_0^{a} \frac{b}{a}\sqrt{a^{2} - x^{2}}\,dx = \frac{b}{a} \cdot \frac{\pi a^{2}}{4}.

  2. =πab4= \frac{\pi ab}{4}, a quarter of the whole ellipse.

Worth noting

πab2\frac{\pi ab}{2} is the half above the xx-axis.

Concept
Area of a region of an ellipse
Typical time
60 s
Your time
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The rule this testsEllipses
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Ten questions from Area of Bounded Regions, at your own pace.

Practise this chapter →

Ten questions from Area of Bounded Regions, at your own pace.