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Determinants, Adjoint & Inverse · Question 49 of 87

Question 49

MediumOriginal question

For A=[1203−14205]A = \begin{bmatrix}1 & 2 & 0 \\ 3 & -1 & 4 \\ 2 & 0 & 5\end{bmatrix}, what is the element in row 1, column 2 of adj⁡A\operatorname{adj} A?

Options for question 49

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. adj⁡A\operatorname{adj} A is the transpose of the matrix of cofactors, so its (1,2)(1, 2) element is the cofactor A21A_{21}.

  2. A21=(−1)2+1∣2005∣=−10A_{21} = (-1)^{2 + 1}\begin{vmatrix} 2 & 0 \\ 0 & 5 \end{vmatrix} = -10.

Worth noting

−7-7 is the cofactor A12A_{12}: the transpose was forgotten.

Concept
An element of the adjoint
Typical time
90 s
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The rule this testsThe adjoint and the inverse
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