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Indefinite Integrals · Question 32 of 90

Question 32

HardOriginal question

Evaluate ∫dxxlog⁡x\int \frac{dx}{x\log x}.

Options for question 32

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Put t=log⁡xt = \log x, so dt=dxxdt = \frac{dx}{x} and the integral becomes ∫dtt\int \frac{dt}{t}.

  2. =log⁡∣t∣+C=log⁡∣log⁡x∣+C= \log|t| + C = \log|\log x| + C.

Worth noting

(log⁡x)22\frac{(\log x)^{2}}{2} is ∫log⁡xx dx\int \frac{\log x}{x}\,dx: here log⁡x\log x is in the denominator.

Concept
Substituting log x
Typical time
120 s
Your time
—
The rule this testsIntegration by substitution
Practise this chapter →

Ten questions from Indefinite Integrals, at your own pace.

Practise this chapter →

Ten questions from Indefinite Integrals, at your own pace.