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Inverse Trigonometric Functions · Question 100 of 120

What is tan θ for this θ = cos^-1(-3/5)?

Question 100

MediumOriginal question

Let θ=cos⁡−1(−35)\theta = \cos^{-1}\left(-\frac{3}{5}\right).

What is tan⁡θ\tan \theta for this θ=cos⁡−1(−35)\theta = \cos^{-1}\left(-\frac{3}{5}\right)?

Options for question 100

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. tan⁡θ=sin⁡θcos⁡θ=4/5−3/5\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{4/5}{-3/5}.

  2. −43-\frac{4}{3}.

Worth noting

43\frac{4}{3} loses the sign: an obtuse angle has a negative tangent.

Concept
A function of a principal value
Typical time
120 s
Your time
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The rule this testsValues of expressions
Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.