The figure shows the region bounded by y = sin x, the x-axis and the lines x = 0 and x = π. What is its area? The graph of y = \sin x with the region under it between x = 0 and x = \pi shaded, down to the x-axis.

The figure shows the region bounded by y = sin…

The figure shows the region bounded by y = sin x, the x-axis and the lines x = 0 and x = π.

EasyOriginal question

The figure shows the region bounded by $y = \sin x$ , the $x$ -axis and the lines $x = 0$ and $x = \pi$ . What is its area?

$The graph of y = \sin x with the region under it between x = 0 and x = \pi shaded, down to the x-axis.$

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CorrectNot quiteAnswer C

Correct answer: C

The curve stays above the $x$ -axis on $[0, \pi]$ , so the area is $\int_{0}^{\pi} \sin x\,dx$ .
That is $2$ square units.

Ten questions from Definite Integrals & Area, at your own pace.

Ten questions from Definite Integrals & Area, at your own pace.