Evaluate $\int 2^{x}\,dx$ .

2^{x}\log 2 + C

Correct answerYour answer

\frac{2^{x + 1}}{x + 1} + C

Correct answerYour answer

\frac{2^{x}}{\log 2} + C

Correct answerYour answer

x \cdot 2^{x - 1} + C

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

$\frac{d}{dx}a^{x} = a^{x}\log a$ , so $\int a^{x}\,dx = \frac{a^{x}}{\log a} + C$ .
With $a = 2$ : $\frac{2^{x}}{\log 2} + C$ .

Worth noting

$2^{x}\log 2$ is the derivative of $2^{x}$ , not its integral.

Ten questions from Indefinite Integrals, at your own pace.

Ten questions from Indefinite Integrals, at your own pace.

Evaluate ∫2x dx\int 2^{x}\,dx∫2xdx.