Read the two statements and choose the correct option.
I. $e^x$ is strictly increasing on $\mathbb{R}$ .
II. $e^{-x}$ is strictly increasing on $\mathbb{R}$ .

Only ICorrect answerYour answerOnly IICorrect answerYour answerBoth I and IICorrect answerYour answerNeither I nor IICorrect answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer A

Correct answer: A

$\frac{d}{dx}e^x = e^x > 0$ , so I is true.
$\frac{d}{dx}e^{-x} = -e^{-x} < 0$ , so $e^{-x}$ is strictly decreasing and II is false.

Ten questions from Increasing & Decreasing Functions, at your own pace.

Ten questions from Increasing & Decreasing Functions, at your own pace.

Read the two statements and choose the correct option.I. exe^xex is strictly increasing on R\mathbb{R}R.II. e−xe^{-x}e−x is strictly increasing on R\mathbb{R}R.