The figure shows the region bounded by y =…

The figure shows the region bounded by y = √(x), the x-axis and the lines x = 0 and x = 4.

Question 55

EasyOriginal question

The figure shows the region bounded by $y = \sqrt{x}$ , the $x$ -axis and the lines $x = 0$ and $x = 4$ . What is its area?

$The graph of y = \sqrt{x} with the region under it between x = 0 and x = 4 shaded, down to the x-axis.$

\frac{8}{3}

Correct answerYour answer

\frac{16}{3}

Correct answerYour answer

\frac{19}{3}

Correct answerYour answer

\frac{32}{3}

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer B

Correct answer: B

The curve stays above the $x$ -axis on $[0, 4]$ , so the area is $\int_{0}^{4} \sqrt{x}\,dx$ .
That is $\frac{16}{3}$ square units.

Ten questions from Definite Integrals & Area, at your own pace.

Ten questions from Definite Integrals & Area, at your own pace.