EduFarming
Your list · 0हिं

Type at least two letters. Press Esc to close.

↑↓ navigate↵ openTAB cycle filter

Derivatives & Second-Order Derivatives · Question 74 of 96

Question 74

MediumOriginal question

If y=tan⁡xy = \tan x, what is d2ydx2\frac{d^2y}{dx^2}?

Options for question 74

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. dydx=sec⁡2x=(sec⁡x)2\frac{dy}{dx} = \sec^{2} x = (\sec x)^{2}.

  2. Chain rule: 2sec⁡x⋅sec⁡xtan⁡x=2sec⁡2xtan⁡x2\sec x \cdot \sec x\tan x = 2\sec^{2} x\tan x.

Worth noting

2sec⁡xtan⁡x2\sec x\tan x differentiates the square but forgets to multiply by sec⁡x\sec x once more, from ddxsec⁡x=sec⁡xtan⁡x\frac{d}{dx}\sec x = \sec x\tan x.

Concept
Second derivative with the chain rule
Typical time
90 s
Your time
—
The rule this testsSecond-order derivatives
Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.