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Derivatives & Second-Order Derivatives · Question 73 of 96

Question 73

MediumOriginal question

If y=exsin⁡xy = e^{x} \sin x, what is d2ydx2\frac{d^2y}{dx^2}?

Options for question 73

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. First derivative: dydx=2exsin⁡(x+π4)\frac{dy}{dx} = \sqrt{2} e^{x} \sin{\left(x + \frac{\pi}{4} \right)}.

  2. Differentiate again: d2ydx2=2excos⁡x\frac{d^2y}{dx^2} = 2 e^{x} \cos x.

Worth noting

2exsin⁡(x+π4)\sqrt{2} e^{x} \sin{\left(x + \frac{\pi}{4} \right)} stops at the first derivative; d2ydx2\frac{d^2y}{dx^2} differentiates it once more.

Concept
Second derivative of a product
Typical time
90 s
Your time
—
The rule this testsSecond-order derivatives
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Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.