Evaluate ∫ 1/(x^2 + 16) dx.

Indefinite Integrals · Question 46 of 90

Question 46

EasyOriginal question

Evaluate $\int \frac{1}{x^{2} + 16}\,dx$ .

\tan^{-1}{\left(\frac{x}{4} \right)} + C

Correct answerYour answer

4 \tan^{-1}{\left(\frac{x}{4} \right)} + C

Correct answerYour answer

\frac{\tan^{-1}{\left(\frac{x}{4} \right)}}{4} + C

Correct answerYour answer

\log\left|x^{2} + 16\right| + C

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

Worth noting

Without the factor $\frac{1}{4}$ the derivative comes out 4 times too large.

Ten questions from Indefinite Integrals, at your own pace.

Ten questions from Indefinite Integrals, at your own pace.