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Inverse Trigonometric Functions · Question 99 of 120

What is sin θ for this θ = cos^-1(-3/5)?

Question 99

MediumOriginal question

Let θ=cos⁡−1(−35)\theta = \cos^{-1}\left(-\frac{3}{5}\right).

What is sin⁡θ\sin \theta for this θ=cos⁡−1(−35)\theta = \cos^{-1}\left(-\frac{3}{5}\right)?

Options for question 99

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. sin⁡2θ=1−925=1625\sin^{2} \theta = 1 - \frac{9}{25} = \frac{16}{25}.

  2. θ\theta is in (0,π)(0, \pi), where sine is positive: 45\frac{4}{5}.

Worth noting

−45-\frac{4}{5} copies the minus sign from the cosine; on [0,π][0, \pi] the sine is never negative.

Concept
A function of a principal value
Typical time
120 s
Your time
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The rule this testsValues of expressions
Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.