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Conditional Probability & Bayes' Theorem · Question 107 of 125

Question 107

MediumOriginal question

Three bags hold 5 balls each: bag I has 2 white, bag II has 3 white and bag III has 4 white, the rest being black. A bag is picked at random and a ball drawn from it is white. What is the probability that it came from bag III?

Options for question 107

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. P(W)=13(25+35+45)=35P(W) = \frac{1}{3}\left(\frac{2}{5} + \frac{3}{5} + \frac{4}{5}\right) = \frac{3}{5}.

  2. P(III∣W)=13×4535=49P(\text{III} \mid W) = \frac{\frac{1}{3} \times \frac{4}{5}}{\frac{3}{5}} = \frac{4}{9}.

Worth noting

13\frac{1}{3} is bag III's chance before the ball is seen; a white ball points towards the bag with the most white balls.

Concept
Bayes' theorem with three hypotheses
Typical time
90 s
Your time
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The rule this testsBayes' theorem
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Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.