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Inverse Trigonometric Functions · Question 109 of 120

Question 109

HardOriginal question

Read the two statements and choose the correct option.

I. cos⁡−1(−12)=π−cos⁡−112\cos^{-1}\left(-\frac{1}{2}\right) = \pi - \cos^{-1} \frac{1}{2}.

II. sin⁡−1(−12)=π−sin⁡−112\sin^{-1}\left(-\frac{1}{2}\right) = \pi - \sin^{-1} \frac{1}{2}.

Options for question 109

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. I: 2π3=π−π3\frac{2\pi}{3} = \pi - \frac{\pi}{3}. True.

  2. II: the left side is −π6-\frac{\pi}{6}, the right 5π6\frac{5\pi}{6}. False; for sin⁡−1\sin^{-1} a negative input just flips the sign.

Worth noting

The rule π−…\pi - \ldots belongs to the branch [0,π][0, \pi], not to [−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right].

Concept
Negative inputs on the two branches
Typical time
120 s
Your time
—
The rule this testsValues of expressions
Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.