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Definite Integrals & Area · Question 27 of 71

Question 27

MediumOriginal question

Evaluate ∫0πsin⁡x2−cos⁡x dx\int_0^{\pi} \frac{\sin x}{2 - \cos x}\,dx.

Options for question 27

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Put t=2−cos⁡xt = 2 - \cos x, dt=sin⁡x dxdt = \sin x\,dx; x=0→t=1x = 0 \to t = 1, x=π→t=3x = \pi \to t = 3.

  2. ∫13dtt=log⁡3\int_1^3 \frac{dt}{t} = \log 3.

Worth noting

−log⁡3-\log 3 takes dt=−sin⁡x dxdt = -\sin x\,dx; the derivative of −cos⁡x-\cos x is +sin⁡x+\sin x.

Concept
A derivative over its function, with limits
Typical time
90 s
Your time
—
The rule this testsSubstitution and by parts with limits
Practise this chapter →

Ten questions from Definite Integrals & Area, at your own pace.

Practise this chapter →

Ten questions from Definite Integrals & Area, at your own pace.