If $y = 2^{x}$, what is $\frac{d^2y}{dx^2}$?

Explanation

1. 01

   $\frac{dy}{dx} = 2^{x}\log 2$, and $\log 2$ is a constant.

2. 02

   $\frac{d^2y}{dx^2} = \log 2 \cdot 2^{x}\log 2 = 2^{x}(\log 2)^{2}$.